Recent Files
Semester_1
EduInCS Exam
Paper-1_05-03-2026
Qn-10.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 06 Mar 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program to find the maximum element in each row of a 2D
array and print the result. */
#include <stdio.h>
void findMax(int row, int col, int[row][col]);
int main()
{
int row = 3, col = 3, i, j, val = 1;
int arr[row][col];
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
{
arr[i][j] = val++;
}
}
findMax(row, col, arr);
return 0;
}
void findMax(int row, int col, int arr[row][col])
{
int i, j;
int max;
for (i = 0; i < row; i++)
{
max = arr[i][0];
for (j = 0; j < col; j++)
{
if(max < arr[i][j]) {
max = arr[i][j];
}
}
printf("Max of row %d = %d\n", i, max);
}
}
Qn-8.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 06 Mar 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program to find the transpose of a given square matrix using 2D array.
The transpose of a matrix is obtained by swapping the rows and columns of the matrix */
#include <stdio.h>
void transpose(int row, int col, int[row][col]);
void print(int row, int col, int[row][col]);
int main()
{
int row = 3, col = 3, i, j, val = 1;
int arr[row][col];
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
{
arr[i][j] = val++;
}
}
printf("Before Transpose: \n");
print(row, col, arr);
transpose(row, col, arr);
return 0;
}
void transpose(int row, int col, int arr[row][col])
{
int i, j;
int res[col][row];
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
{
res[j][i] = arr[i][j];
}
}
printf("\nAfter Transpose: \n");
print(row, col, res);
}
void print(int row, int col, int arr[row][col])
{
int i, j;
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
{
printf("%d ", arr[i][j]);
}
printf("\n");
}
}
Qn-9.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 06 Mar 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program to find sum of all elements in a given 2D array. */
#include <stdio.h>
int findSum(int row, int col, int[row][col]);
int main()
{
int row = 3, col = 3, i, j, val = 1;
int arr[row][col];
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
{
arr[i][j] = val++;
}
}
printf("Sum: %d", findSum(row, col, arr));
return 0;
}
int findSum(int row, int col, int arr[row][col])
{
int i, j;
int sum = 0;
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
{
sum += arr[i][j];
}
}
return sum;
}
Paper-2_05-03-2026
Qn-11.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 06 Mar 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to explain, how an array of stucture can you defined and accessed. */
#include <stdio.h>
#include <string.h>
// 1. Defining the Structure
struct Student {
int rollNo;
char name[50];
float marks;
};
int main() {
int n, i;
printf("Enter the number of students: ");
scanf("%d", &n);
// 2. Defining an Array of Structures
// This creates 'n' blocks of memory, each large enough to hold a Student
struct Student s[n];
// 3. Accessing members to STORE data
for (i = 0; i < n; i++) {
printf("\nEnter details for Student %d:\n", i + 1);
printf("Roll No: ");
scanf("%d", &s[i].rollNo); // Using dot (.) operator with index [i]
printf("Name: ");
getchar(); // To clear the newline character from buffer
fgets(s[i].name, sizeof(s[i].name), stdin);
s[i].name[strcspn(s[i].name, "\n")] = '\0'; // Safe newline removal
printf("Marks: ");
scanf("%f", &s[i].marks);
}
// 4. Accessing members to DISPLAY data
printf("\n--- Student Records ---\n");
printf("ID\tName\t\tMarks\n");
for (i = 0; i < n; i++) {
// Accessing using s[i].member
printf("%d\t%-15s\t%.2f\n", s[i].rollNo, s[i].name, s[i].marks);
}
return 0;
}
Qn-3.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 06 Mar 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to search an element from an array using linear
search technique using malloc() and free() for memory allocation
and deallocation. */
#include <stdio.h>
#include <stdlib.h>
int inputArray(int[], int);
int linearSearch(int[], int, int);
int main()
{
int size, *arr = NULL;
printf("How many element do you want to enter: ");
scanf("%d", &size);
arr = (int *)malloc(size * sizeof(int));
if (arr == NULL)
{
printf("Memory allocation failed! Exiting...\n");
return 1;
}
int target = inputArray(arr, size);
int index = linearSearch(arr, size, target);
if (index != -1)
{
printf("\nElement %d is found at index %d.", target, index);
}
else
{
printf("\nElement %d is not found.", target);
}
free(arr);
return 0;
}
int inputArray(int arr[], int size)
{
int i, target;
for (i = 0; i < size; i++)
{
printf("Enter element for position %d: ", i);
scanf("%d", &arr[i]);
}
printf("\nEnter the target element: ");
scanf("%d", &target);
return target;
}
int linearSearch(int arr[], int size, int target)
{
for (int i = 0; i < size; i++)
{
if (arr[i] == target)
{
return i;
}
}
return -1;
}
Qn-4.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 06 Mar 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to check a string is palindrome or not using
user-defined function. */
#include <stdio.h>
#include <string.h>
#include <stdbool.h>
#include <ctype.h>
bool isPalindrome(char str[]);
int main() {
char str[100];
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] = '\0';
if (isPalindrome(str)) {
printf("\"%s\" is a palindrome.\n", str);
} else {
printf("\"%s\" is not a palindrome.\n", str);
}
return 0;
}
bool isPalindrome(char str[]) {
int left = 0;
int right = strlen(str) - 1;
while (right > left) {
if (tolower(str[left]) != tolower(str[right])) {
return false;
}
left++;
right--;
}
return true;
}
R
Code
R_Code-1.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 19 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# R allows you to assign values to variables in three different ways.
# Write three lines of code assigning the string "R is fun" to a variable
# using Simple Assignment, Leftward Assignment, and Rightward Assignment.
simple = "R is fun"
left <- "R is fun"
"R is fun" -> right
R_Code-10.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 20 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Create a numeric vector of student exam scores.
# Write a single line of code that evaluates these scores and
# outputs "Pass" for any score 50 or above, and "Fail" for any score below 50.
score <- c(45, 26, 89, 21, 75, 99, 13, 68, 85)
ifelse(score < 50, "Fail", "Pass")
R_Code-11.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 20 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Write a while loop that starts with a multiplier of 1.
# The loop should multiply the current multiplier by 4,
# assign it to a result variable, and print the result.
# The loop should exit if the result exceeds 100; otherwise,
# increment the multiplier by 1.
num = 1
while(TRUE) {
result <- num * 4
print(result)
if (result > 100) {
break
}
num = num + 1
}
R_Code-12.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 20 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Write a custom function named calculate_area that takes
# two parameters: length and width. The width parameter should have
# a default value of 5. The function should print the product of the
# two parameters. Finally, call your function passing only the value 12 for the length.
calculate_area <- function(length, width = 5) {
print(length * width)
}
calculate_area(12)
R_Code-13.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 20 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Create a list named student_record containing a string,
# an integer, and a numeric vector of two grades. Then, add the
# logical value TRUE to the end of the list, ensuring the original
# student_record variable is updated. Print the final list.
student_record <- list("Amit Dutta", 95, c(95, 96))
print(student_record)
student_record <- append(student_record, TRUE)
print(student_record)
R_Code-14.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 20 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Write an if...else if...else block that evaluates a newly created temperature variable.
# * If the temperature is strictly greater than 30, print: "30+ is too hot!"
# * If the temperature is between 20 and 30 (inclusive), print: "Perfect weather."
# * Otherwise, print: "It is quite cold."
temperature <- 29
if(temperature > 30) {
print("30+ is too hot!")
} else if(temperature >= 20 && temperature <= 30) {
print("Perfect weather")
} else {
print("It is quite cold.")
}
R_Code-15.r
# Asking for a name
name <- readline(prompt = "Enter your name: ")
# Asking for a number (requires conversion)
age <- readline(prompt = "Enter your age: ")
age <- as.numeric(age)
print(paste("Hello", name, "you are", age, "years old."))
R_Code-2.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 19 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# How do you declare an explicitly integer variable (e.g., the number 14)
# so that its class returns "integer" instead of the default floating-point "numeric"?
num <- 12L
print(class(num))
R_Code-3.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 19 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Assume you have a variable company <- "Programiz".
# Write a line of code using the paste0() function to print "Welcome toProgramiz"
# ensuring there is no default space between the string and the variable.
company <- "Programiz"
print(paste0("welcome to", company))
R_Code-4.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 19 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Write a standard if...else block that checks if a variable named
# age is greater than 18. If the condition is true, print "You are eligible to vote.",
# otherwise print "You cannot vote.".
age <- -1
if (age < 0) {
print("Not a valid age.")
} else if (age < 18) {
print("Not eligible to vote.")
} else {
print("Eligible to vote.")
}
R_Code-5.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 19 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# You have a vector of numbers: x <- c(12, 9, 23, 14).
# Use R's shorthand ifelse() function to output "EVEN" if a number
# in the vector is divisible by 2 (x %% 2 == 0), and "ODD" if it is not.
x <- c(12, 9, 23, 14)
ifelse(x %% 2 == 0, "EVEN", "ODD")
R_Code-6.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 19 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Write a while loop with a number variable starting at 1.
# The loop should print the number and increment it by 1,
# but you must include an if statement with a break command to
# stop the loop's execution exactly when number == 6
number <- 1
while (TRUE) {
if(number == 6) {
break
}
print(number)
number = number + 1
}
R_Code-7.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 19 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Create a numerical vector containing the sequence of
# numbers from 1 to 5 using the : operator. Then, use the rep()
# function with the times argument to repeat that entire sequence exactly 2 times.
s <- rep(c(1:5), times= 2)
print(s)
R_Code-8.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 19 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Create a list named list1 containing the number 24,
# the string "Sabby", the float 5.4, and the string "Nepal".
# Then, write the code using the append() function to add the number 3.14 to the very end of this list.
list1 <- list(24L, "Sabby", 5.4, "Nepal")
print("Before update")
print(list1)
print("After Update")
list1 <- append(list1, 3.14)
print(list1)
R_Code-9.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 19 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Define a function called power that takes two parameters,
# a and b. Give a a default value of 2. The function should print the result
# of a raised to the power of b (a^b).
power <- function (a = 2, b) {
return (a^b)
}
a <- 2
b <- 3
print(power(a, b))
print(power("b" = b))
R_Prac-1.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 25 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Write a R program to print numbers from 1 to 5.
i = 1
while(i <= 5) {
print(i)
i = i + 1
}
# or we can use
print(1:5)
R_Prac-2.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 25 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Check whether a number is even or odd.
num <- readline(prompt="Enter the number: ")
num <- as.integer(num)
print(paste(num, "is", ifelse(num %% 2 == 0, "EVEN", "ODD"), "number."))
R_Prac-3.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 25 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Print elements of vector using for loop.
sample <- c(1:6)
for(elem in sample) {
print(elem)
}
R_Prac-4.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 25 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Program to add two numbers in R program.
num1 <- as.double(readline(prompt="Enter 1st number: "))
num2 <- as.double(readline(prompt="Enter 2nd number: "))
if(is.na(num1) || is.na(num2)) {
stop("You did not enter a valid number.")
}
print(paste("Result", num1 + num2))
R_Prac-5.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 25 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Program to count the number of even numbers stored inside a vector of numbers.
print("Enter your numbers: ")
nums <- as.integer(scan())
count = 0
for(i in nums) {
if(i %% 2 == 0) {
count = count + 1
}
}
print(paste("Even Count=", count))
R_Prac-6.r
# Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 25 Mar 2026
# Repo: https://github.com/notamitgamer/bsc
# License: MIT
# Program to access List elements, modify a List Element, add items to List,
# Remove items from a List, length of List.
l <- list("Amit", 19, "Madhyamgram", 94.5)
print("Initial list:")
print(l)
l[[4]] = 95.46
print("after modifing last element: ")
print(l)
l[length(l) + 1] <- "hello"
print("after adding new element:")
print(l)
l[3] <- NULL
print("after deleting a element: ")
print(l)
print(paste("length of the list after modifing:", length(l)))
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910 0 R 910 0 R 910 0 R 910 0 R 910 0 R 910 0 R 910 0 R 910 0 R 911 0 R 912 0 R
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17 914 0 R 18 914 0 R 19 [390 0 R 390 0 R 390 0 R 390 0 R 390 0 R 390 0 R 390 0 R 390 0 R 391 0 R 391 0 R
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940 0 R 940 0 R 940 0 R 940 0 R 940 0 R 940 0 R 940 0 R 940 0 R 940 0 R 940 0 R
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484 0 R 484 0 R 484 0 R 484 0 R 484 0 R 484 0 R 484 0 R 484 0 R 485 0 R 485 0 R
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495 0 R 495 0 R 495 0 R 495 0 R 495 0 R 495 0 R 496 0 R 496 0 R 497 0 R 497 0 R
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499 0 R 499 0 R 499 0 R 499 0 R 499 0 R 499 0 R 499 0 R 499 0 R 499 0 R 500 0 R
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506 0 R 506 0 R 506 0 R 506 0 R 506 0 R 506 0 R 506 0 R 506 0 R 506 0 R 506 0 R
506 0 R 506 0 R 506 0 R 507 0 R 507 0 R 507 0 R 507 0 R 507 0 R 507 0 R 507 0 R
508 0 R 508 0 R 508 0 R 508 0 R 508 0 R 508 0 R 508 0 R 508 0 R 508 0 R 508 0 R
508 0 R 509 0 R 509 0 R 509 0 R 509 0 R 509 0 R 509 0 R 509 0 R 509 0 R 510 0 R
510 0 R 510 0 R 510 0 R 510 0 R 510 0 R 510 0 R 511 0 R 511 0 R 511 0 R 511 0 R
511 0 R 511 0 R 511 0 R 511 0 R 512 0 R 512 0 R 512 0 R 513 0 R 513 0 R 513 0 R
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513 0 R 513 0 R 513 0 R 513 0 R 513 0 R 513 0 R 513 0 R 513 0 R 513 0 R 513 0 R
513 0 R 513 0 R 513 0 R 513 0 R 513 0 R 514 0 R 514 0 R 514 0 R 514 0 R 514 0 R
514 0 R 514 0 R 514 0 R 514 0 R 514 0 R 514 0 R 514 0 R 514 0 R 514 0 R 514 0 R
514 0 R 515 0 R 515 0 R 515 0 R 515 0 R 515 0 R 515 0 R 515 0 R 515 0 R 516 0 R
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24 [950 0 R 951 0 R 952 0 R 520 0 R 520 0 R 520 0 R 521 0 R 521 0 R 521 0 R 521 0 R
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525 0 R 525 0 R 525 0 R 525 0 R 525 0 R 525 0 R 525 0 R 525 0 R 525 0 R 525 0 R
525 0 R 525 0 R 525 0 R 525 0 R 525 0 R 525 0 R 525 0 R 525 0 R 525 0 R 953 0 R
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528 0 R 528 0 R 528 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R
529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R
529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 529 0 R 530 0 R
530 0 R 531 0 R 531 0 R 531 0 R 531 0 R 531 0 R 531 0 R 531 0 R 531 0 R 531 0 R
531 0 R 531 0 R 531 0 R 531 0 R 531 0 R 531 0 R 532 0 R 532 0 R 532 0 R 532 0 R
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534 0 R 534 0 R 534 0 R 534 0 R 534 0 R 534 0 R 534 0 R 534 0 R 534 0 R 534 0 R
534 0 R 534 0 R 534 0 R 535 0 R 535 0 R 535 0 R 535 0 R 535 0 R 535 0 R 535 0 R
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540 0 R 540 0 R 540 0 R 540 0 R 540 0 R 540 0 R 540 0 R 540 0 R 540 0 R 540 0 R
541 0 R 541 0 R 541 0 R 541 0 R 541 0 R 541 0 R 541 0 R 541 0 R 541 0 R 541 0 R
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541 0 R 541 0 R 541 0 R 541 0 R 541 0 R 541 0 R 541 0 R 541 0 R 541 0 R 542 0 R
542 0 R 543 0 R 543 0 R 543 0 R 543 0 R 543 0 R 543 0 R 543 0 R 543 0 R 543 0 R
543 0 R 543 0 R 543 0 R 543 0 R 543 0 R 544 0 R 544 0 R 544 0 R 544 0 R 544 0 R
544 0 R 544 0 R 544 0 R 544 0 R 544 0 R 544 0 R 544 0 R 545 0 R 545 0 R 545 0 R
546 0 R 546 0 R 546 0 R 546 0 R 546 0 R 546 0 R 546 0 R 546 0 R 546 0 R 546 0 R
546 0 R 546 0 R 546 0 R 546 0 R 546 0 R 546 0 R 546 0 R 546 0 R 546 0 R 547 0 R
547 0 R 547 0 R 547 0 R 547 0 R 547 0 R 547 0 R 547 0 R 547 0 R 959 0 R 960 0 R
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26 963 0 R 27 [964 0 R 965 0 R 966 0 R 967 0 R 967 0 R 967 0 R 967 0 R 967 0 R 968 0 R 969 0 R
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564 0 R 564 0 R 565 0 R 565 0 R 565 0 R 565 0 R 565 0 R 565 0 R 565 0 R 566 0 R
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277766
%%EOF
assignment-primary
assignment-p-01.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that includes a user-defined function named isPrime with the signature
int isPrime(int num); The function should take an integer as a parameter and return 1 if
the number is prime and 0 otherwise. */
#include <stdio.h>
#include <math.h>
int isPrime(int);
int main()
{
int n;
printf("Enter the number: ");
scanf("%d", &n);
if (isPrime(n))
{
printf("\nInput %d is a Prime Number.", n);
}
else
{
printf("\nInput %d is not a Prime Number.", n);
}
return 0;
}
int isPrime(int n)
{
if (n <= 1)
return 0;
if (n == 2)
return 1;
if (n % 2 == 0)
return 0;
int temp = (int)sqrt(n);
int i;
for (i = 3; i <= temp; i += 2)
{
if (n % i == 0)
{
return 0;
}
}
return 1;
}
assignment-p-02.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that includes a user-defined function named isArmstrong with the
signature int isArmstrong(int num);. An Armstrong number is a number that is equal to
the sum of its own digits each raised to the power of the number of digits. For example,
153 is an Armstrong number because 1^3 + 5^3 + 3^3 = 153 */
#include <stdio.h>
#include <math.h>
int isArmstrong(int);
int count(int);
int main()
{
int n;
printf("Enter the number: ");
scanf("%d", &n);
if (isArmstrong(n))
{
printf("\nInput %d is a Armstrong Number.", n);
}
else
{
printf("\nInput %d is Not a Armstrong Number.", n);
}
return 0;
}
int count(int n)
{
int count = 0;
while (n > 0)
{
count++;
n = n / 10;
}
return count;
}
int isArmstrong(int n)
{
if (n < 0)
return 0;
if (n == 0)
return 1;
int power = count(n);
int temp = n;
int checker = 0;
while (temp > 0)
{
int digit = temp % 10;
checker = checker + (int)round(pow(digit, power));
temp = temp / 10;
}
return n == checker;
}
assignment-p-03.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a C program that includes a user-defined function named isPerfect with the signature
int isPerfect(int num);. A perfect number is a positive integer that is equal to the sum of
its proper divisors, excluding itself. For example, 28 is a perfect number because the sum
of its divisors (1, 2, 4, 7, 14) equals 28. */
#include <stdio.h>
int isPerfect(int);
int main()
{
int n;
printf("Enter the number: ");
scanf("%d", &n);
if (isPerfect(n))
{
printf("\nInput %d is a Perfect Number.", n);
}
else
{
printf("\nInput %d is not a Perfect Number.", n);
}
return 0;
}
int isPerfect(int n)
{
if (n <= 1)
return 0;
int temp = 1;
int i;
for (i = 2; i <= n / 2; i++)
{
if (n % i == 0)
{
temp += i;
}
}
return temp == n;
}
assignment-p-04.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that takes an integer input representing a month (1 to 12) and a year.
Use a switch statement to display the number of days in that month, considering leap years. */
#include <stdio.h>
int main()
{
int month, year, days;
printf("Enter the month (1 to 12) and year: ");
scanf("%d %d", &month, &year);
switch (month)
{
case 1: // jan
case 3: // mar
case 5: // may
case 7: // july
case 8: // aug
case 10: // oct
case 12: // dec
days = 31;
break;
case 4: // apr
case 6: // jun
case 9: // sep
case 11: // nov
days = 30;
break;
case 2: // feb
if ((year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0)))
{
days = 29;
}
else
{
days = 28;
}
break;
default:
printf("\nYou entered something wrong.");
return 0;
}
printf("\nNumber of days: %d", days);
return 0;
}
assignment-p-05.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that defines an array of integers, and includes a user-defined function
named reverseArray with the signature void reverseArray(int arr[], int size);. The function
should reverse the elements of the array. */
#include <stdio.h>
void inputArray(int[], int);
void reverseArray(int[], int);
int main()
{
int size;
printf("How many element do you want to add: ");
scanf("%d", &size);
int arr[size];
inputArray(arr, size);
reverseArray(arr, size);
return 0;
}
void inputArray(int arr[], int size)
{
int i;
for (i = 0; i < size; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
void reverseArray(int arr[], int size)
{
int i, j, temp;
printf("\nBefore Reverse: \n");
for (i = 0; i < size; i++)
{
printf("Position: %d, Value: %d\n", i, arr[i]);
}
for (i = 0, j = size - 1; i < j; i++, j--)
{
temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
printf("\nAfter Reverse: \n");
for (i = 0; i < size; i++)
{
printf("Position: %d, Value: %d\n", i, arr[i]);
}
}
assignment-p-06.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that includes a user-defined function named findLargest with the
signature int findLargest(int arr[], int size);. The function should take an array of integers
and its size, and return the largest element in the array. */
#include <stdio.h>
void inputArray(int[], int);
int findLargest(int[], int);
int main()
{
int size;
printf("How many element do you want to enter: ");
scanf("%d", &size);
int arr[size];
inputArray(arr, size);
printf("\nLargest Element is: %d", findLargest(arr, size));
return 0;
}
void inputArray(int arr[], int size)
{
int i;
for (i = 0; i < size; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
int findLargest(int arr[], int size)
{
int largest = arr[0], i;
for (i = 1; i < size; i++)
{
if (largest < arr[i])
{
largest = arr[i];
}
}
return largest;
}
assignment-p-07.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that includes a user-defined function named binarySearch with the
signature int binarySearch(int arr[], int size, int target);. The function should perform a
binary search on a sorted array of integers and return the index of the target element if
found, and -1 otherwise. */
#include <stdio.h>
int inputArray(int[], int);
// void sortArray(int[], int);
int binarySearch(int[], int, int);
int main()
{
int size;
printf("How many element do you want to enter: ");
scanf("%d", &size);
int arr[size];
int target = inputArray(arr, size);
// sortArray(arr, size);
int index = binarySearch(arr, size, target);
if (index != -1)
{
printf("\nElement %d is found at index %d.", target, index);
}
else
{
printf("\nElement %d is not found.", target);
}
return 0;
}
int inputArray(int arr[], int size)
{
int i, target;
for (i = 0; i < size; i++)
{
printf("Enter element for position %d: ", i);
scanf("%d", &arr[i]);
}
printf("\nEnter the target element: ");
scanf("%d", &target);
return target;
}
/* void sortArray(int arr[], int size)
{
// using Bubble Sort...
int tempArr[size], i, j, temp;
printf("\nBefore Sorting:\n[");
for (i = 0; i < size; i++)
{
printf("%d", arr[i]);
if (i != size - 1)
{
printf(", ");
}
}
printf("]\n");
for (i = 0; i < size - 1; i++)
{
for (j = 0; j < size - i - 1; j++)
{
if (arr[j] > arr[j + 1])
{
temp = arr[j];
arr[j] = arr[j + 1];
arr[j + 1] = temp;
}
}
}
printf("\nAfter Sorting:\n[");
for (i = 0; i < size; i++)
{
printf("%d", arr[i]);
if (i != size - 1)
{
printf(", ");
}
}
printf("]\n");
}
*/
int binarySearch(int arr[], int size, int target)
{
int low = 0;
int high = size - 1;
int mid;
while (low <= high)
{
mid = low + ((high - low) / 2);
if (arr[mid] == target)
{
return mid;
}
else if (arr[mid] > target)
{
high = mid - 1;
}
else if (arr[mid] < target)
{
low = mid + 1;
}
}
return -1;
}
assignment-p-08.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a C program that includes a user-defined function named countSetBits with the
signature int countSetBits(int num);. The function should count and return the number of
set bits (1s) in the binary representation of the given number. */
#include <stdio.h>
int countSetBits(int);
int main()
{
int num, result;
printf("Enter the number: ");
scanf("%d", &num);
if (result = countSetBits(num))
{
printf("\nNumber of set bits in %d: %d", num, result);
}
else
{
printf("\nThere is no set bits in %d", num);
}
return 0;
}
int countSetBits(int num)
{
int count = 0;
int mask= 1;
int i = 1;
while (i <= 16)
{
if (num & mask)
{
count++;
}
mask <<= 1;
i++;
}
return count;
}
assignment-p-09.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a C program that includes a user-defined function named setBit with the signature
int setBit(int num, int position);. The function should set the bit at the specified position
(0-indexed) to 1 and return the modified number. */
#include <stdio.h>
int setBit(int, int);
int main()
{
int num, position;
printf("Enter the number: ");
scanf("%d", &num);
printf("Enter the postion where you want to set the bit (0-indexed): ");
scanf("%d", &position);
printf("\nModified number= %d", setBit(num, position));
return 0;
}
int setBit(int num, int position)
{
int mask = 1 << position;
return num | mask;
}
assignment-p-10.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a C program that defines a structure Rectangle with attributes length and width.
Include a user-defined function named calculateArea with the signature float
calculateArea(struct Rectangle r);. The function should calculate and return the area of
the rectangle. */
#include <stdio.h>
struct Rectangle
{
float length;
float width;
};
float calculateArea(struct Rectangle);
int main()
{
struct Rectangle rec;
printf("Enter the length of the Rectangle: ");
scanf("%f", &rec.length);
printf("Enter the width of the Rectangle: ");
scanf("%f", &rec.width);
printf("\nArea of the Rectangle = %g", calculateArea(rec));
}
float calculateArea(struct Rectangle r)
{
return r.length * r.width;
}
assignment-p-11.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that defines a structure Student containing the attributes rollNumber,
name, and marks. Include a user-defined function named displayStudent with the
signature void displayStudent(struct Student s);. The function should display the details
of a student. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct Student
{
int rollNumber;
char name[50];
float marks;
};
void inputStudent(struct Student *);
void displayStudent(struct Student);
int main()
{
struct Student *std = NULL;
int i, n;
printf("How many student details you want to add : ");
if (scanf("%d", &n) != 1 || n < 1)
{
printf("\nInvalid Input.");
return 1;
}
std = (struct Student *)malloc(n * sizeof(struct Student));
if (std == NULL)
{
printf("\nUnable to allocate memory.");
return 1;
}
for (i = 0; i < n; i++)
{
printf("\n- Enter details of Student %d -", i + 1);
inputStudent(&std[i]);
}
printf("\n=== Student Details ===\n");
for (i = 0; i < n; i++)
{
displayStudent(std[i]);
}
free(std);
return 0;
}
void inputStudent(struct Student *std)
{
int len;
printf("\nEnter the Roll Number: ");
scanf("%d", &std->rollNumber);
getchar();
printf("Enter the Name (Max: 50 character): ");
fgets(std->name, sizeof(std->name), stdin);
len = strlen(std->name);
if (len > 0 && std->name[len - 1] == '\n')
{
std->name[len - 1] = '\0';
}
printf("Enter the Marks: ");
scanf("%f", &std->marks);
}
void displayStudent(struct Student std)
{
printf("\n%-12s : %d", "Roll Number", std.rollNumber);
printf("\n%-12s : %s", "Name", std.name);
printf("\n%-12s : %g\n", "Marks", std.marks);
}
assignment-p-12_v1.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that takes multiple integers as command-line arguments and finds the
maximum and minimum value among them. */
#include <stdio.h>
#include <stdlib.h>
// use atoi()
int main(int argc, char *argv[])
{
int current_val, max_val, min_val, i;
char *endptr;
long first_arg_val;
if (argc < 2)
{
printf("Usage: %s <integer1> <integer2> ...\n", argv[0]);
return 1;
}
first_arg_val = strtol(argv[1], &endptr, 10);
if (*endptr != '\0' || argv[1] == endptr)
{
printf("Error: Argument '%s' is not a valid integer.\n", argv[1]);
return 1;
}
max_val = (int)first_arg_val;
min_val = (int)first_arg_val;
for (i = 2; i < argc; i++)
{
long val = strtol(argv[i], &endptr, 10);
if (*endptr != '\0' || argv[i] == endptr)
{
printf("Error: Argument '%s' is not a valid integer.\n", argv[i]);
return 1;
}
current_val = (int)val;
if (current_val > max_val)
{
max_val = current_val;
}
if (current_val < min_val)
{
min_val = current_val;
}
}
printf("The maximum value is: %d\n", max_val);
printf("The minimum value is: %d\n", min_val);
return 0;
}
assignment-p-12_v2.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 06 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that takes multiple integers as command-line arguments and finds the
maximum and minimum value among them. */
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
int current_val, max_val, min_val, i;
if (argc < 2)
{
printf("Usage: %s <integer1> <integer2> ...\n", argv[0]);
return 1;
}
max_val = atoi(argv[1]);
min_val = atoi(argv[1]);
for (i = 2; i < argc; i++)
{
current_val = atoi(argv[i]);
if (current_val > max_val)
{
max_val = current_val;
}
if (current_val < min_val)
{
min_val = current_val;
}
}
printf("The maximum value is: %d\n", max_val);
printf("The minimum value is: %d\n", min_val);
return 0;
}
assignment-p-13.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that accepts a string as a command line argument and includes a user-
defined function named isPalindrome with the signature int isPalindrome(char str[]);.
The function should check if the given string is a palindrome and return 1 if it is, and 0
otherwise. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int isPalindrome(char[]);
int main(int argc, char *argv[])
{
if (argc != 2)
{
printf("\nUsage: %s <string>\n", argv[0]);
return 1;
}
if (isPalindrome(argv[1]))
{
printf("\nThe entered string \"%s\" is Palindrome.\n", argv[1]);
}
else
{
printf("\nThe entered string \"%s\" is not Palindrome.\n", argv[1]);
}
return 0;
}
int isPalindrome(char str[])
{
char *start = str;
char *end;
int len = strlen(str);
if (len == 0)
{
return 1;
}
end = str + (len - 1);
while (start < end)
{
if (*start != *end)
{
return 0;
}
start++;
end--;
}
return 1;
}
assignment-p-14_v1.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that opens its own source code file, reads its contents, and then prints
the contents to the console. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
FILE *code;
int character, len_upto_dot;
char *FILENAME;
char *dot;
FILENAME = strdup(argv[0]);
if (FILENAME == NULL)
{
printf("\nMemory allocation failed.\n");
return 1;
}
dot = strrchr(FILENAME, '.');
if (dot != NULL)
{
len_upto_dot = dot - FILENAME;
FILENAME[len_upto_dot] = '\0';
}
strcat(FILENAME, ".c");
code = fopen(FILENAME, "r");
if (code == NULL)
{
printf("\nCould not open the source file: %s", FILENAME);
printf("\nPlease ensure the source file is in the same directory as the executable.\n");
free(FILENAME);
return 1;
}
printf("\nReading file: %s", FILENAME);
printf("\n========== %s ==========\n\n", FILENAME);
while ((character = fgetc(code)) != EOF)
{
putchar(character);
}
printf("\n\n========== End of %s ==========\n", FILENAME);
fclose(code);
free(FILENAME);
return 0;
}
assignment-p-14_v2.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that opens its own source code file, reads its contents, and then prints
the contents to the console. */
#include <stdio.h>
#define FILENAME "assignment-p-14_v2.c"
int main()
{
FILE *code = NULL;
char temp;
code = fopen(FILENAME, "r");
if (code == NULL)
{
printf("\nCould not open the source file: %s", FILENAME);
return 1;
}
printf("\nReading file: %s", FILENAME);
printf("\n========== %s ==========\n\n", FILENAME);
while ((temp = fgetc(code)) != EOF)
{
printf("%c", temp);
}
printf("\n\n========== End of %s ==========\n", FILENAME);
fclose(code);
return 0;
}
assignment-p-15.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that reads a sequence of integers from a file named 'input.txt'. This
program should segregate the odd numbers from the even numbers and store the odd
numbers in a new file named 'ODDFile.txt' while storing the even numbers in another file
named 'EVENFile.txt' */
#include <stdio.h>
#define FILENAME "input.txt"
#define ODDFILE "ODDFile.txt"
#define EVENFILE "EVENFile.txt"
int main()
{
FILE *input = NULL;
FILE *oddfile = NULL;
FILE *evenfile = NULL;
int num;
input = fopen(FILENAME, "r");
if (input == NULL)
{
printf("\nCould not open the file: %s", FILENAME);
return 1;
}
oddfile = fopen(ODDFILE, "w");
if (oddfile == NULL)
{
printf("\nCould not open the file: %s", ODDFILE);
return 1;
}
evenfile = fopen(EVENFILE, "w");
if (evenfile == NULL)
{
printf("\nCould not open the file: %s", EVENFILE);
return 1;
}
while (fscanf(input, "%d", &num) == 1)
{
if (num % 2 == 0)
{
fprintf(evenfile, "%d ", num);
}
else
{
fprintf(oddfile, "%d ", num);
}
}
printf("Successfully processed numbers from %s.\n", FILENAME);
printf("Odd numbers written to %s.\n", ODDFILE);
printf("Even numbers written to %s.\n", EVENFILE);
fclose(input);
fclose(oddfile);
fclose(evenfile);
return 0;
}
assignment-secondary
assignment-s-01.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to compute the sum and product of digits of an integer using user
defined functions. */
#include <stdio.h>
int sum_of_digits(int);
int product_of_digits(int);
int main()
{
int num;
printf("Enter the number: ");
scanf("%d", &num);
printf("\nSum of digits of %d = %d", num, sum_of_digits(num));
printf("\nProduct of digits of %d = %d", num, product_of_digits(num));
return 0;
}
int sum_of_digits(int num)
{
int sum = 0;
while (num > 0)
{
sum += num % 10;
num /= 10;
}
return sum;
}
int product_of_digits(int num)
{
int product = 1;
while (num > 0)
{
product *= num % 10;
num /= 10;
}
return product;
}
assignment-s-02.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to reverse a non-negative integer using a function. */
#include <stdio.h>
int reverse(int);
int main()
{
int num;
printf("Enter a non-negetive integer: ");
scanf("%d", &num);
if (num < 0)
{
printf("\nOnly non-negetive integers are allowed.");
return 1;
}
printf("\nReverse of the integer %d = %d", num, reverse(num));
return 0;
}
int reverse(int num)
{
int rev = 0;
while (num > 0)
{
rev = (rev * 10) + (num % 10);
num /= 10;
}
return rev;
}
assignment-s-03.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to compute the sum of the first n terms of the series using a function:
S=1−2+3−4+5−6+… */
#include <stdio.h>
int sum_of_series(int);
int main()
{
int n;
printf("Enter the n: ");
scanf("%d", &n);
printf("\nSum of the first %d terms of the series = %d", n, sum_of_series(n));
return 0;
}
int sum_of_series(int n)
{
int sum = 0;
int i;
for (i = 1; i <= n; i++)
{
if (i % 2 == 0)
{
sum -= i;
}
else
{
sum += i;
}
}
return sum;
}
assignment-s-04.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a function to check whether a number is prime or not. Use the same function to
generate all prime numbers less than 100. */
#include <stdio.h>
#include <math.h>
int isPrime(int);
int main()
{
int n, i;
printf("Enter the number: ");
scanf("%d", &n);
if (isPrime(n))
{
printf("\nInput %d is a Prime Number.", n);
}
else
{
printf("\nInput %d is not a Prime Number.", n);
}
printf("\nPrime Numbers less than 100:");
for (i = 1; i < 100; i++)
{
if (isPrime(i))
{
printf(" %d", i);
}
}
return 0;
}
int isPrime(int n)
{
if (n <= 1)
return 0;
if (n == 2)
return 1;
if (n % 2 == 0)
return 0;
int temp = (int)sqrt(n);
int i;
for (i = 3; i <= temp; i += 2)
{
if (n % i == 0)
{
return 0;
}
}
return 1;
}
assignment-s-05.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a function to check whether a given string is a palindrome. Use this function to
determine whether an entered string is Palindrome. */
#include <stdio.h>
#include <string.h>
int isPalindrome(char[]);
int main()
{
char input[100];
int len;
printf("Enter the string (Max: 100 Character): ");
fgets(input, sizeof(input), stdin);
len = strlen(input);
if (len > 0 && input[len - 1] == '\n')
{
input[len - 1] = '\0';
}
if (isPalindrome(input))
{
printf("\nInput string \"%s\" is Palindrome.", input);
}
else
{
printf("\nInput string \"%s\" is not Palindrome", input);
}
return 0;
}
int isPalindrome(char str[])
{
char *start = str;
char *end;
int len = strlen(str);
if (len == 0)
{
return 1;
}
end = str + (len - 1);
while (start < end)
{
if (*start != *end)
{
return 0;
}
start++;
end--;
}
return 1;
}
assignment-s-06.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program using a function to compute and display all factors of a given number. */
#include <stdio.h>
#include <stdlib.h>
void display_factors(int);
int main()
{
int num, i;
printf("Please enter the number to get the factors from it : ");
scanf("%d", &num);
display_factors(num);
return 0;
}
void display_factors(int num) {
int temp = abs(num);
int i;
if (temp == 0)
{
printf("\n0 has infinitely many factors (all integers).");
exit(1);
}
printf("\nThe factors of ' %d ' is :- ", num);
printf("\nPositive : ");
for (i = 1; i <= temp; i++)
if (temp % i == 0)
printf(" %d", i);
printf("\nNegative : ");
for (i = 1; i <= temp; i++)
if (temp % i == 0)
printf(" %d", -i);
}
assignment-s-07.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to swap two numbers using a macro (#define). */
// IMPOSSIBLE
/* It is impossible to swap two literal numbers defined using the
preprocessor directive #define. This is because #define performs simple
text substitution and does not create variables in memory that can be
manipulated or pointed to. */
// Using a Function-Like Macro
#include <stdio.h>
// Define the SWAP macro.
// The do-while(0) block is a common trick to ensure the macro behaves
// like a single statement, regardless of where it is used (e.g., inside an 'if' statement).
#define SWAP(a, b, data_type) \
do { \
data_type temp = a; \
a = b; \
b = temp; \
} while(0)
int main() {
int num1 = 15;
int num2 = 42;
printf("--- Before Swap ---\n");
printf("Number 1 (num1): %d\n", num1);
printf("Number 2 (num2): %d\n", num2);
// Call the macro, passing the variables and their type
// The preprocessor replaces this line with the block of code defined above.
SWAP(num1, num2, int);
printf("\n--- After Swap (using macro) ---\n");
printf("Number 1 (num1): %d\n", num1);
printf("Number 2 (num2): %d\n", num2);
return 0;
}
assignment-s-08.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program that counts the number of occurrences of each alphabet (A-Z, a-z) in
the text entered using Command-Line Arguments. */
#include <stdio.h>
#include <string.h>
int main(int argc, char *argv[])
{
int target[2], i, j, count[2], len;
for (target[0] = 'A', target[1] = 'a'; target[0] <= 'Z', target[1] <= 'z'; target[0]++, target[1]++)
{
count[0] = 0;
count[1] = 0;
for (i = 1; i < argc; i++)
{
len = strlen(argv[i]);
for (j = 0; j < len; j++)
{
if (argv[i][j] == target[0])
{
count[0]++;
}
if (argv[i][j] == target[1])
{
count[1]++;
}
}
}
if (count[0])
{
printf("\n\"%c\" found %d times.", target[0], count[0]);
}
if (count[1])
{
printf("\n\"%c\" found %d times.", target[1], count[1]);
}
}
return 0;
}
assignment-s-09.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 17 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to swap two numbers using pointers (user-defined function). */
#include <stdio.h>
void swap(int *, int *);
int main()
{
int a, b;
printf("Enter value for a and b: ");
scanf("%d %d", &a, &b);
printf("\nBefore Swap: ");
printf("\na = %d,\tAddress: %u", a, &a);
printf("\nb = %d,\tAddress: %u", b, &b);
swap(&a, &b);
printf("\nAfter Swap: ");
printf("\na = %d,\tAddress: %u", a, &a);
printf("\nb = %d,\tAddress: %u", b, &b);
return 0;
}
void swap(int *a, int *b)
{
*a = *a ^ *b;
*b = *a ^ *b;
*a = *a ^ *b;
}
assignment-s-10.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 17 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to swap two numbers using pointers (user-defined function). */
#include <stdio.h>
void swap(int *, int *);
int main()
{
int a, b;
printf("Enter value for a and b: ");
scanf("%d %d", &a, &b);
printf("\nBefore Swap: ");
printf("\na = %d,\tAddress: %u", a, &a);
printf("\nb = %d,\tAddress: %u", b, &b);
swap(&a, &b);
printf("\nAfter Swap: ");
printf("\na = %d,\tAddress: %u", a, &a);
printf("\nb = %d,\tAddress: %u", b, &b);
return 0;
}
void swap(int *a, int *b)
{
*a = *a ^ *b;
*b = *a ^ *b;
*a = *a ^ *b;
}
assignment-s-11.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 17 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program that takes the radius of a circle as input, passes it to a function that
computes area and circumference, and displays results in main(). */
#include <stdio.h>
#include <math.h>
void area_circumference(double, double *, double *);
int main()
{
double r, area, circumference;
printf("Enter the radius of the circle: ");
scanf("%lf", &r);
area_circumference(r, &area, &circumference);
printf("\nArea of the circle = %g", area);
printf("\nCircumference of the circle = %g", circumference);
return 0;
}
void area_circumference(double r, double *area, double *circumference)
{
*area = M_PI * r * r;
*circumference = 2 * M_PI * r;
}
assignment-s-12.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 17 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to find the sum of n elements entered by the user. Use dynamic
memory allocation (malloc() or calloc()). */
#include <stdio.h>
#include <stdlib.h>
void inputarr(int[], int);
int sum_elem(int[], int);
int main()
{
int n, *arr;
printf("How many element do you want to enter: ");
scanf("%d", &n);
arr = (int *)malloc(n * sizeof(int));
inputarr(arr, n);
printf("\nSum of the %d element(s) = %d", n, sum_elem(arr, n));
free(arr);
return 0;
}
void inputarr(int arr[], int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
int sum_elem(int arr[], int n)
{
int i, sum = 0;
for (i = 0; i < n; i++)
{
sum += arr[i];
}
return sum;
}
assignment-s-13-1.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 19 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a function that reverses the elements of an array in place, using only a single
pointer argument, and return void. */
#include <stdio.h>
#include <stdlib.h>
void inputarr(int[], int);
void display(int[], int);
void reverse(int *);
int main()
{
int size, *arr;
printf("How many element do you want to add: ");
scanf("%d", &size);
arr = (int *)malloc((size + 1) * sizeof(int));
inputarr(arr, size);
printf("\n=== Before Reverse ===\n");
display(arr, size);
reverse(arr);
printf("\n\n=== After Reverse ===\n");
display(arr, size);
free(arr);
return 0;
}
void inputarr(int arr[], int n)
{
int i;
arr[0] = n;
for (i = 1; i <= n; i++)
{
printf("Enter element %d: ", i);
scanf("%d", &arr[i]);
}
}
void display(int arr[], int n)
{
int i;
for (i = 1; i <= n; i++)
{
printf("\nIndex: %-2d | Value: %-5d | Address: %p", i, arr[i], (void *)&arr[i]);
}
}
void reverse(int *arr)
{
int *start = arr + 1;
int size = *arr;
int *end = arr + size;
while (start < end)
{
*start = *start ^ *end;
*end = *start ^ *end;
*start = *start ^ *end;
start++;
end--;
}
}
assignment-s-13-2.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 19 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a function that reverses the elements of an array in place, using only a single
pointer argument, and return void. */
#include <stdio.h>
#include <stdlib.h>
struct Array
{
int size;
int *arr;
};
void inputarr(int[], int);
void display(int[], int);
void reverse(struct Array *);
int main()
{
struct Array array;
printf("How many element do you want to add: ");
scanf("%d", &array.size);
array.arr = (int *)malloc((array.size) * sizeof(int));
inputarr(array.arr, array.size);
printf("\n=== Before Reverse ===\n");
display(array.arr, array.size);
reverse(&array);
printf("\n\n=== After Reverse ===\n");
display(array.arr, array.size);
free(array.arr);
return 0;
}
void inputarr(int arr[], int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
void display(int arr[], int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("\nIndex: %-2d | Value: %-5d | Address: %p", i, arr[i], (void *)&arr[i]);
}
}
void reverse(struct Array *array)
{
int *start = array->arr;
int *end = array->arr + (array->size - 1);
while (start < end)
{
*start = *start ^ *end;
*end = *start ^ *end;
*start = *start ^ *end;
start++;
end--;
}
}
assignment-s-14.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 20 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/*
Write a menu-driven program to perform the following string operations:
a. Show address of each character
b. Concatenate two strings without using strcat()
c. Concatenate two strings using strcat()
d. Compare two strings
e. Find string length using pointers
f. Convert lowercase to uppercase
g. Convert uppercase to lowercase
h. Count number of vowels
i. Reverse the string
*/
#include <stdio.h>
#include <ctype.h>
#include <string.h>
void address_char(char *);
void concat_manual(char[], char[]);
void concat_strcat(char[], char[]);
int string_cmp(char *, char *);
int string_len(char *);
void ltou(char[]);
void utol(char[]);
int vowel_count(char[]);
void reverse(char[]);
int main()
{
char str1[100], str2[100], choice;
int result_cmp;
printf("Enter first string (Max: 100 character): ");
fgets(str1, sizeof(str1), stdin);
str1[strcspn(str1, "\n")] = '\0';
// this will replace the enter (\n) used in the end to null
printf("Enter second string (Max: 100 character): ");
fgets(str2, sizeof(str2), stdin);
str2[strcspn(str2, "\n")] = '\0';
while (1)
{
printf("\n\n\n ========== MENU ==========\n"
"a. Show address of each character\n"
"b. Concatenate two strings without using strcat()\n"
"c. Concatenate two strings using strcat()\n"
"d. Compare two strings\n"
"e. Find string length using pointers\n"
"f. Convert lowercase to uppercase\n"
"g. Convert uppercase to lowercase\n"
"h. Count number of vowels\n"
"i. Reverse the string\n"
"1. Change input strings\n"
"0. Exit\n");
printf("\nEnter your choice: ");
scanf(" %c", &choice);
choice = tolower(choice);
switch (choice)
{
case '1':
while (getchar() != '\n')
;
printf("Enter first string (Max: 100 character): ");
fgets(str1, sizeof(str1), stdin);
str1[strcspn(str1, "\n")] = '\0';
printf("Enter second string (Max: 100 character): ");
fgets(str2, sizeof(str2), stdin);
str2[strcspn(str2, "\n")] = '\0';
break;
case '0':
printf("\n\n\nExiting program...\n\n");
return 0;
case 'a':
printf("\n --- Show address of each character ---\n");
printf("\nSrting 1: ");
address_char(str1);
printf("\nString 2: ");
address_char(str2);
break;
case 'b':
printf("\n --- Concatenate two strings without using strcat() ---\n");
printf("\nResult: ");
concat_manual(str1, str2);
break;
case 'c':
printf("\n --- Concatenate two strings using strcat() ---\n");
printf("\nResult: ");
concat_strcat(str1, str2);
break;
case 'd':
printf("\n --- Compare two strings ---\n");
result_cmp = string_cmp(str1, str2);
if (result_cmp == 0)
{
printf("\nString 1 = String 2");
break;
}
else if (result_cmp > 0)
{
printf("\nString 1 > String 2");
break;
}
else
{
printf("\nString 1 < String 2");
break;
}
case 'e':
printf("\n --- Find string length using pointers ---\n");
printf("\nLength of the String_1: %d", string_len(str1));
printf("\nLength of the String_2: %d", string_len(str2));
break;
case 'f':
printf("\n --- Convert lowercase to uppercase ---\n");
printf("\nString 1: ");
ltou(str1);
printf("\nString 2: ");
ltou(str2);
break;
case 'g':
printf("\n --- Convert uppercase to lowercase ---\n");
printf("\nString 1: ");
utol(str1);
printf("\nString 2: ");
utol(str2);
break;
case 'h':
printf("\n --- Count number of vowels ---\n");
printf("\nString 1: %d", vowel_count(str1));
printf("\nString 2: %d", vowel_count(str2));
break;
case 'i':
printf("\n --- Reverse the string ---\n");
printf("\nString 1: ");
reverse(str1);
printf("\nString 2: ");
reverse(str2);
break;
default:
printf("\nWrong choice. Try again...\n");
}
}
}
void address_char(char *str)
{
printf("\nCharacter | Memory Address");
printf("\n--------- | --------------");
while (*str != '\0')
{
printf("\n %-6c| %p", *str, (void *)str);
str++;
}
}
void concat_manual(char str1[], char str2[])
{
int size1 = strlen(str1);
int size2 = strlen(str2);
char result[size1 + size2 + 1];
int i = 0, j;
j = 0;
while (str1[j] != '\0')
{
result[i] = str1[j];
i++;
j++;
}
j = 0;
while (str2[j] != '\0')
{
result[i] = str2[j];
i++;
j++;
}
result[i] = '\0';
printf("%s\n", result);
}
void concat_strcat(char str1[], char str2[])
{
int size1 = strlen(str1);
int size2 = strlen(str2);
char result[size1 + size2 + 1];
result[0] = '\0';
strcat(result, str1);
strcat(result, str2);
printf("%s\n", result);
}
int string_cmp(char *str1, char *str2)
{
// written based on strcmp()
while (*str1 != '\0' && (*str1 == *str2))
{
str1++;
str2++;
}
return (*str1 - *str2);
}
int string_len(char *str)
{
char *end = str;
while (*end != '\0')
{
end++;
}
return end - str;
}
void ltou(char str[])
{
int i;
for (i = 0; str[i] != '\0'; i++)
{
printf("%c", toupper(str[i]));
}
}
void utol(char str[])
{
int i;
for (i = 0; str[i] != '\0'; i++)
{
printf("%c", tolower(str[i]));
}
}
int vowel_count(char str[])
{
int i, vowel = 0;
char character;
for (i = 0; str[i] != '\0'; i++)
{
character = tolower(str[i]);
if (character == 'a' || character == 'e' || character == 'i' || character == 'o' || character == 'u')
{
vowel++;
}
}
return vowel;
}
void reverse(char str[])
{
int len = strlen(str);
char result[len + 1];
char *start = result;
char *end = result + len - 1;
char temp;
result[0] = '\0';
strcat(result, str);
while (start < end)
{
temp = *start;
*start = *end;
*end = temp;
start++;
end--;
}
printf("%s\n", result);
}
assignment-s-15.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 21 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to merge two sorted integer arrays to form a single sorted array. */
#include <stdio.h>
#include <stdlib.h>
void merge(int[], int, int[], int);
int main()
{
int a[] = {10, 30, 50, 70, 90};
int b[] = {20, 40, 60, 80, 100};
int n1 = sizeof(a) / sizeof(a[0]);
int n2 = sizeof(b) / sizeof(b[0]);
merge(a, n1, b, n2);
return 0;
}
void merge(int a[], int n1, int b[], int n2)
{
int n = n1 + n2;
int *c = (int *)malloc(n * sizeof(int));
int i, j, k;
i = j = k = 0;
while (i < n1 && j < n2)
{
if (a[i] < b[j])
{
c[k++] = a[i++];
}
else
{
c[k++] = b[j++];
}
}
while (i < n1)
{
c[k++] = a[i++];
}
while (j < n2)
{
c[k++] = b[j++];
}
printf("Merged Array:");
for (i = 0; i < n; i++)
{
printf(" %d", c[i]);
}
free(c);
}
assignment-s-16.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 21 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program that reads 10 integers into an array (using pointers), and prints the
array in ascending and descending order. */
#include <stdio.h>
#include <stdlib.h>
#define true 1
#define false 0
void input_arr(int *, int);
void print(int *, int);
int main()
{
int arr[10];
input_arr(arr, 10);
print(arr, 10);
return 0;
}
void input_arr(int *arr, int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", arr + i);
}
}
void print(int *arr, int n)
{
int i, j, isSwaped = true, backup;
int *temp = (int *)malloc(n * sizeof(int));
if (temp == NULL)
{
printf("\nMemory Allocation Failed.");
return;
}
for (i = 0; i < n; i++)
{
*(temp + i) = *(arr + i);
}
for (i = 0; i < n - 1 && isSwaped == true; i++)
{
isSwaped = false;
for (j = 0; j < n - i - 1; j++)
{
if (*(temp + j) > *(temp + j + 1))
{
backup = *(temp + j);
*(temp + j) = *(temp + j + 1);
*(temp + j + 1) = backup;
isSwaped = true;
}
}
}
printf("\nAscending Order:");
for (i = 0; i < n; i++)
{
printf(" %d", *(temp + i));
}
printf("\nDescending Order:");
for (i = n - 1; i >= 0; i--)
{
printf(" %d", *(temp + i));
}
free(temp);
}
assignment-s-17.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 21 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to display the Fibonacci series
(i) using recursion
(ii) using iteration
*/
#include <stdio.h>
long long int fib_rec(int);
long long int fib_tail_rec(int, long long int, long long int);
void fib_rec_print(int);
void fib_ite_print(int);
int main()
{
int n;
printf("Enter the number of terms: ");
scanf("%d", &n);
fib_rec_print(n);
fib_ite_print(n);
return 0;
}
long long int fib_rec(int n)
{
if (n == 0 || n == 1)
{
return n;
}
else
{
return fib_rec(n - 1) + fib_rec(n - 2);
}
}
long long int fib_tail_rec(int n, long long int t1, long long int t2)
{
if (n == 0)
{
return t1;
}
else if (n == 1)
{
return t2;
}
else
{
return fib_tail_rec(n - 1, t2, t1 + t2);
}
}
void fib_rec_print(int n)
{
int i;
printf("\nFibonacci Series (Recursion):");
for (i = 0; i < n; i++)
{
printf(" %lld", fib_rec(i));
}
printf("\nFibonacci Series (Tail-Recursion):");
for (i = 0; i < n; i++)
{
printf(" %lld", fib_tail_rec(i, 0, 1));
}
}
void fib_ite_print(int n)
{
int i;
long long int t1 = 0, t2 = 1, temp;
printf("\nFibonacci Series (Iteration):");
if (n > 0)
{
printf(" 0");
}
if (n > 1)
{
printf(" 1");
}
for (i = 2; i < n; i++)
{
printf(" %lld", t1 + t2);
temp = t1;
t1 = t2;
t2 = temp + t2;
}
}
assignment-s-18.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 22 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to calculate the factorial of a number
(i) using recursion
(ii) using iteration
*/
#include <stdio.h>
long long int fact_tail_rec(int, long long int);
long long int fact_rec(int);
long long int fact_ite(int);
int main()
{
int n;
printf("Enter the number: ");
scanf("%d", &n);
if (n < 0)
{
printf("\nFactorial of negetive number is not possible.");
return 1;
}
printf("\nFactorial of %d (Tail-Recursion) = %lld", n, fact_tail_rec(n, 1));
printf("\nFactorial of %d (Recursion) = %lld", n, fact_rec(n));
printf("\nFactorial of %d (Iteration) = %lld", n, fact_ite(n));
return 0;
}
long long int fact_tail_rec(int n, long long int result)
{
if (n == 0 || n == 1)
{
return result;
}
else
{
return fact_tail_rec(n - 1, n * result);
}
}
long long int fact_rec(int n)
{
if (n == 0 || n == 1)
{
return 1;
}
else
{
return n * fact_rec(n - 1);
}
}
long long int fact_ite(int n)
{
int i;
long long int result = 1;
if (n == 0 || n == 1)
{
return 1;
}
for (i = 2; i <= n; i++)
{
result *= i;
}
return result;
}
assignment-s-19.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 22 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to calculate the GCD of two numbers
(i) using recursion
(ii) without recursion
*/
#include <stdio.h>
int gcd_tail_rec(int, int);
int gcd_rec(int, int);
int gcd_ite(int, int);
int main()
{
int a, b;
printf("Enter two number: ");
scanf("%d %d", &a, &b);
if (a < 0)
a = -a;
if (b < 0)
b = -b;
printf("\nGCD (Tail-Recursion) of %d and %d is = %d", a, b, gcd_tail_rec(a, b));
printf("\nGCD (Recursion) of %d and %d is = %d", a, b, gcd_rec(a, b));
printf("\nGCD (Iteration) of %d and %d is = %d", a, b, gcd_ite(a, b));
return 0;
}
int gcd_tail_rec(int a, int b)
{
if (b == 0)
{
return a;
}
else
{
return gcd_tail_rec(b, a % b);
}
}
int gcd_rec(int a, int b)
{
if (b == 0)
{
return a;
}
else
{
return gcd_rec(b, a % b);
}
}
int gcd_ite(int a, int b)
{
int temp;
while (b > 0)
{
temp = b;
b = a % b;
a = temp;
}
return a;
}
assignment-s-20.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 22 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a menu-driven program to perform the following matrix operations using 2-D
arrays and functions:
a. Sum
b. Difference
c. Product
d. Transpose
*/
#include <stdio.h>
#include <stdlib.h>
#define COL_MAX 10
#define COL_MIN 0
#define ROW_MAX 10
#define ROW_MIN 0
#define TRUE 1
#define FALSE 0
void input(int ***, int *, int *);
void display(int **, int, int);
void clear(int **, int);
void sum(int **, int **, int, int);
void difference(int **, int **, int, int);
void product(int **, int **, int, int, int);
void transpose(int **, int, int);
int main()
{
int **a = NULL, **b = NULL;
int rows_a, rows_b, cols_a, cols_b;
int choice;
while (TRUE)
{
printf("\n === MENU ===\n"
"1. Sum\n"
"2. Difference\n"
"3. Product\n"
"4. Transpose\n"
"0. Exit\n");
printf("\nEnter your choice: ");
scanf("%d", &choice);
switch (choice)
{
case 1:
input(&a, &rows_a, &cols_a);
if (a == NULL)
break;
input(&b, &rows_b, &cols_b);
if (b == NULL)
{
clear(a, rows_a);
a = NULL;
break;
}
printf("\nMatrix A = \n");
display(a, rows_a, cols_a);
printf("\nMatrix B = \n");
display(b, rows_b, cols_b);
if (rows_a != rows_b || cols_a != cols_b)
{
printf("\nOrder of both matrix should be same to calculate sum.");
printf("\nInput : Matrix A = [%d x %d]"
" Matrix B = [%d x %d]",
rows_a, cols_a, rows_b, cols_b);
clear(a, rows_a);
clear(b, rows_b);
a = NULL;
b = NULL;
break;
}
printf("\nResult = \n");
sum(a, b, rows_a, cols_a);
clear(a, rows_a);
clear(b, rows_b);
a = NULL;
b = NULL;
break;
case 2:
input(&a, &rows_a, &cols_a);
if (a == NULL)
break;
input(&b, &rows_b, &cols_b);
if (b == NULL)
{
clear(a, rows_a);
a = NULL;
break;
}
printf("\nMatrix A = \n");
display(a, rows_a, cols_a);
printf("\nMatrix B = \n");
display(b, rows_b, cols_b);
if (rows_a != rows_b || cols_a != cols_b)
{
printf("\nOrder of both matrix should be same to calculate difference.");
printf("\nInput : Matrix A = [%d x %d]"
" Matrix B = [%d x %d]",
rows_a, cols_a, rows_b, cols_b);
clear(a, rows_a);
clear(b, rows_b);
a = NULL;
b = NULL;
break;
}
printf("\nResult = \n");
difference(a, b, rows_a, cols_a);
clear(a, rows_a);
clear(b, rows_b);
a = NULL;
b = NULL;
break;
case 3:
input(&a, &rows_a, &cols_a);
if (a == NULL)
break;
input(&b, &rows_b, &cols_b);
if (b == NULL)
{
clear(a, rows_a);
a = NULL;
break;
}
printf("\nMatrix A = \n");
display(a, rows_a, cols_a);
printf("\nMatrix B = \n");
display(b, rows_b, cols_b);
if (cols_a != rows_b)
{
printf("\nColumn count of matrix A should be same as Row count of matrix B.");
printf("\nInput : Matrix A = [%d x %d]"
" Matrix B = [%d x %d]",
rows_a, cols_a, rows_b, cols_b);
clear(a, rows_a);
clear(b, rows_b);
a = NULL;
b = NULL;
break;
}
printf("\nResult = \n");
product(a, b, rows_a, cols_b, cols_a);
clear(a, rows_a);
clear(b, rows_b);
a = NULL;
b = NULL;
break;
case 4:
input(&a, &rows_a, &cols_a);
if (a == NULL)
break;
printf("\nMatrix = \n");
display(a, rows_a, cols_a);
printf("\nResult = \n");
transpose(a, rows_a, cols_a);
clear(a, rows_a);
a = NULL;
break;
case 0:
printf("\n\nExiting program...\n");
return 0;
default:
printf("\nInvalid choice. Please pick a choice from the menu.\n");
}
}
}
void input(int ***matrix, int *rows, int *cols)
{
int i, j;
printf("\nEnter row and column count (Max : 10 x 10): ");
scanf("%d %d", rows, cols);
if (*rows > ROW_MAX || *cols > COL_MAX || *rows <= ROW_MIN || *cols <= COL_MIN)
{
printf("\nInvalid dimensions. Limit is 1 to 10.\n");
*matrix = NULL;
return;
}
*matrix = (int **)malloc(*rows * sizeof(int *));
for (i = 0; i < *rows; i++)
{
(*matrix)[i] = (int *)malloc(*cols * sizeof(int));
for (j = 0; j < *cols; j++)
{
printf("Enter element [%d][%d]: ", i + 1, j + 1);
scanf("%d", &((*matrix)[i][j]));
}
}
}
void display(int **matrix, int rows, int cols)
{
int i, j;
for (i = 0; i < rows; i++)
{
for (j = 0; j < cols; j++)
{
printf("%d ", matrix[i][j]);
}
printf("\n");
}
}
void clear(int **matrix, int rows)
{
int i;
for (i = 0; i < rows; i++)
{
free(matrix[i]);
}
free(matrix);
}
void sum(int **a, int **b, int rows, int cols)
{
int i, j;
int **r = (int **)malloc(rows * sizeof(int *));
for (i = 0; i < rows; i++)
{
r[i] = (int *)malloc(cols * sizeof(int));
for (j = 0; j < cols; j++)
{
r[i][j] = a[i][j] + b[i][j];
}
}
display(r, rows, cols);
clear(r, rows);
}
void difference(int **a, int **b, int rows, int cols)
{
int i, j;
int **r = (int **)malloc(rows * sizeof(int *));
for (i = 0; i < rows; i++)
{
r[i] = (int *)malloc(cols * sizeof(int));
for (j = 0; j < cols; j++)
{
r[i][j] = a[i][j] - b[i][j];
}
}
display(r, rows, cols);
clear(r, rows);
}
void product(int **a, int **b, int rows_a, int cols_b, int common)
{
int i, x, y, z, temp;
int **r = (int **)malloc(rows_a * sizeof(int *));
for (i = 0; i < rows_a; i++)
{
r[i] = (int *)malloc(cols_b * sizeof(int));
}
for (x = 0; x < rows_a; x++)
{
for (y = 0; y < cols_b; y++)
{
temp = 0;
for (z = 0; z < common; z++)
{
temp += a[x][z] * b[z][y];
}
r[x][y] = temp;
}
}
display(r, rows_a, cols_b);
clear(r, rows_a);
}
void transpose(int **matrix, int rows, int cols)
{
int i, j;
int **r = (int **)malloc(cols * sizeof(int *));
for (i = 0; i < cols; i++)
{
r[i] = (int *)malloc(rows * sizeof(int));
for (j = 0; j < rows; j++)
{
r[i][j] = matrix[j][i];
}
}
display(r, cols, rows);
clear(r, cols);
}
assignment-s-21.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 21 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to copy the contents of a text file to another file, after removing all
white spaces (spaces, tabs, newlines). */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define NEW_FILE_PREFIX "cleaned_"
int cleaning(FILE *);
int main()
{
char filename[50];
char *newFilename = NULL;
FILE *givenFile = NULL;
FILE *cleanedFile = NULL;
int len, temp;
printf("Enter the filename (Max: 50 character): ");
fgets(filename, sizeof(filename), stdin);
len = strlen(filename);
if (filename[len - 1] == '\n')
{
filename[len - 1] = '\0';
}
givenFile = fopen(filename, "r");
if (givenFile == NULL)
{
printf("\nCouldn't opened the file \"%s\""
"\nPlease ensure that \"%s\" is in the same folder.",
filename, filename);
return 1;
}
len += strlen(NEW_FILE_PREFIX);
newFilename = (char *)malloc((len + 1) * sizeof(char));
if (newFilename == NULL)
{
printf("\nMemory allocation failed.");
fclose(givenFile);
return 1;
}
newFilename[0] = '\0';
strcat(newFilename, NEW_FILE_PREFIX);
strcat(newFilename, filename);
cleanedFile = fopen(newFilename, "w");
if (cleanedFile == NULL)
{
printf("\nCUnable to create the file \"%s\"", newFilename);
free(newFilename);
return 1;
}
while ((temp = fgetc(givenFile)) != EOF)
{
if (temp != ' ' && temp != '\n' && temp != '\t')
{
fputc(temp, cleanedFile);
}
}
printf("\nSuccessfully cleaned: \"%s\"", filename);
printf("\nGenerated file: \"%s\"", newFilename);
fclose(givenFile);
fclose(cleanedFile);
free(newFilename);
return 0;
}
assignment-s-22.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 18 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program using structures to add two distances in meter-kilometer format. */
#include <stdio.h>
#include <stdlib.h>
struct distance
{
int km;
int m;
};
void total_distance(struct distance[]);
int main()
{
struct distance dis[2] = {0};
printf("Enter the 1st distance (KM M): ");
scanf("%d %d", &dis[0].km, &dis[0].m);
printf("Enter the 2nd distance: ");
scanf("%d %d", &dis[1].km, &dis[1].m);
total_distance(dis);
return 0;
}
void total_distance(struct distance dis[])
{
int result_km = dis[0].km + dis[1].km;
int result_m = dis[0].m + dis[1].m;
result_km += result_m / 1000;
result_m = result_m % 1000;
printf("Total distance: %d KM, %d M", result_km, result_m);
}
assignment-s-23.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 18 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to add two complex numbers using structures. */
#include <stdio.h>
#include <stdlib.h>
struct complex_number
{
double real;
double imaginary;
};
int main()
{
struct complex_number a, b;
printf("Enter the 1st complex number in this format (a+bi): ");
scanf("%lf+%lfi", &a.real, &a.imaginary);
printf("Enter the 2nd complex number in this format (a+bi): ");
scanf("%lf+%lfi", &b.real, &b.imaginary);
printf("Result = %-2g + %-2.2g", a.real + b.real, a.imaginary + b.imaginary);
return 0;
}
assignment-s-24.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 18 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to calculate the difference between two time periods using structures. */
#include <stdio.h>
#include <stdlib.h>
struct time_dif
{
int hour;
int min;
int sec;
};
int main()
{
struct time_dif tpA, tpB;
long int tfA, tfB, tdif;
printf("Enter the start time in this 24 hours clock format (HH MM SS): ");
scanf("%d %d %d", &tpA.hour, &tpA.min, &tpA.sec);
printf("Enter the end time in this 24 hours clock format (HH MM SS): ");
scanf("%d %d %d", &tpB.hour, &tpB.min, &tpB.sec);
tfA = tpA.hour * 3600 + tpA.min * 60 + tpA.sec;
tfB = tpB.hour * 3600 + tpB.min * 60 + tpB.sec;
tdif = tfB - tfA;
if (tdif < 0)
{
printf("\nWrong information, End time should be later than Start time.");
return 1;
}
printf("\nTime difference: %ld Hour(s) %ld Minutes(s) %ld Second(s).", tdif / 3600, (tdif % 3600) / 60, (tdif % 3600) % 60);
return 0;
}
internal-practice
IP-01.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 03 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to compute the sum and product of digits of an integer using user
defined functions. */
#include <stdio.h>
int sum_of_digits(int);
int product_of_digits(int);
int main()
{
int num;
printf("Enter the number: ");
scanf("%d", &num);
printf("\nSum of digits of %d = %d", num, sum_of_digits(num));
printf("\nProduct of digits of %d = %d", num, product_of_digits(num));
return 0;
}
int sum_of_digits(int num)
{
int sum = 0;
while (num > 0)
{
sum += num % 10;
num /= 10;
}
return sum;
}
int product_of_digits(int num)
{
int product = 1;
while (num > 0)
{
product *= num % 10;
num /= 10;
}
return product;
}
IP-02.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 03 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to reverse a non-negative integer using a function. */
#include <stdio.h>
int reverse(int);
int main()
{
int num;
printf("Enter a non-negetive integer: ");
scanf("%d", &num);
if (num < 0)
{
printf("\nOnly non-negetive integers are allowed.");
return 1;
}
printf("\nReverse of the integer %d = %d", num, reverse(num));
return 0;
}
int reverse(int num)
{
int rev = 0;
while (num > 0)
{
rev = (rev * 10) + (num % 10);
num /= 10;
}
return rev;
}
IP-03.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 03 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to compute the sum of the first n terms of the series using a function:
S=1−2+3−4+5−6+… */
#include <stdio.h>
int sum_of_series(int);
int main()
{
int n;
printf("Enter the n: ");
scanf("%d", &n);
printf("\nSum of the first %d terms of the series = %d", n, sum_of_series(n));
return 0;
}
int sum_of_series(int n)
{
int sum = 0;
int i;
for (i = 1; i <= n; i++)
{
if (i % 2 == 0)
{
sum -= i;
}
else
{
sum += i;
}
}
return sum;
}
IP-04.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a function to check whether a number is prime or not. Use the same function to
generate all prime numbers less than 100. */
#include <stdio.h>
#include <math.h>
int isPrime(int);
int main()
{
int n, i;
printf("Enter the number: ");
scanf("%d", &n);
if (isPrime(n))
{
printf("\nInput %d is a Prime Number.", n);
}
else
{
printf("\nInput %d is not a Prime Number.", n);
}
printf("\nPrime Numbers less than 100:");
for (i = 1; i < 100; i++)
{
if (isPrime(i))
{
printf(" %d", i);
}
}
return 0;
}
int isPrime(int n)
{
if (n <= 1)
return 0;
if (n == 2)
return 1;
if (n % 2 == 0)
return 0;
int temp = (int)sqrt(n);
int i;
for (i = 3; i <= temp; i += 2)
{
if (n % i == 0)
{
return 0;
}
}
return 1;
}
IP-05.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a function to check whether a given string is a palindrome. Use this function to
determine whether an entered string is Palindrome. */
#include <stdio.h>
#include <string.h>
int isPalindrome(char[]);
int main()
{
char input[100];
int len;
printf("Enter the string (Max: 100 Character): ");
fgets(input, sizeof(input), stdin);
len = strlen(input);
if (len > 0 && input[len - 1] == '\n')
{
input[len - 1] = '\0';
}
if (isPalindrome(input))
{
printf("\nInput string \"%s\" is Palindrome.", input);
}
else
{
printf("\nInput string \"%s\" is not Palindrome", input);
}
return 0;
}
int isPalindrome(char str[])
{
char *start = str;
char *end;
int len = strlen(str);
if (len == 0)
{
return 1;
}
end = str + (len - 1);
while (start < end)
{
if (*start != *end)
{
return 0;
}
start++;
end--;
}
return 1;
}
IP-06.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 03 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program using a function to compute and display all factors of a given number. */
#include <stdio.h>
#include <stdlib.h>
void display_factors(int);
int main()
{
int num, i;
printf("Please enter the number to get the factors from it : ");
scanf("%d", &num);
display_factors(num);
return 0;
}
void display_factors(int num) {
int temp = abs(num);
int i;
if (temp == 0)
{
printf("\n0 has infinitely many factors (all integers).");
exit(1);
}
printf("\nThe factors of ' %d ' is :- ", num);
printf("\nPositive : ");
for (i = 1; i <= temp; i++)
if (temp % i == 0)
printf(" %d", i);
printf("\nNegative : ");
for (i = 1; i <= temp; i++)
if (temp % i == 0)
printf(" %d", -i);
}
IP-07.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 03 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to swap two numbers using pointers (user-defined function). */
#include <stdio.h>
void swap(int *, int *);
int main()
{
int a, b;
printf("Enter value for a and b: ");
scanf("%d %d", &a, &b);
printf("\nBefore Swap: ");
printf("\na = %d,\tAddress: %u", a, &a);
printf("\nb = %d,\tAddress: %u", b, &b);
swap(&a, &b);
printf("\nAfter Swap: ");
printf("\na = %d,\tAddress: %u", a, &a);
printf("\nb = %d,\tAddress: %u", b, &b);
return 0;
}
void swap(int *a, int *b)
{
*a = *a ^ *b;
*b = *a ^ *b;
*a = *a ^ *b;
}
IP-08.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 03 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program that takes the radius of a circle as input, passes it to a function that
computes area and circumference, and displays results in main(). */
#include <stdio.h>
#include <math.h>
void area_circumference(double, double *, double *);
int main()
{
double r, area, circumference;
printf("Enter the radius of the circle: ");
scanf("%lf", &r);
area_circumference(r, &area, &circumference);
printf("\nArea of the circle = %g", area);
printf("\nCircumference of the circle = %g", circumference);
return 0;
}
void area_circumference(double r, double *area, double *circumference)
{
*area = M_PI * r * r;
*circumference = 2 * M_PI * r;
}
IP-09.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 03 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to find the sum of n elements entered by the user. Use dynamic
memory allocation (malloc() or calloc()). */
#include <stdio.h>
#include <stdlib.h>
void inputarr(int[], int);
int sum_elem(int[], int);
int main()
{
int n, *arr;
printf("How many element do you want to enter: ");
scanf("%d", &n);
arr = (int *)malloc(n * sizeof(int));
inputarr(arr, n);
printf("\nSum of the %d element(s) = %d", n, sum_elem(arr, n));
free(arr);
return 0;
}
void inputarr(int arr[], int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
int sum_elem(int arr[], int n)
{
int i, sum = 0;
for (i = 0; i < n; i++)
{
sum += arr[i];
}
return sum;
}
IP-10.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a function that reverses the elements of an array in place, using only a single
pointer argument, and return void. */
#include <stdio.h>
#include <stdlib.h>
void inputArray(int[], int);
void printArray(int[], int);
void reverse(int *);
int main()
{
int n, i, *arr = NULL;
printf("Enter the number of element: ");
scanf("%d", &n);
arr = (int *)malloc(n * sizeof(int));
if (arr == NULL)
{
printf("\nMemory allocation failed.");
return 1;
}
inputArray(arr, n);
printf("\nGiven Array: ");
printArray(arr, n);
for (i = 0; i < n; i++)
{
reverse(&arr[i]);
}
printf("\nUpdated Array: ");
printArray(arr, n);
free(arr);
return 0;
}
void inputArray(int arr[], int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
void printArray(int arr[], int n)
{
int i;
printf("[");
for (i = 0; i < n; i++)
{
printf("%d", arr[i]);
if (i < n - 1)
{
printf(", ");
}
}
printf("]");
}
void reverse(int *n)
{
int temp = *n;
int rev = 0;
while (temp > 0)
{
rev = (rev * 10) + (temp % 10);
temp /= 10;
}
*n = rev;
}
IP-11.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to merge two sorted integer arrays to form a single sorted array. */
#include <stdio.h>
#include <stdlib.h>
void merge(int[], int, int[], int);
int main()
{
int a[] = {10, 30, 50, 70, 90};
int b[] = {20, 40, 60, 80, 100};
int n1 = sizeof(a) / sizeof(a[0]);
int n2 = sizeof(b) / sizeof(b[0]);
merge(a, n1, b, n2);
return 0;
}
void merge(int a[], int n1, int b[], int n2)
{
int n = n1 + n2;
int *c = (int *)malloc(n * sizeof(int));
int i, j, k;
i = j = k = 0;
while (i < n1 && j < n2)
{
if (a[i] < b[j])
{
c[k++] = a[i++];
}
else
{
c[k++] = b[j++];
}
}
while (i < n1)
{
c[k++] = a[i++];
}
while (j < n2)
{
c[k++] = b[j++];
}
printf("Merged Array:");
for (i = 0; i < n; i++)
{
printf(" %d", c[i]);
}
free(c);
}
IP-12.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program that reads 10 integers into an array (using pointers), and prints the
array in ascending and descending order. */
#include <stdio.h>
#include <stdlib.h>
#define true 1
#define false 0
void input_arr(int *, int);
void print(int *, int);
int main()
{
int arr[10];
input_arr(arr, 10);
print(arr, 10);
return 0;
}
void input_arr(int *arr, int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", arr + i);
}
}
void print(int *arr, int n)
{
int i, j, isSwaped = true, backup;
int *temp = (int *)malloc(n * sizeof(int));
if (temp == NULL)
{
printf("\nMemory Allocation Failed.");
return;
}
for (i = 0; i < n; i++)
{
*(temp + i) = *(arr + i);
}
for (i = 0; i < n - 1 && isSwaped == true; i++)
{
isSwaped = false;
for (j = 0; j < n - i - 1; j++)
{
if (*(temp + j) > *(temp + j + 1))
{
backup = *(temp + j);
*(temp + j) = *(temp + j + 1);
*(temp + j + 1) = backup;
isSwaped = true;
}
}
}
printf("\nAscending Order:");
for (i = 0; i < n; i++)
{
printf(" %d", *(temp + i));
}
printf("\nDescending Order:");
for (i = n - 1; i >= 0; i--)
{
printf(" %d", *(temp + i));
}
free(temp);
}
IP-13.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to display the Fibonacci series
(i) using recursion
(ii) using iteration
*/
#include <stdio.h>
long long int fib_rec(int);
long long int fib_tail_rec(int, long long int, long long int);
void fib_rec_print(int);
void fib_ite_print(int);
int main()
{
int n;
printf("Enter the number of terms: ");
scanf("%d", &n);
fib_rec_print(n);
fib_ite_print(n);
return 0;
}
long long int fib_rec(int n)
{
if (n == 0 || n == 1)
{
return n;
}
else
{
return fib_rec(n - 1) + fib_rec(n - 2);
}
}
long long int fib_tail_rec(int n, long long int t1, long long int t2)
{
if (n == 0)
{
return t1;
}
else if (n == 1)
{
return t2;
}
else
{
return fib_tail_rec(n - 1, t2, t1 + t2);
}
}
void fib_rec_print(int n)
{
int i;
printf("\nFibonacci Series (Recursion):");
for (i = 0; i < n; i++)
{
printf(" %lld", fib_rec(i));
}
printf("\nFibonacci Series (Tail-Recursion):");
for (i = 0; i < n; i++)
{
printf(" %lld", fib_tail_rec(i, 0, 1));
}
}
void fib_ite_print(int n)
{
int i;
long long int t1 = 0, t2 = 1, temp;
printf("\nFibonacci Series (Iteration):");
if (n > 0)
{
printf(" 0");
}
if (n > 1)
{
printf(" 1");
}
for (i = 2; i < n; i++)
{
printf(" %lld", t1 + t2);
temp = t1;
t1 = t2;
t2 = temp + t2;
}
}
IP-14.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to calculate the factorial of a number
(i) using recursion
(ii) using iteration
*/
#include <stdio.h>
long long int fact_tail_rec(int, long long int);
long long int fact_rec(int);
long long int fact_ite(int);
int main()
{
int n;
printf("Enter the number: ");
scanf("%d", &n);
if (n < 0)
{
printf("\nFactorial of negetive number is not possible.");
return 1;
}
printf("\nFactorial of %d (Tail-Recursion) = %lld", n, fact_tail_rec(n, 1));
printf("\nFactorial of %d (Recursion) = %lld", n, fact_rec(n));
printf("\nFactorial of %d (Iteration) = %lld", n, fact_ite(n));
return 0;
}
long long int fact_tail_rec(int n, long long int result)
{
if (n == 0 || n == 1)
{
return result;
}
else
{
return fact_tail_rec(n - 1, n * result);
}
}
long long int fact_rec(int n)
{
if (n == 0 || n == 1)
{
return 1;
}
else
{
return n * fact_rec(n - 1);
}
}
long long int fact_ite(int n)
{
int i;
long long int result = 1;
if (n == 0 || n == 1)
{
return 1;
}
for (i = 2; i <= n; i++)
{
result *= i;
}
return result;
}
IP-15.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to calculate the GCD of two numbers
(i) using recursion
(ii) without recursion
*/
#include <stdio.h>
int gcd_tail_rec(int, int);
int gcd_rec(int, int);
int gcd_ite(int, int);
int main()
{
int a, b;
printf("Enter two number: ");
scanf("%d %d", &a, &b);
if (a < 0)
a = -a;
if (b < 0)
b = -b;
printf("\nGCD (Tail-Recursion) of %d and %d is = %d", a, b, gcd_tail_rec(a, b));
printf("\nGCD (Recursion) of %d and %d is = %d", a, b, gcd_rec(a, b));
printf("\nGCD (Iteration) of %d and %d is = %d", a, b, gcd_ite(a, b));
return 0;
}
int gcd_tail_rec(int a, int b)
{
if (b == 0)
{
return a;
}
else
{
return gcd_tail_rec(b, a % b);
}
}
int gcd_rec(int a, int b)
{
if (b == 0)
{
return a;
}
else
{
return gcd_rec(b, a % b);
}
}
int gcd_ite(int a, int b)
{
int temp;
while (b > 0)
{
temp = b;
b = a % b;
a = temp;
}
return a;
}
IP-16.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that includes a user-defined function named isArmstrong with the
signature int isArmstrong(int num);. An Armstrong number is a number that is equal to
the sum of its own digits each raised to the power of the number of digits. For example,
153 is an Armstrong number because 1^3 + 5^3 + 3^3 = 153 */
#include <stdio.h>
#include <math.h>
int isArmstrong(int);
int count(int);
int main()
{
int n;
printf("Enter the number: ");
scanf("%d", &n);
if (isArmstrong(n))
{
printf("\nInput %d is a Armstrong Number.", n);
}
else
{
printf("\nInput %d is Not a Armstrong Number.", n);
}
return 0;
}
int count(int n)
{
int count = 0;
while (n > 0)
{
count++;
n = n / 10;
}
return count;
}
int isArmstrong(int n)
{
if (n < 0)
return 0;
if (n == 0)
return 1;
int power = count(n);
int temp = n;
int checker = 0;
while (temp > 0)
{
int digit = temp % 10;
checker = checker + (int)round(pow(digit, power));
temp = temp / 10;
}
return n == checker;
}
IP-17.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 03 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a C program that includes a user-defined function named isPerfect with the signature
int isPerfect(int num);. A perfect number is a positive integer that is equal to the sum of
its proper divisors, excluding itself. For example, 28 is a perfect number because the sum
of its divisors (1, 2, 4, 7, 14) equals 28. */
#include <stdio.h>
int isPerfect(int);
int main()
{
int n;
printf("Enter the number: ");
scanf("%d", &n);
if (isPerfect(n))
{
printf("\nInput %d is a Perfect Number.", n);
}
else
{
printf("\nInput %d is not a Perfect Number.", n);
}
return 0;
}
int isPerfect(int n)
{
if (n <= 1)
return 0;
int temp = 1;
int i;
for (i = 2; i <= n / 2; i++)
{
if (n % i == 0)
{
temp += i;
}
}
return temp == n;
}
IP-18.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that includes a user-defined function named findLargest with the
signature int findLargest(int arr[], int size);. The function should take an array of integers
and its size, and return the largest element in the array. */
#include <stdio.h>
void inputArray(int[], int);
int findLargest(int[], int);
int main()
{
int size;
printf("How many element do you want to enter: ");
scanf("%d", &size);
int arr[size];
inputArray(arr, size);
printf("\nLargest Element is: %d", findLargest(arr, size));
return 0;
}
void inputArray(int arr[], int size)
{
int i;
for (i = 0; i < size; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
int findLargest(int arr[], int size)
{
int largest = arr[0], i;
for (i = 1; i < size; i++)
{
if (largest < arr[i])
{
largest = arr[i];
}
}
return largest;
}
IP-19.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that includes a user-defined function named binarySearch with the
signature int binarySearch(int arr[], int size, int target);. The function should perform a
binary search on a sorted array of integers and return the index of the target element if
found, and -1 otherwise. */
#include <stdio.h>
int inputArray(int[], int);
// void sortArray(int[], int);
int binarySearch(int[], int, int);
int main()
{
int size;
printf("How many element do you want to enter: ");
scanf("%d", &size);
int arr[size];
int target = inputArray(arr, size);
// sortArray(arr, size); // If needed
int index = binarySearch(arr, size, target);
if (index != -1)
{
printf("\nElement %d is found at index %d.", target, index);
}
else
{
printf("\nElement %d is not found.", target);
}
return 0;
}
int inputArray(int arr[], int size)
{
int i, target;
for (i = 0; i < size; i++)
{
printf("Enter element for position %d: ", i);
scanf("%d", &arr[i]);
}
printf("\nEnter the target element: ");
scanf("%d", &target);
return target;
}
/* void sortArray(int arr[], int size)
{
// using Bubble Sort...
int tempArr[size], i, j, temp;
printf("\nBefore Sorting:\n[");
for (i = 0; i < size; i++)
{
printf("%d", arr[i]);
if (i != size - 1)
{
printf(", ");
}
}
printf("]\n");
for (i = 0; i < size - 1; i++)
{
for (j = 0; j < size - i - 1; j++)
{
if (arr[j] > arr[j + 1])
{
temp = arr[j];
arr[j] = arr[j + 1];
arr[j + 1] = temp;
}
}
}
printf("\nAfter Sorting:\n[");
for (i = 0; i < size; i++)
{
printf("%d", arr[i]);
if (i != size - 1)
{
printf(", ");
}
}
printf("]\n");
}
*/
int binarySearch(int arr[], int size, int target)
{
int low = 0;
int high = size - 1;
int mid;
while (low <= high)
{
mid = low + ((high - low) / 2);
if (arr[mid] == target)
{
return mid;
}
else if (arr[mid] > target)
{
high = mid - 1;
}
else if (arr[mid] < target)
{
low = mid + 1;
}
}
return -1;
}
IP-20.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 03 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program that defines an array of integers, and includes a user-defined function
named reverseArray with the signature void reverseArray(int arr[], int size);. The function
should reverse the elements of the array. */
#include <stdio.h>
void inputArray(int[], int);
void reverseArray(int[], int);
int main()
{
int size;
printf("How many element do you want to add: ");
scanf("%d", &size);
int arr[size];
inputArray(arr, size);
reverseArray(arr, size);
return 0;
}
void inputArray(int arr[], int size)
{
int i;
for (i = 0; i < size; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
void reverseArray(int arr[], int size)
{
int i, j, temp;
printf("\nBefore Reverse: \n");
for (i = 0; i < size; i++)
{
printf("Position: %d, Value: %d\n", i, arr[i]);
}
for (i = 0, j = size - 1; i < j; i++, j--)
{
temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
printf("\nAfter Reverse: \n");
for (i = 0; i < size; i++)
{
printf("Position: %d, Value: %d\n", i, arr[i]);
}
}
khurapati-idea
KI001.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
// khurapati idea no. : 1
// Idea : we can use the side effect of printf function to get length of any string or number
#include <stdio.h>
int main()
{
// testing number
int num, len = -13 /* here minus 13 because we will remove the massage characters in line 10 */;
printf("Enter a number to get the length : ");
scanf("%d", &num);
len += printf("Your input : %d", num); // here the "Your input : ", this 13 characters are extra
printf("\nLength : %d", len);
// testing char
char a[20];
len = -13;
while (getchar() != '\n')
;
printf("\nEnter a word to get the length : ");
scanf("%19s", &a);
len += printf("Your input : %s", a); // here the "Your input : ", this 13 characters are extra
printf("\nLength : %d", len);
return 0;
}
KI002.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Plan - checking for edge case */
#include <stdio.h>
int main()
{
printf("Starting.....\n");
for (int i = 1; ; i++)
{
printf("i = %d\n", i);
}
return 0;
}
KI003.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 24 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Bubble sort (with swap) */
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
void inputarr(int **, int);
void display(int[], int);
int asort(int *, int);
int dsort(int *, int);
int main()
{
int *arr = NULL, n, choice;
do
{
printf("\nEnter element count: ");
if (scanf("%d", &n) != 1 || n < 1)
{
printf("\nERROR: Invalid element count!!! Try again...");
}
else
{
break;
}
} while (true);
inputarr(&arr, n);
while (true)
{
printf("\n1. Sort in Ascending Order."
"\n2. Sort in Descending Order"
"\n3. Change Input"
"\n0. Exit"
"\nYour choice: ");
do
{
if (scanf("%d", &choice) != 1)
{
printf("\nInvalid Choice!!! Try again...");
while (getchar() != '\n')
;
}
else
{
break;
}
} while (true);
switch (choice)
{
case 1:
printf("\n === Selected Mode: Ascending Order ===\n");
if (!asort(arr, n))
{
printf("\nElements are already sorted.\n");
display(arr, n);
}
printf("\n");
break;
case 2:
printf("\n === Selected Mode: Descending Order ===\n");
if (!dsort(arr, n))
{
printf("\nElements are already sorted.\n");
display(arr, n);
}
printf("\n");
break;
case 3:
do
{
printf("\nEnter element count: ");
if (scanf("%d", &n) != 1 || n < 1)
{
printf("\nERROR: Invalid element count!!! Try again...");
}
else
{
break;
}
} while (true);
free(arr);
inputarr(&arr, n);
break;
case 0:
printf("\nExiting Program...\n");
free(arr);
return 0;
default:
printf("\nInvalid Choice!!! Try again...");
}
}
}
void inputarr(int **arr, int n)
{
int i;
if (n < 1)
{
printf("\nInvalid element number.");
return;
}
*arr = (int *)malloc(n * sizeof(int));
if (*arr == NULL)
{
printf("\nERROR: Memory Allocation falied.\nExiting Program...\n");
exit(1);
}
for (i = 0; i < n; i++)
{
printf("Enter Element %d: ", i + 1);
scanf("%d", &((*arr)[i]));
}
}
void display(int arr[], int n)
{
int i;
printf("[");
for (i = 0; i < n; i++)
{
printf("%d", arr[i]);
if (i != n - 1)
{
printf(", ");
}
}
printf("]");
}
int asort(int *arr, int n)
{
bool isSwaped = true;
int i, j, tempNum, swapCount = 0;
int *temp = (int *)malloc(n * sizeof(int));
if (temp == NULL)
{
printf("\nERROR: Memory Allocation falied.\nExiting Program...\n");
free(arr);
exit(1);
}
for (i = 0; i < n; i++)
{
temp[i] = *(arr + i);
}
for (i = 0; i < n - 1 && isSwaped == true; i++)
{
isSwaped = false;
for (j = 0; j < n - i - 1; j++)
{
if (temp[j] > temp[j + 1])
{
tempNum = temp[j];
temp[j] = temp[j + 1];
temp[j + 1] = tempNum;
isSwaped = true;
swapCount++;
}
}
}
if (swapCount > 0)
{
display(temp, n);
}
free(temp);
return swapCount;
}
int dsort(int *arr, int n)
{
bool isSwaped = true;
int i, j, tempNum, swapCount = 0;
int *temp = (int *)malloc(n * sizeof(int));
if (temp == NULL)
{
printf("\nERROR: Memory Allocation falied.\nExiting Program...\n");
free(arr);
exit(1);
}
for (i = 0; i < n; i++)
{
temp[i] = *(arr + i);
}
for (i = 0; i < n - 1 && isSwaped == true; i++)
{
isSwaped = false;
for (j = 0; j < n - i - 1; j++)
{
if (temp[j] < temp[j + 1])
{
tempNum = temp[j];
temp[j] = temp[j + 1];
temp[j + 1] = tempNum;
isSwaped = true;
swapCount++;
}
}
}
if (swapCount > 0)
{
display(temp, n);
}
free(temp);
return swapCount;
}
KI004.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 27 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Trying to write code only with emoji */
#include<stdio.h>
#define 😒 int
#define 😊 main
#define 😂 (
#define 🤣 )
#define ❤️ printf
#define 😍 ;
#define 🙌 return
#define 👍 scanf
#define 😁 "
#define 👌 {
#define 😘 }
😒 😊😂🤣👌
😒 num😍
❤️😂😁Enter the number: 😁🤣😍
👍😂😁%d😁, &num🤣😍
❤️😂😁Entered number: %d😁, num🤣😍
🙌 0😍
😘
interpeter.py
# Author : Amit Dutta <amitdutta4255@gmail.com>
# Date : 06 Feb 2026
# Repo : https://github.com/notamitgamer/bsc
# License : MIT License (See the LICENSE file for details)
# Copyright (c) 2026 Amit Dutta
import sys
import os
import subprocess
import re
# Set the absolute path to your GCC compiler based on your system logs
COMPILER_PATH = r"G:\bsc\MinGW64\bin\gcc.exe"
def run_universal_compiler():
if len(sys.argv) < 2:
print("Usage: python emojic.py <file.c>")
sys.exit(1)
source_path = sys.argv[1]
if not os.path.exists(source_path):
print(f"File not found: {source_path}")
sys.exit(1)
with open(source_path, 'r', encoding='utf-8') as f:
content = f.read()
mapping = {}
# Extract emoji mappings from #define statements
define_pattern = re.compile(r'#define\s+(\S+)\s+(.+)')
lines = content.splitlines()
code_lines = []
for line in lines:
match = define_pattern.match(line.strip())
if match:
emoji_key = match.group(1)
c_value = match.group(2).strip()
mapping[emoji_key] = c_value
else:
code_lines.append(line)
translated_code = "\n".join(code_lines)
# Sort keys by length descending to replace multi-emoji tokens correctly
sorted_keys = sorted(mapping.keys(), key=len, reverse=True)
for key in sorted_keys:
translated_code = translated_code.replace(key, mapping[key])
# Ensure standard header is present if logic needs it
header = "#include <stdio.h>\n"
if "#include" not in translated_code:
translated_code = header + translated_code
temp_file = "output_target.c"
with open(temp_file, "w", encoding="utf-8") as f:
f.write(translated_code)
exe_name = source_path.rsplit('.', 1)[0] + ".exe"
compile_cmd = [COMPILER_PATH, temp_file, "-o", exe_name]
try:
# Use shell=True for better command resolution on Windows
result = subprocess.run(compile_cmd, capture_output=True, text=True, shell=(os.name == 'nt'))
if result.returncode == 0:
print(f"Compilation Successful: {exe_name}")
run_cmd = [f".\\{exe_name}"] if os.name == 'nt' else [f"./{exe_name}"]
subprocess.run(run_cmd, shell=(os.name == 'nt'))
else:
print("Compilation Error:")
print(result.stderr)
except FileNotFoundError:
print(f"Error: Compiler '{COMPILER_PATH}' not found.")
print("Please ensure GCC is installed and added to your PATH,")
print("or edit COMPILER_PATH in this script to point to your gcc.exe.")
if os.path.exists(temp_file):
os.remove(temp_file)
if __name__ == "__main__":
run_universal_compiler()
letusc
interest.h
/*
* Author : Amit Dutta
* File : interest.h
*/
#define SIMPLE_INTEREST(p, r, t) ((p * r * t) / 100.0)
#define AMOUNT(p, si) (p + si)
luc001.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Temperature of a city in fahrenheit degrees is input through
the keyboard. WAP to convert this temperature into Centigrade
degrees. */
/* Chapter 1; Page 19; Question NO.: F(a) */
#include<stdio.h>
int main() {
float f, c;
printf("Enter the temperature of city in Fahrenheit : ");
scanf("%f", &f);
// formula (F - 32) 5/9
c = ((f - 32) * 5) / 9;
printf("\nTemperature in centigrade : %f", c);
return 0;
}
luc002.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* The length and breadth of a rectangle and radius of a circle
are input through the keyboard. Write a program to calculate the
area and perimeter of the rectangle, and the area and circumference
of the circle. */
/* Let Us C; Page - 19; Chap- 1; QNo.: F(b) */
#include <stdio.h>
#include <math.h>
int main()
{
double len, bre, r, area_r, per, area_c, cir;
printf("Enter the length and breadth of the rectangle : ");
scanf("%lf %lf", &len, &bre);
printf("Enter the Radius of the circle : ");
scanf("%lf", &r);
area_r = len * bre;
per = 2 * (len + bre);
area_c = M_PI * r * r;
cir = 2 * M_PI * r;
printf("\nArea of Rectangle : %lf"
"\nPerimeter of Rectangle : %lf"
"\nArea of Circle : %lf"
"\nCircumference of Circle : %lf",
area_r, per, area_c, cir);
return 0;
}
luc003.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Paper of size AO has dimensions 1189 mm x 841 mm.
Each subsequent size A(n) is defined as A(n-1) cut in
half, parallel to its shorter sides. Thus, paper of
size A1 would have dimensions 841 mm x 594 mm. Write
a program to calculate and print paper sizes A0,�
A1,�A2,�...�A8. */
/* Let Us C; Page - 19; Chap- 1; QNo.: F(c) */
#include<stdio.h>
#include<math.h>
int main() {
double s_long = 1189.0, s_short = 841.0, temp;
int i;
printf("A0 Dimension : %g mm x %g mm", floor(s_long), floor(s_short));
for (i = 1; i <= 8; i++) {
temp = s_long;
s_long = s_short;
s_short = temp / 2;
printf("\nA%d Dimension : %g mm x %g mm", i, floor(s_long), floor(s_short));
}
return 0;
}
luc004.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* If a five digit number is input through the keyboard,
write a program to calculate the sum of it's digit.
(Hint : Use the modulus operator %) */
/* Let Us C; Page - 37; Chap- 2; QNo.: G(a) */
#include <stdio.h>
int main()
{
int inp, result = 0, i, temp;
printf("Enter a five digit number : ");
scanf("%d", &inp);
if (inp < 10000 || inp > 99999)
{
printf("\nPlease enter a valid five digit number.");
return 1;
}
temp = inp;
for (i = 1; i <= 5; i++)
{
result = result + (inp % 10);
inp = inp / 10;
}
printf("\nSum of the digit '%d' is : %d", temp, result);
return 0;
}
luc005.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to recive Cartesian
co-ordinates (x, y) of a point and convert
them into Polar co-ordinates (r, phi)
Hint : r = sqrt (x^2 + y^2) and phi = tan^-1 (y/x) */
/* Let Us C; Page - 37; Chap- 2; QNo.: G(b) */
#include <stdio.h>
#include <math.h>
int main()
{
double x, y, r, phi;
printf("Enter the Cartesian Co-Ordinates in this format 'x, y' : ");
scanf("%lf, %lf", &x, &y);
r = sqrt(pow(x, 2) + pow(y, 2));
phi = atan2(y, x);
printf("\nPolar Co-Ordinates are : (%g, %g Rad)", r, phi);
return 0;
}
luc006.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to receive values of latitude (L1, L2) and longitude
(G1, G2), in degrees, of two places on the earth and output the distance
(D) between them in nautical miles. The formula for distance in nautical
miles is :
D = 3963 cos^-1(sin L1 sin L2 + cos L1 cos L2 * cos(G2 - G1))
*/
/* Let Us C, Chap - 2, Page - 37, Qn no.: G(c) */
#include <stdio.h>
#include <math.h>
int main()
{
double l1, l2, g1, g2, d;
printf("Enter the Latitude in 'L1, L2' format : ");
scanf("%lf, %lf", &l1, &l2);
printf("Enter the Longitude in 'G1, G2' format : ");
scanf("%lf, %lf", &g1, &g2);
// Converting degree to radian because function from math.h use radian not degree
l1 = l1 * (M_PI / 180);
l2 = l2 * (M_PI / 180);
g1 = g1 * (M_PI / 180);
g2 = g2 * (M_PI / 180);
d = 3963 * acos(sin(l1) * sin(l2) + cos(l1) * cos(l2) * cos(g2 - g1));
printf("Distance in nautical miles : %g", d);
return 0;
}
luc007.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Wind-chill factor is the felt air temperature on exposed skin due to wind.
The wind-chill temperature is always lower than the air temperature, and is
calculated as per the following formula.
wcf = 35.74 + 0.6215t + (0.4275t - 35.75) * v^0.16
Where t is temperature and v is wind velocity. Write a program to receive
values of t and v and calcualate wind-chill factor (wcf). */
/* Let Us C, Chap - 2, Page - 37, Qn No.: G(d) */
#include <stdio.h>
#include <math.h>
int main()
{
double t, v, wcf;
printf("Enter the temperature and velociy of the wind : ");
scanf("%lf %lf", &t, &v);
wcf = 35.74 + (0.6215 * t) + (((0.4275 * t) - 35.75) * pow(v, 0.16));
printf("\nWind-chill factor (wcf) : %g", wcf);
return 0;
}
luc008.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* If value of an angle is input through the keyboard,
write a program to print all its trigonometric ratios. */
/* Let Us C, Chap - 2, Page - 37, Qn No.: G(e) */
#include <stdio.h>
#include <math.h>
int main()
{
double inp, rsin, rcos, rtan, rcosec, rsec, rcot;
printf("Enter the Angle in degree : ");
scanf("%lf", &inp);
inp = inp * (M_PI / 180); //changing degree to radian
rsin = sin(inp);
rcos = cos(inp);
rtan = tan(inp);
rcosec = 1 / rsin;
rsec = 1 / rcos;
rcot = 1 / rtan;
printf("\nTrigonometric ratios :-"
"\nsin = %g "
"\ncos = %g"
"\ntan = %g"
"\ncosec = %g"
"\nsec = %g"
"\ncot = %g",
rsin, rcos, rtan, rcosec, rsec, rcot);
return 0;
}
luc009.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Two numbers are input through the keyboard into two locations
C and D. Write a program to interchange the contents of C and D. */
/* Let Us C, Chap - 2, Page - 37, Qn No.: G(d) */
#include <stdio.h>
int main()
{
double a, b;
printf("Enter the two number A and B : ");
scanf("%lf %lf", &a, &b);
printf("\nBefore Interchange : ");
printf("\nA = %g (Memory location = %p)", a, &a);
printf("\nB = %g (Memory location = %p)", b, &b);
a = a + b;
b = a - b;
a = a - b;
printf("\nAfter Interchange :");
printf("\nA = %g (Memory location = %p)", a, &a);
printf("\nB = %g (Memory location = %p)", b, &b);
return 0;
}
luc010.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* A five-digit number is entered through the keyboard. Write a program
to obtain the reversed number and to etermine whether the original and reversed
numbers are equal or not. */
/* Let Us C, Chap - 3, Page - 53, Qn No.: f(a) */
#include <stdio.h>
int main()
{
int num, rev, temp, i;
printf("Please enter the number : ");
scanf("%d", &num);
if (num < 10000 || num > 99999)
{
printf("\nPlease enter a five digit number.");
return 1;
}
temp = num;
for (i = 1; i <= 5; i++)
{
rev = (rev * 10) + num % 10;
num = num / 10;
}
printf("\nReverse of the Input number : %d", rev);
if (rev == temp)
printf("\nOriginal and reversed numbers are equal.");
else
printf("\nOrigianl and reversed numbers are not equal.");
return 0;
}
luc011.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* If ages of Ram, Shyam and Ajay are input through the keyboard,
write a program to determine the youngest of the three. */
/* Let Us C, Chap- 3, Page - 53, Qn No.: f(b) */
#include <stdio.h>
int main()
{
int ram, shyam, ajay;
printf("Please enter the age of Ram, Shyam and Ajay : ");
scanf("%d %d %d", &ram, ­am, &ajay);
if (ram == shyam || ram == ajay || shyam == ajay)
printf("\nThree must have different age.");
if (ram < shyam && ram < ajay)
printf("\nRam is the youngest. Age : %d", ram);
if (shyam < ram && shyam < ajay)
printf("\nShyam is the youngest. Age : %d", shyam);
if (ajay < ram && ajay < shyam)
printf("\nAjay is the youngest. Age : %d", ajay);
return 0;
}
luc012.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to check whether a triangle is valid or not,
if three angles of the triangle are entered through the keyboard.
A triangle is valid if the sum of all the three angles is equal to 180 degrees. */
/* Let Us C, Chap- 3, Page - 53, Qn No.: f(c) */
#include <stdio.h>
int main()
{
double angle1, angle2, angle3, sum;
printf("Enter the value of the three angle of the triangle : ");
scanf("%lf %lf %lf", &angle1, &angle2, &angle3);
sum = angle1 + angle2 + angle3;
if (sum == 180.0)
printf("\nThis Triangle is a valid one.");
else
printf("\nThis Triangle is not valid. Sum of the angles : %g", sum);
return 0;
}
luc013.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to find the absolute value
of a number entered through the keyboard. */
/* Let Us C, Chap- 3, Page - 53, Qn No.: f(d) */
#include <stdio.h>
#include <math.h>
int main()
{
double num;
printf("Enter the number : ");
scanf("%lf", &num);
num = abs(num);
printf("\nAbsolute value of the input is : %g", num);
return 0;
}
luc014.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Given the length and breadth of a rectangle, write a program to find
whether the area of the rectangle is greater than it's perimeter.
For example, the area of the rectangle with length = 5 and breadth = 4
is greater than its perimeter. */
/* Let Us C, Chap- 3, Page - 53, Qn No.: f(e) */
#include <stdio.h>
int main()
{
double len, bre, area, peri;
printf("Enter the length and breadth of the rectangle : ");
scanf("%lf %lf", &len, &bre);
area = len * bre;
peri = 2 * (len + bre);
if (area > peri)
printf("\nThe area of the rectangle is greater than it's perimeter.");
else if (area < peri)
printf("\nThe area of the rectangle is lower than it's perimeter.");
else
printf("\nThe area of the rectangle is same as it's perimeter.");
return 0;
}
luc015.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Given three points (x1, y1), (x2, y2), and (x3, y3),
write a program to check if the three poins fall on one straight line. */
/* Let Us C, Chap- 3, Page - 53, Qn No.: f(f) */
#include <stdio.h>
#include <math.h>
#define EPSILON 0.0001
// Define a small tolerance value (EPSILON) for safe floating-point comparison
// This is critical because of minor rounding errors in computer arithmetic.
int main()
{
double x1, x2, x3, y1, y2, y3, area;
printf("Enter the point A(x1, y1) : ");
scanf("%lf %lf", &x1, &y1);
printf("Enter the point B(x2, y2) : ");
scanf("%lf %lf", &x2, &y2);
printf("Enter the point C(x3, y3) : ");
scanf("%lf %lf", &x3, &y3);
area = 0.5 * ((x1 * (y2 - y3)) + (x2 * (y3 - y1)) + (x3 * (y1 - y2)));
if (fabs(area) < EPSILON) // abs() for integer, fabs() for float, double
printf("\nA(%g, %g), B(%g, %g) and C(%g, %g) points fall on one straight line.", x1, y1, x2, y2, x3, y3);
else
printf("\nA(%g, %g), B(%g, %g) and C(%g, %g) points doesn't fall on one straight line.", x1, y1, x2, y2, x3, y3);
return 0;
}
luc016.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Given the coordiantes (x, y) of center of a circle and its radius,
write a program that will determine whether a point lies inside the circle,
on the circle or outside the circle. (Hint : Use sqrt() and pow() functions.) */
/* Let Us C, Chap- 3, Page - 53, Qn No.: f(g) */
#include <stdio.h>
#include <math.h>
// Define a small tolerance value (EPSILON) for reliable floating-point comparison
#define EPSILON 0.0001
int main()
{
double h, k;
double R;
double x, y;
double distance_sq;
printf("Enter the center coordinates (h, k) : ");
scanf("%lf %lf", &h, &k);
printf("Enter the radius (R) : ");
scanf("%lf", &R);
printf("Enter the point P coordinates (x, y) : ");
scanf("%lf %lf", &x, &y);
distance_sq = pow(x - h, 2) + pow(y - k, 2);
double radius_sq = R * R;
// Case 1: On the circle (D^2 = R^2) - Use EPSILON for safety!
if (fabs(distance_sq - radius_sq) < EPSILON)
{
printf("The point P(%g, %g) lies ON THE CIRCLE.\n", x, y);
}
// Case 2: Inside the circle (D^2 < R^2)
else if (distance_sq < radius_sq)
{
printf("The point P(%g, %g) lies INSIDE THE CIRCLE.\n", x, y);
}
// Case 3: Outside the circle (D^2 > R^2)
else
{
printf("The point P(%g, %g) lies OUTSIDE THE CIRCLE.\n", x, y);
}
return 0;
}
luc017.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Given a point (x, y), write a program to find out if it lies on X-axis, Y-axis or origin. */
/* Let Us C, Chap- 3, Page - 53, Qn No.: f(h) */
#include <stdio.h>
#include <math.h>
#define EPSILON 0.00001
int main()
{
double x, y;
printf("Enter the point P(x, y) : ");
scanf("%lf %lf", &x, &y);
if (fabs(x) < EPSILON && fabs(y) < EPSILON)
printf("\nPoint P(%g, %g) lies on the origin.", x, y);
else if (fabs(x) < EPSILON)
printf("\nPoint P(%g, %g) lies on the Y-Axis.", x, y);
else if (fabs(y) < EPSILON)
printf("\nPoint P(%G, %g) lies on the X-Axis.", x, y);
else
printf("\nThe point P(%g, %g) lies in a QUADRANT (not on an axis or the origin).", x, y);
return 0;
}
luc018-logic.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* According to Gregorian calender, it was Monday on the date 01/01/01.
Write a program to find out what is the day on 1st January of any input year. */
/* Let Us C, Chap- 3, Page - 53, Qn No.: f(i) */
#include <stdio.h>
/**
* @brief Determines if a given year is a leap year.
* * The rule: A year is a leap year if it is divisible by 4, UNLESS it is
* divisible by 100 but NOT by 400.
* * @param year The year to check.
* @return 1 if it is a leap year, 0 otherwise.
*/
int is_leap(int year) {
// Check if divisible by 400 OR (divisible by 4 AND not divisible by 100)
if ((year % 400 == 0) || (year % 4 == 0 && year % 100 != 0)) {
return 1;
}
return 0;
}
/**
* @brief Calculates the day of the week for January 1st of the given year.
* * The base date is 01/01/01, which was a Monday (index 1).
* * Day Mapping: 0:Sunday, 1:Monday, 2:Tuesday, 3:Wednesday, 4:Thursday, 5:Friday, 6:Saturday
*/
int main() {
long long year; // Use long long for year input if years far in the future/past are tested
int i;
long long total_days = 0;
int day_index;
// Day names array for output
const char *day_names[] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};
printf("Enter the year (e.g., 2025): ");
if (scanf("%lld", &year) != 1 || year < 1) {
printf("Invalid year input. Please enter a positive integer year (>= 1).\n");
return 1;
}
// --- Core Logic: Calculate Total Days ---
// We only need to consider the years that have *passed* before the target year.
// So, we count days from the end of year 0 up to the end of year (year - 1).
int years_passed = year - 1;
// 1. Calculate the number of leap days up to the end of year (year - 1)
// Formula based on Gregorian calendar rules for years Y-1:
// (Y-1)/4 - (Y-1)/100 + (Y-1)/400
long long leap_years = years_passed / 4 - years_passed / 100 + years_passed / 400;
// 2. Total days = (Number of years * 365) + (Number of leap years)
// Note: The loop method (below) is more intuitive but the formula is faster.
// We will use the direct formula for efficiency.
total_days = years_passed * 365 + leap_years;
// --- Alternate Loop Method (for conceptual simplicity) ---
/*
for (i = 1; i < year; i++) {
total_days += 365;
if (is_leap(i)) {
total_days += 1; // Add 1 for the leap day
}
}
*/
// --- Determine the Day of the Week ---
// Since 01/01/01 was Monday (index 1), we use the following setup:
// Index 1 corresponds to Monday.
// The calculation gives the number of days *past* the Monday start (01/01/01).
// The modulo operation gives the remainder (0-6).
// 0 days elapsed (Year 1): total_days=0. (0 + 1) % 7 = 1 (Monday). Correct.
// 365 days elapsed (Year 2): total_days=365. (365 + 1) % 7 = 2 (Tuesday). Correct. (365 mod 7 = 1, 1+1 = 2)
day_index = (total_days + 1) % 7;
// Correct the Day Index to match the array (0:Sun, 1:Mon, ..., 6:Sat)
// The +1 adjusts for the Monday starting point (index 1).
printf("\nOn January 1st, %lld, the day was: **%s**.\n", year, day_names[day_index]);
return 0;
}
luc018.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* According to Gregorian calender, it was Monday on the date 01/01/01.
if any year is input through the keyboard write a program to find out
what is the day on 1st January of this year. */
/* Let Us C, Chap- 3, Page - 53, Qn No.: f(i) */
#include <stdio.h>
int is_leap(int year) {
if ((year % 400 == 0) || (year % 4 == 0 && year % 100 != 0)) {
return 1;
}
return 0;
}
int main() {
long long year; // long long for year input if years far in the future/past are tested
int i;
long long total_days = 0;
int day_index;
// Day names array for output
const char *day_names[] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};
printf("Enter the year (e.g., 2025): ");
if (scanf("%lld", &year) != 1 || year < 1) {
printf("Invalid year input. Please enter a positive integer year (>= 1).\n");
return 1;
}
int years_passed = year - 1;
long long leap_years = years_passed / 4 - years_passed / 100 + years_passed / 400;
total_days = years_passed * 365 + leap_years;
day_index = (total_days + 1) % 7;
printf("\nOn January 1st, %lld, the day was: %s.\n", year, day_names[day_index]);
return 0;
}
luc019.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* If the length of three sides of a triangle are entered through the
keyboard, write a program to check whether the triangle is an isosceles,
an equilateral, a scalene or a right-angled triangle. */
/* Let Us C, Chap- 4, Page - 71, Qn No.: D(a) */
#include <stdio.h>
#include <math.h>
#define EPSILON 0.000001
/* EPSILON is used to compare double values for approximate equality,
mitigating floating-point precision errors. */
int main()
{
double side1, side2, side3;
printf("Please enter the length of three side of the triangle : ");
scanf("%lf %lf %lf", &side1, &side2, &side3);
if (side1 < 1 || side2 < 1 || side3 < 1)
{
printf("\nLength of a side of triangle should be a positive integer.");
return 1;
}
if (side1 + side2 < side3 || side1 + side3 < side2 || side2 + side3 < side1)
{
printf("\nEntered triangle is not VALID.");
return 1;
}
// isosceles check
if (side1 == side2 || side2 == side3 || side3 == side1)
printf("\nEntered triangle is a ISOSCELES triangle.");
else
printf("\nEntered triangle is NOT a ISOSCELES triangle.");
// equilateral check
if (side1 == side2 && side2 == side3)
printf("\nEntered triangle is a EQUILATERAL triangle.");
else
printf("\nEntered triangle is NOT a EQUILATERAL triangle.");
// scalene check
if (side1 != side2 && side2 != side3)
printf("\nEntered triangle is a SCALENE triangle.");
else
printf("\nEntered triangle is NOT a SCALENE triangle.");
// right-angle check
if (fabs(((side1 * side1) + (side2 * side2)) - (side3 * side3)) < EPSILON ||
fabs(((side2 * side2) + (side3 * side3)) - (side1 * side1)) < EPSILON ||
fabs(((side3 * side3) + (side1 * side1)) - (side2 * side2)) < EPSILON)
printf("\nEntered triangle is a RIGHT-ANGLED triangle.");
else
printf("\nEntered triangle is NOT a RIGHT-ANGLED triangle.");
return 0;
}
luc020.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* In digital world colors are specified in Red-Green-Blue (RGB) format,
with values of R, G, B varying on an integer scale from 0 to 255. In print
publishing the colors are mentioned in Cyan-Magenta-Yellow-Black (CMYK) format,
with values of C, M, Y, and K varying on a real scale from 0.0 to 1.0.
Write a program that converts RGB color to CMYK color as per the following formulae:
White = Max(Red/255, Green/255, Blue/255)
Cyan = (White-Red/255) / White
Magenta = (White-Green/255) / White
Yellow = (White-Blue/255) / White
Black = 1 - White
Note that if the RGB values are all 0, then the CMY values are all 0 and the K value is 1. */
/* Let Us C, Chap- 4, Page - 71, Qn No.: D(b) */
#include <stdio.h>
// declaring function
double get_white(double red, double green, double blue)
{
double max;
max = red / 255;
if (max < (green / 255))
max = green / 255;
if (max < (blue / 255))
max = blue / 255;
return max;
}
int main()
{
double r, g, b, w, c = 0, m = 0, y = 0, k = 0;
printf("Enter the RGB color code in 'R G B' format : ");
scanf("%lf %lf %lf", &r, &g, &b);
// checking for invalid input (negetive input)
if (r < 0 || g < 0 || b < 0)
{
printf("\nRGB color code can not be a negetive number.");
return 1;
}
// checking for invalid input (out of range color code)
if (r > 255 || g > 255 || b > 255)
{
printf("\nRGB color code can be maximum (255, 255, 255).");
return 1;
}
// converting RGB color code to CMYK color code
if (r == 0 && g == 0 && b == 0)
k = 1;
else
{
w = get_white(r, g, b);
c = (w - (r / 255)) / w;
m = (w - (g / 255)) / w;
y = (w - (b / 255)) / w;
k = 1 - w;
}
printf("\nRGB color (%g, %g, %g) equivalent to CMYK color (%g, %g, %g, %g).", r, g, b, c, m, y, k);
return 0;
}
luc021.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* A certain grade of steel is graded according to the following conditions:
(i) Hardness must be greater than 50
(ii) Carbon content must be less than 0.7
(iii) Tensile strength must be greater than 5600
The grades are as follows:
Grade is 10 if all three conditions are met
Grade is 9 if conditions (i) and (ii) are met
Grade is 8 if conditions (ii) and (iii) are met
Grade is 7 if conditions (i) and (iii) are met
Grade is 6 if only one condition is met
Grade is 5 if none of the conditions are met
Write a program, which will require the user to give values of hardness,
carbon content and tensile strength of the steel under consideration and output
the grade of the steel. */
/* Let Us C, Chap- 4, Page - 71, Qn No.: D(c) */
#include <stdio.h>
int main()
{
double hardness, carbon_content, tensile_strength;
printf("Enter the details of the steel below - \n");
printf("1. Hardness : ");
scanf("%lf", &hardness);
printf("2. Carbon Content : ");
scanf("%lf", &carbon_content);
printf("3. Tensile Strength : ");
scanf("%lf", &tensile_strength);
// storing how many conditions are met as boolean result
int condition_met, condition1, condition2, condition3;
condition1 = hardness > 50;
condition2 = carbon_content < 0.7;
condition3 = tensile_strength > 5600;
condition_met = condition1 + condition2 + condition3;
// now grading according the result
int grade;
if (condition_met == 3)
grade = 10;
else if (condition_met == 2)
{
if (condition1 && condition2)
grade = 9;
else if (condition2 && condition3)
grade = 8;
else if (condition1 && condition3)
grade = 7;
}
else if (condition_met == 1)
grade = 6;
else
grade = 5;
// printing the result
printf("\n------------- Result -------------");
printf("\n1. Hardness : Condition %s", condition1 ? "MET" : "DID NOT MET");
printf("\n2. Carbon Content : Condition %s", condition2 ? "MET" : "DID NOT MET");
printf("\n3. Tensile Strength : Condition %s", condition3 ? "MET" : "DID NOT MET");
printf("\nTotal Condition Met : %d", condition_met);
printf("\n\nGrade : %d\n\n", grade);
return 0;
}
/* I did not used this long variable names. I used very short just the first letter of the word.
After writting the whole program, I just renamed the valiables. This is possible in Visual Stdio Code. */
luc022.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* The Body Mass Index (BMI) is defined as ratio of weight of the
person (in Kilograms) to square of the height (in meters).
Write a program that receives weight and height, calculate the BMI, and reports
the BMI catagory as per the following table.
BMI Catagory BMI
Starvation < 15
Anorexic 15.1 to 17.5
Underweight 17.6 to 18.5
Ideal 18.6 to 24.9
Overweight 25 to 25.9
Obese 30 to 39.9
Morbidly Obese >= 40
*/
/* Let Us C, Chap- 4, Page - 72, Qn No.: D(d) */
#include <stdio.h>
int main()
{
double weight, height, bmi;
printf("Enter your Weight (in Kilograms) and Height (in Meters) : ");
scanf("%lf %lf", &weight, &height);
bmi = weight / (height * height);
printf("\nCalculated BMI : %g", bmi);
if (bmi < 15)
printf("\nBMI Catagory : Starvation");
else if (bmi >= 15.1 && bmi <= 17.5)
printf("\nBMI Catagory : Anorexic");
else if (bmi >= 17.6 && bmi <= 18.5)
printf("\nBMI Catagory : Underweight");
else if (bmi >= 18.6 && bmi <= 24.9)
printf("\nBMI Catagory : Ideal");
else if (bmi >= 25 && bmi <= 25.9)
printf("\nBMI Catagory : Overweight");
else if (bmi >= 30 && bmi <= 39.9)
printf("\nBMI Catagory : Obese");
else if (bmi >= 40)
printf("\nBMI Catagory : Morbidly Obese");
else
printf("\nBMI Catagory : Unclassified");
return 0;
}
luc023.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Using conditional operators determine :
(1) Whether the character entered through the keyboard is a
lower case alphabet or not.
(2) Whether a character entered through the keyboard is a special
symbol or not. */
/* Let Us C, Chap- 4, Page - 72, Qn No.: E(a) */
#include <stdio.h>
int main()
{
char inp;
printf("Enter the character : ");
scanf("%c", &inp);
printf("\nInput Character '%c' is %s a LOWER CASE ALPHABET.", inp,
(inp >= 'a' && inp <= 'z') ? "" : "NOT");
printf("\nInput Character '%c' is %s a SPECIAL SYMBOL.", inp,
(inp >= 'a' && inp <= 'z' || inp >= 'A' && inp <= 'Z'
|| inp >= '0' && inp <= '9') ? "NOT" : "");
return 0;
}
luc024.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program using conditional operators to determine whether
a year entered through the keyboard is a leap year or not. */
/* Let Us C, Chap- 4, Page - 72, Qn No.: E(b) */
#include <stdio.h>
int main()
{
int year;
printf("Enter the year : ");
scanf("%d", &year);
printf("\nYear %d is %s a Leapyear.", year, (year % 400 == 0 || year % 4 == 0 && year % 100 != 0) ? "" : "NOT");
return 0;
}
luc025.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to find the greates of the three numbers entered
through the keyboard. Use conditional operators. */
/* Let Us C, Chap- 4, Page - 72, Qn No.: E(c) */
#include <stdio.h>
int main()
{
double num1, num2, num3, max;
printf("Enter three number : ");
scanf("%lf %lf %lf", &num1, &num2, &num3);
printf("\nGreatest of the three number '%g', '%g' and '%g' is : '%g'", num1, num2, num3,
(num1 > num2 && num1 > num3) ? num1 : ((num2 > num1 && num2 > num3) ? num2 : num3));
return 0;
}
luc026.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to recieve value of an angle in degreesand check
whether sum of squares of sine and cosine of this angle is equal to 1. */
/* Let Us C, Chap- 4, Page - 73, Qn No.: E(d) */
#include <stdio.h>
#include <math.h>
#define EPSILON 0.0000001
int main()
{
double angle, result;
printf("Enter the angle value in degree : ");
// checking if the input is other than number.
if(scanf("%lf", &angle) != 1) {
printf("\nPlease enter a number.");
return 1;
}
angle = angle * (M_PI / 180); // converting degree to radian
result = pow(sin(angle), 2) + pow(cos(angle), 2);
(fabs(result - 1.0) < EPSILON) ?
printf("\nsum of squares of sine and cosine of this angle is equal to 1.") :
printf("\nsum of squares of sine and cosine of this angle is NOT equal to 1.");
return 0;
}
luc027.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Rewrite the folowing program using conditional operations
#include<stdio.h>
int main()
{
float sal;
printf("Enter the salary");
scanf("%f", &sal);
if(sal >= 25000 && sal <= 40000)
printf("Manager\n");
else
if(sal >= 15000 && sal < 25000)
printf("Accountant\n");
else
printf("Clerk\n");
return 0;
}
*/
/* Let Us C, Chap- 4, Page - 73, Qn No.: E(e) */
#include <stdio.h>
int main()
{
float sal;
printf("Enter the salary");
scanf("%f", &sal);
(sal >= 25000 && sal <= 40000) ? printf("Manager\n") :
((sal >= 15000 && sal < 25000) ? printf("Accountant\n") : printf("Clerk\n"));
return 0;
}
luc028.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to print all the ASCII values and their equivalent
characters using a while loop. The ASCII may vary from 0 to 255. */
/* Let Us C, Chap- 5, Page - 87, Qn No.: B(a) */
#include <stdio.h>
int main()
{
int i = 0;
printf("ASCII Value\tCharacter");
printf("\n-----------\t---------\n");
while (i <= 255)
{
printf("%d.\t%c\n\n", i, i);
i++;
}
return 0;
}
luc029.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to print out all Armstrong numbers between 100
and 500. If sum of cubes of each digit of the number is equal to the
number itself, then the number is called an Armstrong number. For
example, 153 = (1 * 1 * 1) + (5 * 5 * 5) + (3 * 3 * 3) */
/* Let Us C, Chap- 5, Page - 87, Qn No.: B(b) */
#include <stdio.h>
#include <math.h>
int main()
{
int num = 100, temp1, temp2, res;
printf("Armstrong numbers between 100 and 500 :");
while (num <= 500)
{
temp1 = num;
res = 0;
while (temp1 != 0)
{
temp2 = temp1 % 10;
res = res + pow(temp2, 3);
temp1 = temp1 / 10;
}
if (num == res)
printf(" %d", num);
num++;
}
return 0;
}
luc030.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program for a matchstick game being played between the
computer and a user. Your program should ensure that the computer
always wins. Rules for the game are as follows :
- There are 21 matchsticks.
- The computer asks the player to pick 1, 2, 3, or 4 matchsticks.
- After the person picks, the computer does its picking.
- Whoever is forced to pick up the last matchstick loses the game.
*/
/* Let Us C, Chap- 5, Page - 87, Qn No.: B(c) */
/* My Plan: The total number of matchsticks is 21. To guarantee a win,
the computer ensures that after its turn, the number of remaining
matchsticks is always a multiple of 5 plus 1 (i.e., 16, 11, 6, 1).
This is achieved by making the sum of the player's pick and the
computer's pick equal to 5 in each round. This forces the player
to pick the final matchstick. */
#include <stdio.h>
int main()
{
int remaining_matchsticks = 21, player_pick, computer_pick;
printf(" --- Matchstick Game ---\n");
printf("Rules: There are 21 matchsticks. You can pick 1, 2, 3, or 4.\n");
printf("Whoever is forced to pick the last matchstick loses the game.\n");
while (remaining_matchsticks > 1)
{
// game start
printf("\n--------------------------");
printf("\nRemaining Matchsticks : %d", remaining_matchsticks);
// player pick and checking input is valid or not
printf("\nYour turn: Pick 1, 2, 3, or 4 matchsticks: ");
if (scanf("%d", &player_pick) != 1)
{
printf("\n\tPlease enter a number.");
while (getchar() != '\n')
;
continue;
}
// checking player pick is valid or not
if (player_pick < 1 || player_pick > 4)
{
printf("\n\tPlease enter a number among 1, 2, 3 and 4.");
while (getchar() != '\n')
;
continue;
}
if (player_pick > remaining_matchsticks)
{
printf("\nInvalid choice! There are not enough matchsticks left.");
while (getchar() != '\n')
;
continue;
}
// computer_picks
computer_pick = 5 - player_pick;
printf("\ncomputer_picks : %d", computer_pick);
// remaining matchsticks
remaining_matchsticks = remaining_matchsticks - (player_pick + computer_pick);
}
// game over
printf("\n----------------------------------\n");
printf("Only 1 matchstick is left.\n");
printf("You are forced to pick the last matchstick. You lose!\n");
printf("The computer wins.\n");
return 0;
}
luc031-logic.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to enter numbers till the user wants. At the end it
should display the count of positive, negative and zeros entered. */
/* Let Us C, Chap- 5, Page - 87, Qn No.: B(d) */
/*
* DETAILED PROGRAM PLAN:
* 1. INITIALIZATION: Set three counters (positive_count, negative_count, zero_count) to zero.
* 2. INPUT LOOP: Start an infinite loop to continuously request user input.
* 3. READ INPUT: Use fgets() to read the user's input as a generic string (char array).
* This allows the program to accept multi-digit numbers (e.g., "-500") or the command ('n').
* 4. TERMINATION CHECK: Immediately check if the input string is exactly "n" using strcmp().
* If true, the user wants to quit, so break the loop.
* 5. VALIDATION & CONVERSION: If the input is not "n", use sscanf() to safely attempt to convert
* the string into an integer.
* 6. COUNTING LOGIC: If sscanf() successfully reads an integer (sscanf returns 1):
* - If the number is > 0, increment positive_count.
* - If the number is < 0, increment negative_count.
* - If the number is == 0, increment zero_count.
* 7. ERROR HANDLING: If the input is neither "n" nor a valid number (sscanf returns 0),
* inform the user of invalid input and continue the loop.
* 8. FINAL DISPLAY: After the loop terminates, print the final totals for positive, negative, and zero counts.
*/
#include <stdio.h>
#include <stdlib.h> // for strtol
#include <string.h> // for strcmp
// Maximum size of the input line
#define MAX_INPUT_LEN 15
int main() {
// Initialize counters
int positive_count = 0;
int negative_count = 0;
int zero_count = 0;
// Buffer to store the user's input as a string (e.g., "123", "-50", or "n")
char input_buffer[MAX_INPUT_LEN];
int number;
printf("--- Number Analyzer ---\n");
printf("Enter numbers one by one. Type 'n' and press Enter to finish.\n\n");
// Loop until the user enters 'n'
while (1) {
printf("Enter number or 'n': ");
// Read the entire line of input into the buffer
if (fgets(input_buffer, MAX_INPUT_LEN, stdin) == NULL) {
// Handle EOF (end of file) or reading error
break;
}
// Remove the trailing newline character from the input_buffer
// The last character will be '\n' if the input was shorter than MAX_INPUT_LEN
size_t len = strlen(input_buffer);
if (len > 0 && input_buffer[len - 1] == '\n') {
input_buffer[len - 1] = '\0';
}
// 1. Check for the termination condition
if (strcmp(input_buffer, "n") == 0) {
printf("\n'n' received. Stopping input...\n");
break; // Exit the while loop
}
// 2. Attempt to convert the input string to an integer
// sscanf attempts to read the string according to the format "%d" (decimal integer)
// It returns 1 if a number was successfully read.
int conversions = sscanf(input_buffer, "%d", &number);
if (conversions == 1) {
// Conversion was successful, now check the number's sign
if (number > 0) {
positive_count++;
} else if (number < 0) {
negative_count++;
} else {
zero_count++;
}
printf(" -> Number recorded: %d\n", number);
} else {
// Conversion failed. The input was neither 'n' nor a valid integer.
printf(" -> Invalid input. Please enter a valid number or 'n'.\n");
}
}
// Display the final results
printf("\n====================================\n");
printf(" Analysis Complete\n");
printf("====================================\n");
printf("Positive numbers entered: %d\n", positive_count);
printf("Negative numbers entered: %d\n", negative_count);
printf("Zeroes entered: %d\n", zero_count);
printf("Total numbers recorded: %d\n", positive_count + negative_count + zero_count);
printf("====================================\n");
return 0;
}
luc031.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to enter numbers till the user wants. At the end it
should display the count of positive, negative and zeros entered. */
/* Let Us C, Chap- 5, Page - 87, Qn No.: B(d) */
#include <stdio.h>
int main()
{
int choice = 1, num, positive_count = 0, negative_count = 0, zero_count = 0;
while (choice == 1)
{
printf("\nEnter the number (Type any character and press Enter to finish.) : ");
choice = scanf("%d", &num); // Checking whether the user has input any characters
if (choice == 1)
{
printf("Number recorded : %d", num);
if (num < 0)
negative_count++;
else if (num > 0)
positive_count++;
else if (num == 0)
zero_count++;
}
else
{
// If the user inputs any characters, then choice = 0, it means he doesn't want to give any more input;
choice = 0;
printf("\nCharacter received. Stopping input...\n");
}
}
// Display the final results
printf("\n====================================\n");
printf(" Analysis Complete\n");
printf("====================================\n");
printf("Positive numbers entered: %d\n", positive_count);
printf("Negative numbers entered: %d\n", negative_count);
printf("Zeroes entered: %d\n", zero_count);
printf("Total numbers recorded: %d\n", positive_count + negative_count + zero_count);
printf("====================================\n");
}
luc032.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to recieve an integer and find its octal equivalent.
(Hint : To obtain octal equivalent of an integer, Divide it continuously
by 8 till dividend does not become zero, then write the remainders
obtained in reverse derection.) */
/* Let Us C, Chap- 5, Page - 87, Qn No.: B(e) */
// using array
#include <stdio.h>
int main()
{
int octal[20], decimal, index = 0, temp, rem;
printf("Enter the decimal number : ");
scanf("%d", &decimal);
temp = decimal;
while (temp != 0)
{
rem = temp % 8;
temp = temp / 8;
octal[index] = rem;
index++;
}
printf("\nDeciaml %d to octal : ", decimal);
while ((index - 1) >= 0)
{
printf("%d", octal[index - 1]);
index--;
}
return 0;
}
luc033.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to find the range of a set of numbers entered
through the keyboard. Range is the difference between the smallest
and biggest number in the list. */
/* Let Us C, Chap- 5, Page - 87, Qn No.: B(f) */
#include <stdio.h>
int main()
{
int choice = 1, set_of_numbers[30], num, index = -1;
while (choice == 1)
{
printf("\nEnter the number (Type any character and press Enter to finish.) : ");
choice = scanf("%d", &num); // Checking whether the user has input any characters
if (choice != 1)
{
// If the user inputs any characters, then choice = 0, it means he doesn't want to give any more input;
choice = 0;
printf("\nCharacter received. Stopping input...\n");
break;
}
index++;
set_of_numbers[index] = num;
}
int max = set_of_numbers[0], min = set_of_numbers[0];
while (index >= 0)
{
if (max < set_of_numbers[index])
max = set_of_numbers[index];
if (min > set_of_numbers[index])
min = set_of_numbers[index];
index--;
}
int range = max - min;
printf("\nBiggest number in the set : %d", max);
printf("\nSmallest number in the set : %d", min);
printf("\nRange : %d", range);
return 0;
}
luc034.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to print the multiplication table of the number
entered by the user. The table should get displayed in the following
form :
29 * 1 = 29
29 * 2 = 58
*/
/* Let Us C, Chap- 6, Page - 105, Qn No.: B(a) */
#include <stdio.h>
int main()
{
int i, num, res;
printf("Enter the number : ");
scanf("%d", &num);
printf("\n--- Multiplication Table ---\n");
for (i = 1; i <= 10; i++)
printf("%d * %d = %d\n", num, i, num * i);
return 0;
}
luc035.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* According to a study, the approximate level of intelligence of a
person can be calculated using the following formula.
i = 2 + (y + 0.5x)
write a program that will produce a table of values of i, y and x,
where y varies from 1 to 6, and, for each value of y, x varies from
5.5 to 12.5 in steps of 0.5 */
/* Let Us C, Chap- 6, Page - 105, Qn No.: B(b) */
#include <stdio.h>
int main()
{
double y, x;
printf("\n--- Approximate Intelligence ---\n");
for (y = 1; y <= 6; y++)
{
printf("\tY = %d\n", y);
for (x = 5.5; x <= 12.5; x += 0.5)
{
printf("Y: %g\t X: %.2g\t I: %g\n", y, x, 2 + (y + 0.5 * x));
}
printf("-----------------------\n");
}
return 0;
}
luc036.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* When interest compounds q times per year at an annual rate of
r % for n years, the principle p compounds to an amount a as per
the following formula
a = p (1 + r / q) ^ nq
Write a program to read 10 sets of p, r, n & q and calculate the
corresponding as' */
/* Let Us C, Chap- 6, Page - 106, Qn No.: B(c) */
// DEVELOPMENT STATUS: This implementation is currently untested.
// Please report any functional defects or errors by submitting a GitHub issue "https://github.com/notamitgamer/bsc/issues" with the updated code.
#include <stdio.h>
#include <math.h>
int main()
{
double interest, principalAmount, interestRate, timeInYears, compoundFactor, totalAmount;
int index;
for (index = 1; index <= 10; index++)
{
printf("Enter Principle amount : ");
scanf("%lf", &principalAmount);
printf("Enter Rate of Interest : ");
scanf("%lf", &interestRate);
interestRate *= 0.01;
printf("Enter the Time (Years) : ");
scanf("%lf", &timeInYears);
printf("Compound count in one year : ");
scanf("%lf", &compoundFactor);
totalAmount = (principalAmount * pow((1 + interestRate / compoundFactor), (timeInYears * compoundFactor)));
interest = totalAmount - principalAmount;
printf("\nInterest : %.2f\nTotal Amount : %.2f\n\n", interest, totalAmount);
}
return 0;
}
luc037.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* The natural logarithm can be approximated by the following series.
(x-1)/x + 1/2 ((x-1)/x)^2 + 1/2 ((x-1)/x)^3 + 1/2 ((x-1)/x)^4 + ...
If x is input through the keyboard, write a program to calculate the
sum of the first seven terms of this series. */
/* Let Us C, Chap- 6, Page - 106, Qn No.: B(d) */
#include <stdio.h>
#include <math.h>
double series(double x) // made this fn only for fun, making a fn was not necessary
{
double result = (x - 1) / x;
int i;
for (i = 2; i <= 7; i++)
{
result += 0.5 * pow(((x - 1) / x), i);
}
return result;
}
int main()
{
double x;
printf("Enter the value for x : ");
scanf("%lf", &x);
printf("\nResult : %g", series(x));
return 0;
}
luc038.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to generate all Pythagorean Triplets with slide
length less than or equal to 30. */
/* Let Us C, Chap- 6, Page - 106, Qn No.: B(e) */
#include <stdio.h>
#include <math.h>
int main()
{
int a, b, c;
printf("Pythagorean Triplets with slide length less than or equal to 30 : \n");
for (a = 1; a <= 30; a++)
{
for (b = a; b <= 30; b++)
{
int c_square = a * a + b * b;
for (c = b + 1; c <= 30; c++)
{
if (c * c == c_square)
printf("(%d, %d, %d)\n", a, b, c);
}
}
}
return 0;
}
luc039.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Population of a town today is 100000. The population has increased
steadily at the rate of 10% per year for last 10 years. Write a
program to determine the population at the end of each year in the
last decade. */
/* Let Us C, Chap- 6, Page - 106, Qn No.: B(f) */
#include <stdio.h>
int main()
{
int i, population = 100000;
printf("Present year : %d\n", population);
for (i = 1; i <= 10; i++)
{
population /= 1.10;
printf("%d year ago : %d\n", i, population);
}
return 0;
}
luc040-logic.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Ramanujan number (1729) is the smallest number that can be
expressed as sum of cubes in two different ways - 1729 can be
expressed as 1^3 + 12^3 and 9^3 + 10^3. Write a program to print all such
numbers up to a reasonable limit. */
/* Let Us C, Chap- 6, Page - 106, Qn No.: B(g) */
// 1. INCLUDE SECTION
#include <stdio.h> // Includes the standard input/output library, necessary for printf()
// 2. CONSTANT DEFINITIONS (MACROS)
// These define fixed values we can easily use and change later.
#define LIMIT 100000 // The maximum number we want to search up to.
// The maximum base value (a, b, c, or d) we need to check.
// Since 47^3 is greater than 100,000, checking bases up to 47 covers the LIMIT.
#define MAX_BASE_VAL 47
// 3. MAIN FUNCTION
int main()
{
// 4. VARIABLE DECLARATION
// sum1 and sum2 store the results of a^3 + b^3 and c^3 + d^3.
// We use 'long long' because cubes (like 47^3) are large and can exceed
// the capacity of a standard 'int', preventing errors.
long long sum1, sum2;
int count = 0; // Counter to keep track of how many Ramanujan numbers we find.
// This flag is used to optimize the search. If we find the second way (c^3 + d^3)
// to make sum1, we set this to 1 and immediately stop the inner loops.
int found_match;
// Print introductory message to the user.
printf("Ramanujan Number Finder (a^3 + b^3 = c^3 + d^3)\n");
printf("Searching up to %d (Max base value is %d)\n", LIMIT, MAX_BASE_VAL);
printf("---------------------------------------------------\n");
// 5. OUTER LOOPS: Establishing the FIRST SUM (a^3 + b^3 = sum1)
// Loop for 'a' (the smaller base of the first pair)
for (int a = 1; a <= MAX_BASE_VAL; a++)
{
// Loop for 'b' (the larger base of the first pair)
// We start 'b' at 'a + 1' to enforce the rule a < b.
// This prevents us from checking redundant pairs like (1, 12) and (12, 1).
for (int b = a + 1; b <= MAX_BASE_VAL; b++)
{
// Calculate the first sum: sum1 = a^3 + b^3
// (long long) is a cast to ensure the math is done using the 'long long' type.
sum1 = (long long)a * a * a + (long long)b * b * b;
// Optimization 1: Check if the sum exceeds the global limit.
if (sum1 > LIMIT)
{
// Since 'b' is increasing, any further increase will also be over the limit.
// We stop the 'b' loop and move to the next 'a'.
break;
}
// Reset the flag for every new sum1.
// We start searching for a second way for this new 'sum1', so we reset the flag to 0.
found_match = 0;
// 6. INNER LOOPS: Searching for the SECOND SUM (c^3 + d^3 = sum2)
// Loop for 'c' (the smaller base of the second pair)
// We start 'c' at 'a + 1' to enforce the rule a < c.
// This ensures the two pairs {(a, b) and (c, d)} are truly distinct (e.g., 1729 = 1^3 + 12^3 and 9^3 + 10^3).
for (int c = a + 1; c <= MAX_BASE_VAL; c++)
{
// Optimization 2: Check the flag to exit the 'c' loop early.
if (found_match)
{
// If we already found the second way (c, d) in a previous iteration of 'c', stop searching and move to the next (a, b) pair.
break;
}
// Loop for 'd' (the larger base of the second pair)
// We start 'd' at 'c + 1' to enforce c < d.
for (int d = c + 1; d <= MAX_BASE_VAL; d++)
{
// Calculate the second sum: sum2 = c^3 + d^3
sum2 = (long long)c * c * c + (long long)d * d * d;
// Optimization 3: Check if the second sum has passed the first sum.
if (sum2 > sum1)
{
// Since 'd' is increasing, any further increase will also be greater than sum1.
// We stop the 'd' loop and move to the next 'c'.
break;
}
// 7. CONDITION CHECK: Have we found a Ramanujan number?
// Check if the two sums are equal.
if (sum1 == sum2)
{
count++; // Increment the counter
// Print the result in the required format.
printf("[%d] %lld = %d^3 + %d^3 = %d^3 + %d^3\n",
count, sum1, a, b, c, d);
// Set the flag to 1, confirming we found the second way.
found_match = 1;
// Stop the 'd' loop immediately, as we found the required second pair.
break;
}
}
// If found_match was set to 1, the 'break' in the d loop will execute,
// then the 'if (found_match) break;' in the c loop will execute,
// and the program will move to the next (a, b) pair.
}
}
}
// 8. CONCLUSION
printf("---------------------------------------------------\n");
printf("Search complete. Found %d Ramanujan-type numbers.\n", count);
return 0; // Standard way to indicate successful program execution.
}
luc040.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Ramanujan number (1729) is the smallest number that can be
expressed as sum of cubes in two different ways - 1729 can be
expressed as 1^3 + 12^3 and 9^3 + 10^3. Write a program to print all such
numbers up to a reasonable limit. */
/* Let Us C, Chap- 6, Page - 106, Qn No.: B(g) */
#include <stdio.h>
#define limit 100000
#define max_base 47
int main()
{
long long sum1, sum2;
int count = 0;
printf("Ramanujan numbers : \n");
int found_match;
for (int a = 1; a <= max_base; a++)
{
for (int b = a + 1; b <= max_base; b++)
{
sum1 = (long long)a * a * a + (long long)b * b * b;
if (sum1 > limit)
{
break;
}
found_match = 0;
for (int c = a + 1; c <= max_base; c++)
{
if (found_match)
{
break;
}
for (int d = c + 1; d <= max_base; d++)
{
sum2 = (long long)c * c * c + (long long)d * d * d;
if (sum2 > sum1)
{
break;
}
if (sum1 == sum2)
{
count++;
printf("(%d.) %lld = %d^3 + %d^3 = %d^3 + %d^3\n", count, sum1, a, b, c, d);
found_match = 1;
break;
}
}
}
}
}
printf("-------------------------------\n");
printf("Search complete.");
return 0;
}
luc041.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to print 24 hours of day with suitable suffixes like
AM, PM, Noon and Midnight. */
/* Let Us C, Chap- 6, Page - 106, Qn No.: B(h) */
#include <stdio.h>
int main()
{
int hour, temp;
printf("Time \tSuffix\n");
for (int hour = 0; hour <= 23; hour++)
{
if (hour == 0)
printf("12:00\tAM (Midnight)\n");
else if (hour == 12)
printf("12:00\tPM (Noon)\n");
else if (hour >= 1 && hour <= 11)
printf("%02d:00\tAM\n", hour);
else if (hour >= 13 && hour <= 23)
printf("%02d:00\tPM\n", hour - 12);
}
return 0;
}
luc042.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to produce the following output :
1
2 3
4 5 6
7 8 9 10
*/
/* Let Us C, Chap- 6, Page - 106, Qn No.: B(i) */
#include <stdio.h>
int main()
{
int starter = 1;
int tab = 3;
printf("The pattern : \n");
for (int i = 1; i <= 4; i++)
{
int count = 0;
for (int k = 1; k <= tab; k++)
{
printf(" ");
}
tab = tab - 1;
for (int j = starter; j <= 10; j++)
{
if (count >= i)
{
break;
}
printf("%d ", j);
count++;
starter++;
}
printf("\n");
}
return 0;
}
luc043.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to find the grace marks for a student using switch.
The user should enter the class obtained by the student and the
number of subjects he has failed in. Use the following logic.
- If the student gets first class and he fails in more than 3
subjects, he does not get any grace, Otherwise, he gets a grace
of 5 marks per subject.
- If the student gets second class and he fails in more than 2
subjects, he does not get any grace. Otherwise, he gets a grace
of 4 marks per subject.
- If the student gets third class and he fails in more than 1
subject, then he does not get any grace. Otherwise, he gets a
grace of 5 marks.
*/
/* Let Us C, Chap- 7, Page - 125, Qn No.: C */
#include <stdio.h>
int main()
{
int studentClass, failedSubjectCount, graceMarks = 0;
printf("Class obtained by the student (Enter 1 for First Class, 2 for Second Class, 3 for Third Class): ");
scanf("%d", &studentClass);
printf("Failed Subject Count: ");
scanf("%d", &failedSubjectCount);
if (failedSubjectCount < 0) {
printf("\nFailed subject count cannot be negative.");
return 1;
}
switch (studentClass)
{
case 1:
if (failedSubjectCount <= 3)
{
graceMarks += 5 * failedSubjectCount;
}
break;
case 2:
if (failedSubjectCount <= 2)
{
graceMarks += 4 * failedSubjectCount;
}
break;
case 3:
if (failedSubjectCount <= 1)
{
graceMarks += 5 * failedSubjectCount;
}
break;
default:
printf("\nWrong Choice.");
return 1;
}
printf("\nStudent will get %d grace marks.", graceMarks);
return 0;
}
luc044.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Any year is entered through the keyboard. Write a function to
determine whether the year is aleap year or not. */
/* Let Us C, Chap- 8, Page - 144, Qn No.: C(1) */
#include <stdio.h>
int leapYear(int);
int leapYear(int year)
{
if ((year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0)))
return 1;
else
return 0;
}
int main()
{
int year;
printf("Enter the year : ");
scanf("%d", &year);
if (leapYear(year))
printf("\nYear %d is a Leap Year.", year);
else
printf("\nYear %d is not a Leap Year.", year);
return 0;
}
luc045.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* A position integer is entered through the keyboard. Write a Function
to obtain the prime factors of this number.
For example, prime factors of 24 are 2, 2, 2 and 3, whereas prime
factors of 35 are 5 and 7
*/
/* Let Us C, Chap- 8, Page - 144, Qn No.: C(2) */
#include <stdio.h>
#include <math.h>
void findPrimeFactors(int n)
{
int temp_n = n;
if (temp_n == 1)
{
printf("Prime factors of %d are: None.\n", n);
return;
}
printf("Prime factors of %d are:", n);
while (temp_n % 2 == 0)
{
printf(" %d", 2);
temp_n = temp_n / 2;
}
for (int i = 3; i <= (int)sqrt(temp_n); i = i + 2)
{
while (temp_n % i == 0)
{
printf(" %d", i);
temp_n = temp_n / i;
}
}
if (temp_n > 2)
{
printf(" %d", temp_n);
}
printf("\n");
}
int main()
{
int n;
printf("Enter a positive integer to get the prime factors: ");
if (scanf("%d", &n) != 1)
{
printf("Error: Invalid input. Please enter an integer.\n");
return 1;
}
if (n <= 0)
{
printf("Error: Please enter a POSITIVE integer.\n");
return 1;
}
findPrimeFactors(n);
return 0;
}
luc046.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Given three variables x, y, z, write a function to circularly shift their
values to right. In other words, if x = 5, y = 8, z = 10, after circular
shift y = 5, z = 8, x = 10. cal the function with variables a, b, c to
circularly shift values.
*/
/* Let Us C, Chap- 9, Page - 163, Qn No.: C(a) */
#include <stdio.h>
void circularShift(int *, int *, int *);
int main()
{
int x = 5, y = 8, z = 10;
printf("--- Before Shift ---\n");
printf("x: %d, y: %d, z: %d", x, y, z);
circularShift(&x, &y, &z);
printf("\n--- After Shift ---\n");
printf("x: %d, y: %d, z: %d", x, y, z);
return 0;
}
void circularShift(int *x, int *y, int *z)
{
int temp = *z;
*z = *y;
*y = *x;
*x = temp;
}
luc047.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Define a function that receives weight of a commodity in kilograms
and returns the equivalent weight in Grams, Tons and pounds. Call
this fuction from main() and print the results in main()
*/
/* Let Us C, Chap- 9, Page - 163, Qn No.: C(b) */
#include <stdio.h>
void convertWeight(double, double *, double *, double *);
int main()
{
double weightGram, weightPound, weightKG, weightTON;
printf("Enter the weight of the comodity in Kilogram(s): ");
scanf("%lf", &weightKG);
convertWeight(weightKG, &weightGram, &weightPound, &weightTON);
printf("\n%g Kilogram(s) = %.04f Gram(s)"
"\n%g Kilogram(s) = %.04f Pound(s)"
"\n%g Kilogram(s) = %.04f TON(s)",
weightKG, weightGram, weightKG, weightPound, weightKG, weightTON);
return 0;
}
void convertWeight(double weightKG, double *weightGram, double *weightPound, double *weightTON)
{
*weightGram = weightKG * 1000.0;
*weightPound = weightKG * 2.2046226218;
*weightTON = weightKG / 1000.0;
}
luc048.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Define a function to compute the distance between two points and
use it to develop another function that will compute the area of the
triangle whose vertices are A(x1, y1), B(x2, y2), and C(x3, y3). Use
these functions to develop a function which returns a value 1 if the
point (x, y) lines inside the triangle ABC, otherwise returns a value
0. Would you get any advantage if you develop these functions to
work on call by reference principle?
*/
/* Let Us C, Chap- 9 (Pointers), Page - 163, Qn No.: C(c) */
#include <stdio.h>
#include <math.h>
#include <ctype.h>
#include <stdlib.h>
void distance(double, double, double, double, double *);
void area(double, double, double, double, double, double, double *);
int is_inside(double, double, double, double, double, double, double, double);
int main()
{
// Variables
double x, y, x1, x2, y1, y2, x3, y3, result_Distance, result_Area;
char choice;
/* ********** Requirement: 1 ********** */
// Calculate the length of the line segment between two points, P1(x1, y1) and P2(x2, y2).
// Function Used: distance()
printf("--- Compute the distance between two points ---\n\n");
printf("Enter the co-ordinates of Point 1 (Ex.: 5,6): ");
scanf("%lf,%lf", &x1, &y1);
printf("Enter the co-ordinates of Point 2 (Ex.: 3,4): ");
scanf("%lf,%lf", &x2, &y2);
distance(x1, y1, x2, y2, &result_Distance);
printf("\nDistance between P1(%g, %g) and P2(%g, %g) = %g",
x1, y1, x2, y2, result_Distance);
/* ********** Requirement: 2 ********** */
// Calculate the area of a triangle ABC using its three vertices A(x1, y1), B(x2, y2), and C(x3, y3).
// Fuction Used: distance(), area()
printf("\n\n--- Compute the area of a triangle ABC ---\n\n");
printf("Enter the co-ordinates of Point A (Ex.: 5,6): ");
scanf("%lf,%lf", &x1, &y1);
printf("Enter the co-ordinates of Point B (Ex.: 3,4): ");
scanf("%lf,%lf", &x2, &y2);
printf("Enter the co-ordinates of Point C (Ex.: 6,7): ");
scanf("%lf,%lf", &x3, &y3);
area(x1, y1, x2, y2, x3, y3, &result_Area);
printf("\nArea of the A(%g, %g), B(%g, %g), C(%g, %g) = %g",
x1, y1, x2, y2, x3, y3, result_Area);
/* ********** Requirement: 3 ********** */
// Check if a test point P(x, y) lies strictly inside the triangle ABC.
// Function Used: distance(), area(), is_inside()
printf("\n\n--- Check if a test point P(x, y) lies strictly inside the triangle ABC ---\n\n");
printf("Do you wish to use previous entered triangle?"
"\nIf Yes, type 'Y'; If No, type 'N': ");
scanf(" %c", &choice);
choice = toupper(choice);
switch (choice)
{
case 'Y':
break;
case 'N':
printf("Enter the co-ordinates of Point A (Ex.: 5,6): ");
scanf("%lf,%lf", &x1, &y1);
printf("Enter the co-ordinates of Point B (Ex.: 3,4): ");
scanf("%lf,%lf", &x2, &y2);
printf("Enter the co-ordinates of Point C (Ex.: 6,7): ");
scanf("%lf,%lf", &x3, &y3);
break;
default:
printf("\nYou entered invalid choice.");
break;
}
printf("Enter the co-ordinates of Test Point (Ex.: 3,5): ");
scanf("%lf,%lf", &x, &y);
if (is_inside(x, y, x1, y1, x2, y2, x3, y3))
printf("\nTest Point (%g, %g) is inside ABC.", x, y);
else
printf("\nTest Point (%g, %g) is not inside ABC.", x, y);
/* ANSWER TO THE QUESTION:
Qn.:
Would you get any advantage if you develop these functions to
work on call by reference principle?
Ans:
NO, there is no advantage, and moreover, that would be a disadvantage.
It introduces unnecessary dereferencing overhead for every operation,
Which is less efficient than reading the simple value copy supplied by Call by Value.
*/
// End of Program
return 0;
}
void distance(double x1, double y1, double x2, double y2, double *result_Distance)
{
*result_Distance = sqrt(pow((x2 - x1), 2) + pow((y2 - y1), 2));
}
void area(double x1, double y1, double x2, double y2, double x3, double y3, double *result_Area)
{
double s, ab, bc, ac;
distance(x1, y1, x2, y2, &ab);
distance(x2, y2, x3, y3, &bc);
distance(x1, y1, x3, y3, &ac);
s = (ab + bc + ac) / 2.0;
double area_sq = s * (s - ab) * (s - bc) * (s - ac);
if (area_sq < 0)
// Handle cases where area_sq is slightly negative due to floating-point errors
*result_Area = 0.0;
else
*result_Area = sqrt(area_sq);
}
int is_inside(double x, double y, double x1, double y1, double x2, double y2, double x3, double y3)
{
double area_ABC, area_PAB, area_PBC, area_PAC;
const double EPSILON = 0.000001;
area(x1, y1, x2, y2, x3, y3, &area_ABC);
area(x, y, x1, y1, x2, y2, &area_PAB);
area(x, y, x2, y2, x3, y3, &area_PBC);
area(x, y, x1, y1, x3, y3, &area_PAC);
double sum_of_sub_areas = area_PAB + area_PBC + area_PAC;
if (fabs(area_ABC - sum_of_sub_areas) < EPSILON)
return 1;
else
return 0;
}
/*
*************** SAMPLE OUTPUT ***************
PS G:\bsc\letusc> ./*.exe
--- Compute the distance between two points ---
Enter the co-ordinates of Point 1 (Ex.: 5,6): 1234.56,7890.12
Enter the co-ordinates of Point 2 (Ex.: 3,4): 1234.56,7891.12
Distance between P1(1234.56, 7890.12) and P2(1234.56, 7891.12) = 1
--- Compute the area of a triangle ABC ---
Enter the co-ordinates of Point A (Ex.: 5,6): 100.10,200.20
Enter the co-ordinates of Point B (Ex.: 3,4): 105.10,200.20
Enter the co-ordinates of Point C (Ex.: 6,7): 100.10,205.20
Area of the A(100.1, 200.2), B(105.1, 200.2), C(100.1, 205.2) = 12.5
--- Check if a test point P(x, y) lies strictly inside the triangle ABC ---
Do you wish to use previous entered triangle?
If Yes, type 'Y'; If No, type 'N': y
Enter the co-ordinates of Test Point (Ex.: 3,5): 101.10,201.20
Test Point (101.1, 201.2) is inside ABC.
*/
luc049.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* A positive integer is entered through the keyboard, write a function to find the binary equivalent of this number:
(1) Without using recursion
(2) Using recursion
*/
/* Let Us C, Chap- 10 (Recursive), Qn No.: B(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int binary_non_rec(int);
void binary_rec(int);
int main()
{
int num, bin;
printf("Enter a positive integer: ");
scanf("%d", &num);
bin = binary_non_rec(num);
printf("Binary (Non-Recursive): %d\n", bin);
printf("Binary (Recursive): ");
binary_rec(num);
printf("\n");
return 0;
}
int binary_non_rec(int n)
{
int rem, i = 1, bin = 0;
while (n != 0)
{
rem = n % 2;
n = n / 2;
bin = bin + rem * i;
i = i * 10;
}
return bin;
}
void binary_rec(int n)
{
if (n > 1)
binary_rec(n / 2);
printf("%d", n % 2);
}
luc050.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a recursive function to obtain the sum of first 25 natural numbers.
*/
/* Let Us C, Chap- 10 (Recursive), Qn No.: B(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int get_sum(int);
int main()
{
int n = 25, sum;
sum = get_sum(n);
printf("Sum of first %d natural numbers is: %d\n", n, sum);
return 0;
}
int get_sum(int n)
{
if (n == 0)
return 0;
else
return n + get_sum(n - 1);
}
luc051.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Tower of Hanoi: Write a program to print out the sequence in which 4 disks should be moved from peg A to peg C using peg B.
*/
/* Let Us C, Chap- 10 (Recursive), Qn No.: B(c) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
void hanoi(int, char, char, char);
int main()
{
int n = 4;
printf("Sequence of moves for %d disks:\n\n", n);
hanoi(n, 'A', 'B', 'C');
return 0;
}
void hanoi(int n, char from_rod, char aux_rod, char to_rod)
{
if (n == 1)
{
printf("Move disk 1 from rod %c to rod %c\n", from_rod, to_rod);
return;
}
hanoi(n - 1, from_rod, to_rod, aux_rod);
printf("Move disk %d from rod %c to rod %c\n", n, from_rod, to_rod);
hanoi(n - 1, aux_rod, from_rod, to_rod);
}
luc052.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* If a macro is not getting expanded as per your expectation, how will you find out how is it being expanded by the preprocessor?
*/
/* Let Us C, Chap- 12 (The C Preprocessor), Qn No.: C(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main()
{
printf("To see how macros are expanded, use the compiler flag '-E'.\n");
printf("Command: gcc -E filename.c\n");
printf("This outputs the file after preprocessing stage.\n");
return 0;
}
luc053.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write macro definitions for: Mean, Absolute value, Uppercase to Lowercase, Biggest of three.
*/
/* Let Us C, Chap- 12 (The C Preprocessor), Qn No.: C(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#define MEAN(x, y) ((x + y) / 2.0)
#define ABS(x) ((x) < 0 ? -(x) : (x))
#define TO_LOWER(x) ((x) >= 'A' && (x) <= 'Z' ? (x) + 32 : (x))
#define MAX(x, y, z) ((x) > (y) ? ((x) > (z) ? (x) : (z)) : ((y) > (z) ? (y) : (z)))
int main()
{
int a, b, c, num;
char ch;
printf("Enter two numbers for Mean: ");
scanf("%d %d", &a, &b);
printf("Mean: %.2f\n\n", MEAN(a, b));
printf("Enter a number for Absolute value: ");
scanf("%d", &num);
printf("Absolute: %d\n\n", ABS(num));
printf("Enter an uppercase character: ");
scanf(" %c", &ch);
printf("Lowercase: %c\n\n", TO_LOWER(ch));
printf("Enter three numbers: ");
scanf("%d %d %d", &a, &b, &c);
printf("Biggest: %d\n", MAX(a, b, c));
return 0;
}
luc054.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Use 'interest.h' macros to calculate Simple Interest and Amount.
*/
/* Let Us C, Chap- 12 (The C Preprocessor), Qn No.: C(c) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include "interest.h"
int main()
{
float p, r, t, si, amt;
printf("Enter Principal, Rate and Time: ");
scanf("%f %f %f", &p, &r, &t);
si = SIMPLE_INTEREST(p, r, t);
amt = AMOUNT(p, si);
printf("Simple Interest: %.2f\n", si);
printf("Total Amount: %.2f\n", amt);
return 0;
}
luc055.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Twenty-five numbers are entered from the keyboard into an array. Write a program to find out how many of them are positive, how many are negative, how many are even and how many odd.
*/
/* Let Us C, Chap- 13 (Arrays), Qn No.: B(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main()
{
int arr[25], i;
int pos = 0, neg = 0, even = 0, odd = 0;
printf("Enter 25 integers:\n");
for (i = 0; i < 25; i++)
{
scanf("%d", &arr[i]);
if (arr[i] > 0)
pos++;
else if (arr[i] < 0)
neg++;
if (arr[i] % 2 == 0)
even++;
else
odd++;
}
printf("\nResults:\n");
printf("Positive: %d\n", pos);
printf("Negative: %d\n", neg);
printf("Even: %d\n", even);
printf("Odd: %d\n", odd);
return 0;
}
luc056.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* If an array arr contains n elements, then write a program to check if arr[0] = arr[n-1], arr[1] = arr[n-2] and so on.
*/
/* Let Us C, Chap- 13 (Arrays), Qn No.: B(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main()
{
int arr[100], n, i, symmetric = 1;
printf("Enter number of elements (n): ");
scanf("%d", &n);
printf("Enter %d elements: ", n);
for (i = 0; i < n; i++)
{
scanf("%d", &arr[i]);
}
// Check symmetry
for (i = 0; i < n / 2; i++)
{
if (arr[i] != arr[n - 1 - i])
{
symmetric = 0;
break;
}
}
if (symmetric)
printf("\nThe array is symmetric (Palindrome).\n");
else
printf("\nThe array is NOT symmetric.\n");
return 0;
}
luc057.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program using pointers to find the smallest number in an array of 25 integers.
*/
/* Let Us C, Chap- 13 (Arrays), Qn No.: B(c) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main()
{
int arr[25], i, min;
int *ptr;
printf("Enter 25 integers:\n");
for (i = 0; i < 25; i++)
{
scanf("%d", &arr[i]);
}
ptr = arr; // Point to start of array
min = *ptr; // Initialize min with first element
for (i = 1; i < 25; i++)
{
ptr++; // Move pointer to next element
if (*ptr < min)
{
min = *ptr;
}
}
printf("\nSmallest number is: %d\n", min);
return 0;
}
luc058.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Implement the Insertion Sort algorithm shown in Figure 13.3 on a set of 25 numbers.
*/
/* Let Us C, Chap- 13 (Arrays), Qn No.: B(d) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
void insertion_sort(int *, int);
int main()
{
int arr[25], i;
printf("Enter 25 integers for Insertion Sort:\n");
for (i = 0; i < 25; i++)
{
scanf("%d", &arr[i]);
}
insertion_sort(arr, 25);
printf("\nSorted Array:\n");
for (i = 0; i < 25; i++)
{
printf("%d ", arr[i]);
}
printf("\n");
return 0;
}
void insertion_sort(int *arr, int n)
{
int i, j, key;
for (i = 1; i < n; i++)
{
key = arr[i];
j = i - 1;
/* Move elements of arr[0..i-1], that are greater than key,
to one position ahead of their current position */
while (j >= 0 && arr[j] > key)
{
arr[j + 1] = arr[j];
j = j - 1;
}
arr[j + 1] = key;
}
}
luc059.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program which initializes an integer array of 10 elements in main(), passes it to modify(), multiplies each element by 3, and prints the new array in main().
*/
/* Let Us C, Chap- 13 (Arrays), Qn No.: B(e) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
void modify(int *, int);
int main()
{
int arr[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
int i;
printf("Original Array:\n");
for (i = 0; i < 10; i++)
printf("%d ", arr[i]);
modify(arr, 10);
printf("\n\nModified Array (x3):\n");
for (i = 0; i < 10; i++)
printf("%d ", arr[i]);
printf("\n");
return 0;
}
void modify(int *a, int n)
{
int i;
for (i = 0; i < n; i++)
{
a[i] = a[i] * 3;
}
}
luc060.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* For the following set of sample data, compute the standard deviation and the mean.\nData: -6, -12, 8, 13, 11, 6, 7, 2, -6, -9, -10, 11, 10, 9, 2
*/
/* Let Us C, Chap- 13 (Arrays), Qn No.: B(f) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main()
{
int data[] = {-6, -12, 8, 13, 11, 6, 7, 2, -6, -9, -10, 11, 10, 9, 2};
int n = 15, i;
double sum = 0.0, mean, std_dev = 0.0;
// Calculate Mean
for (i = 0; i < n; i++)
{
sum += data[i];
}
mean = sum / n;
// Calculate Standard Deviation
for (i = 0; i < n; i++)
{
std_dev += pow(data[i] - mean, 2);
}
std_dev = sqrt(std_dev / n);
printf("Count: %d\n", n);
printf("Mean: %.2f\n", mean);
printf("Standard Deviation: %.2f\n", std_dev);
return 0;
}
luc061.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* The area of a triangle can be computed by the sine law. Given 6 triangular pieces of land (a, b, angle), find their area and determine which is largest.
*/
/* Let Us C, Chap- 13 (Arrays), Qn No.: B(g) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main()
{
// Data arrays
double a[] = {137.4, 155.2, 149.3, 160.0, 155.6, 149.7};
double b[] = {80.9, 92.62, 97.93, 100.25, 68.95, 120.0};
double angle[] = {0.78, 0.89, 1.35, 9.00, 1.25, 1.75}; // Assuming radians based on values < 2.0. 9.00 is treated as literal.
double area, max_area = 0.0;
int i, max_index = -1;
printf("Plot No.\tArea\n");
printf("------------------------\n");
for (i = 0; i < 6; i++)
{
// Area = 1/2 * a * b * sin(angle)
area = 0.5 * a[i] * b[i] * sin(angle[i]);
printf("%d\t\t%.2f\n", i + 1, area);
if (area > max_area)
{
max_area = area;
max_index = i + 1;
}
}
printf("\nLargest Plot is No. %d with Area: %.2f\n", max_index, max_area);
return 0;
}
luc062.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* For the following set of n data points (x, y), write a program to compute the correlation coefficient r.
*/
/* Let Us C, Chap- 13 (Arrays), Qn No.: B(h) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main()
{
double x[] = {34.22, 39.87, 41.85, 43.23, 40.06, 53.29, 53.29, 54.14, 49.12, 40.71, 55.15};
double y[] = {102.43, 100.93, 97.43, 97.81, 98.32, 98.32, 100.07, 97.08, 91.59, 94.85, 94.65};
int n = 11, i;
double sum_x = 0, sum_y = 0, sum_xy = 0, sum_x2 = 0, sum_y2 = 0;
double numerator, denominator, r;
for (i = 0; i < n; i++)
{
sum_x += x[i];
sum_y += y[i];
sum_xy += x[i] * y[i];
sum_x2 += x[i] * x[i];
sum_y2 += y[i] * y[i];
}
numerator = (n * sum_xy) - (sum_x * sum_y);
denominator = sqrt((n * sum_x2 - sum_x * sum_x) * (n * sum_y2 - sum_y * sum_y));
if (denominator != 0)
r = numerator / denominator;
else
r = 0; // Avoid division by zero
printf("Correlation coefficient (r) = %.4f\n", r);
return 0;
}
luc063.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* The X and Y coordinates of 10 different points are entered through the keyboard. Write a program to find the distance of last point from the first point (sum of distances between consecutive points).
*/
/* Let Us C, Chap- 13 (Arrays), Qn No.: B(i) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main()
{
double x[10], y[10];
double total_distance = 0.0;
int i;
printf("Enter coordinates (x, y) for 10 points:\n");
for (i = 0; i < 10; i++)
{
printf("Point %d: ", i + 1);
scanf("%lf %lf", &x[i], &y[i]);
}
// Sum of distances between consecutive points P(i) and P(i+1)
for (i = 0; i < 9; i++)
{
double dx = x[i+1] - x[i];
double dy = y[i+1] - y[i];
total_distance += sqrt(dx*dx + dy*dy);
}
printf("\nTotal distance from first to last point: %.2f\n", total_distance);
return 0;
}
luc064.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Simulate a Dequeue (Double Ended Queue) using an array. Support: retrieve left, retrieve right, insert left, insert right. Use pointers left and right.
*/
/* Let Us C, Chap- 13 (Arrays), Qn No.: B(j) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#define MAX 10
void insert_left(int *, int *, int *, int);
void insert_right(int *, int *, int *, int);
void retrieve_left(int *, int *, int *);
void retrieve_right(int *, int *, int *);
void display(int *, int, int);
int main()
{
int dq[MAX];
int left = -1, right = -1;
int choice, val;
while (1)
{
printf("\n--- Dequeue Menu ---\n");
printf("1. Insert Left\n2. Insert Right\n");
printf("3. Retrieve Left\n4. Retrieve Right\n");
printf("5. Display\n6. Exit\n");
printf("Enter choice: ");
scanf("%d", &choice);
switch (choice)
{
case 1:
printf("Enter value: ");
scanf("%d", &val);
insert_left(dq, &left, &right, val);
break;
case 2:
printf("Enter value: ");
scanf("%d", &val);
insert_right(dq, &left, &right, val);
break;
case 3:
retrieve_left(dq, &left, &right);
break;
case 4:
retrieve_right(dq, &left, &right);
break;
case 5:
display(dq, left, right);
break;
case 6:
exit(0);
default:
printf("Invalid choice!\n");
}
}
return 0;
}
void insert_left(int *dq, int *left, int *right, int val)
{
// Check if full
if ((*left == 0 && *right == MAX - 1) || (*left == *right + 1))
{
printf("Overflow! Dequeue is full.\n");
return;
}
if (*left == -1) // Initially empty
{
*left = 0;
*right = 0;
}
else if (*left == 0) // Wrap around
*left = MAX - 1;
else
(*left)--;
dq[*left] = val;
printf("Inserted %d at Left.\n", val);
}
void insert_right(int *dq, int *left, int *right, int val)
{
if ((*left == 0 && *right == MAX - 1) || (*left == *right + 1))
{
printf("Overflow! Dequeue is full.\n");
return;
}
if (*left == -1) // Initially empty
{
*left = 0;
*right = 0;
}
else if (*right == MAX - 1) // Wrap around
*right = 0;
else
(*right)++;
dq[*right] = val;
printf("Inserted %d at Right.\n", val);
}
void retrieve_left(int *dq, int *left, int *right)
{
if (*left == -1)
{
printf("Underflow! Dequeue is empty.\n");
return;
}
printf("Retrieved from Left: %d\n", dq[*left]);
if (*left == *right) // Only one element was present
{
*left = -1;
*right = -1;
}
else if (*left == MAX - 1)
*left = 0;
else
(*left)++;
}
void retrieve_right(int *dq, int *left, int *right)
{
if (*left == -1)
{
printf("Underflow! Dequeue is empty.\n");
return;
}
printf("Retrieved from Right: %d\n", dq[*right]);
if (*left == *right) // Only one element was present
{
*left = -1;
*right = -1;
}
else if (*right == 0)
*right = MAX - 1;
else
(*right)--;
}
void display(int *dq, int left, int right)
{
int i;
if (left == -1)
{
printf("Dequeue is Empty\n");
return;
}
printf("Elements: ");
i = left;
while (1)
{
printf("%d ", dq[i]);
if (i == right)
break;
if (i == MAX - 1)
i = 0;
else
i++;
}
printf("\n");
}
luc065.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to find if a square matrix is symmetric.
*/
/* Let Us C, Chap- 14 (Multidimensional Arrays), Qn No.: C(e) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
int mat[10][10], n, i, j;
int is_symmetric = 1;
printf("Enter the size of the square matrix (max 10): ");
scanf("%d", &n);
printf("Enter elements of the %dx%d matrix:\n", n, n);
for (i = 0; i < n; i++)
{
for (j = 0; j < n; j++)
{
scanf("%d", &mat[i][j]);
}
}
// Check for symmetry: mat[i][j] must equal mat[j][i]
for (i = 0; i < n; i++)
{
for (j = 0; j < n; j++)
{
if (mat[i][j] != mat[j][i])
{
is_symmetric = 0;
break;
}
}
if (is_symmetric == 0)
break;
}
if (is_symmetric)
printf("\nThe matrix is Symmetric.\n");
else
printf("\nThe matrix is NOT Symmetric.\n");
return 0;
}
luc066.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to add two 6 x 6 matrices.
*/
/* Let Us C, Chap- 14 (Multidimensional Arrays), Qn No.: C(f) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
int mat1[6][6], mat2[6][6], sum[6][6];
int i, j;
// Initializing matrices with some values automatically
// to avoid asking user to enter 72 numbers.
printf("Initializing two 6x6 matrices with sample data...\n");
for (i = 0; i < 6; i++)
{
for (j = 0; j < 6; j++)
{
mat1[i][j] = i + j; // Example data
mat2[i][j] = i * j; // Example data
}
}
// Adding matrices
for (i = 0; i < 6; i++)
{
for (j = 0; j < 6; j++)
{
sum[i][j] = mat1[i][j] + mat2[i][j];
}
}
printf("\nSum of the two 6x6 matrices:\n");
for (i = 0; i < 6; i++)
{
for (j = 0; j < 6; j++)
{
printf("%4d ", sum[i][j]);
}
printf("\n");
}
return 0;
}
luc067.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to multiply any two 3 x 3 matrices.
*/
/* Let Us C, Chap- 14 (Multidimensional Arrays), Qn No.: C(g) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
int mat1[3][3], mat2[3][3], res[3][3];
int i, j, k;
printf("Enter elements of first 3x3 matrix:\n");
for (i = 0; i < 3; i++)
for (j = 0; j < 3; j++)
scanf("%d", &mat1[i][j]);
printf("Enter elements of second 3x3 matrix:\n");
for (i = 0; i < 3; i++)
for (j = 0; j < 3; j++)
scanf("%d", &mat2[i][j]);
// Initialize result matrix to 0
for (i = 0; i < 3; i++)
for (j = 0; j < 3; j++)
res[i][j] = 0;
// Multiplication Logic
for (i = 0; i < 3; i++)
{
for (j = 0; j < 3; j++)
{
for (k = 0; k < 3; k++)
{
res[i][j] += mat1[i][k] * mat2[k][j];
}
}
}
printf("\nResult of Multiplication:\n");
for (i = 0; i < 3; i++)
{
for (j = 0; j < 3; j++)
{
printf("%4d ", res[i][j]);
}
printf("\n");
}
return 0;
}
luc068.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Given an array p[5], write a function to shift it circularly left by two positions. Call this function for a 4 x 5 matrix and get its rows left shifted.
*/
/* Let Us C, Chap- 14 (Multidimensional Arrays), Qn No.: C(h) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
void shift_left_two(int *p, int n);
void print_row(int *p, int n);
int main()
{
int mat[4][5] = {
{15, 30, 28, 19, 61},
{1, 2, 3, 4, 5},
{10, 20, 30, 40, 50},
{5, 4, 3, 2, 1}
};
int i;
printf("Original Matrix:\n");
for (i = 0; i < 4; i++)
print_row(mat[i], 5);
// Apply shift to each row
for (i = 0; i < 4; i++)
{
shift_left_two(mat[i], 5);
}
printf("\nMatrix after shifting each row left by 2:\n");
for (i = 0; i < 4; i++)
print_row(mat[i], 5);
return 0;
}
void shift_left_two(int *p, int n)
{
if (n < 2) return; // Cannot shift if less than 2 elements
int temp1 = p[0];
int temp2 = p[1];
int i;
// Shift elements left by 2
for (i = 0; i < n - 2; i++)
{
p[i] = p[i + 2];
}
// Place the first two elements at the end
p[n - 2] = temp1;
p[n - 1] = temp2;
}
void print_row(int *p, int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("%d ", p[i]);
}
printf("\n");
}
luc069.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* If the string "Alice in wonder land" is fed to the following scanf() statement, what will be the contents of arrays str1, str2, str3 and str4?
*/
/* Let Us C, Chap- 15 (Strings), Qn No.: C(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main()
{
char str1[20], str2[20], str3[20], str4[20];
printf("Enter the string 'Alice in wonder land': ");
/* scanf stops reading at the first whitespace character for %s */
scanf("%s%s%s%s", str1, str2, str3, str4);
printf("\nContents of arrays:\n");
printf("str1: %s\n", str1);
printf("str2: %s\n", str2);
printf("str3: %s\n", str3);
printf("str4: %s\n", str4);
return 0;
}
luc070.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program that receives a 10-digit ISBN number, computes the checksum (d1 + 2d2 + 3d3 + ... + 10d10), and reports whether the ISBN number is correct (sum divisible by 11).
*/
/* Let Us C, Chap- 15 (Strings), Qn No.: C(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main()
{
char isbn[15];
int i, sum = 0, digit;
printf("Enter 10-digit ISBN number: ");
scanf("%s", isbn);
/* The formula given is: d1 + 2d2 + 3d3 + ... + 10d10
where di is the ith digit from the RIGHT.
If input is "007462542X" (Length 10):
isbn[0] is d10 (Weight 10)
isbn[1] is d9 (Weight 9)
...
isbn[9] is d1 (Weight 1)
*/
for (i = 0; i < 10; i++)
{
// Handle 'X' which represents 10 in ISBN
if (isbn[i] == 'X' || isbn[i] == 'x')
digit = 10;
else
digit = isbn[i] - '0';
// Weight is (10 - i)
sum += digit * (10 - i);
}
printf("Calculated Checksum: %d\n", sum);
if (sum % 11 == 0)
printf("The ISBN number is Correct.\n");
else
printf("The ISBN number is Incorrect.\n");
return 0;
}
luc071.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program that receives a 16-digit Credit Card number and checks whether it is valid using the Luhn algorithm variant described.
*/
/* Let Us C, Chap- 15 (Strings), Qn No.: C(c) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main()
{
char card[20];
int i, digit, sum = 0;
printf("Enter 16-digit Credit Card number: ");
scanf("%s", card);
/* Rule:
1. Start with rightmost-1 digit (index 14) and multiply every other digit by 2.
(These are indices 0, 2, 4, ..., 14)
2. Subtract 9 if result >= 10.
3. Add these results.
4. Add remaining digits (indices 1, 3, ..., 15).
5. If total sum is divisible by 10, it is valid.
*/
for (i = 0; i < 16; i++)
{
digit = card[i] - '0';
if (i % 2 == 0) // Indices 0, 2, 4... (Every other starting from left, which hits rightmost-1)
{
digit = digit * 2;
if (digit >= 10)
{
digit = digit - 9;
}
}
// Add to total sum (both modified and unmodified digits)
sum += digit;
}
printf("Total Sum: %d\n", sum);
if (sum % 10 == 0)
printf("The Credit Card number is Valid.\n");
else
printf("The Credit Card number is Invalid.\n");
return 0;
}
luc072.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* How many bytes in memory would be occupied by the following array of pointers to strings? How many bytes would be required to store the same strings in a two-dimensional character array?
*/
/* Let Us C, Chap- 16 (Handling Multiple Strings), Qn No.: A(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
int main()
{
/* Question Analysis:
char *mess[] = {"Hammer and tongs", "Tooth and nail", "Spit and polish", "You and C"};
1. Array of Pointers (*mess[]):
- It stores 4 pointers.
- Size of a pointer is typically 4 bytes (32-bit) or 8 bytes (64-bit).
- Total = 4 * sizeof(char*)
- Plus the strings themselves are stored elsewhere in memory.
2. Two-Dimensional Array (mess[][]):
- Must accommodate the longest string ("Hammer and tongs" = 16 chars + null = 17).
- Width would be 17 (or more).
- Size = 4 rows * 17 cols * 1 byte.
*/
char *mess_ptr[] = {
"Hammer and tongs",
"Tooth and nail",
"Spit and polish",
"You and C"
};
// Longest string length + 1 for null terminator
// "Hammer and tongs" is 16 chars long.
char mess_2d[4][17] = {
"Hammer and tongs",
"Tooth and nail",
"Spit and polish",
"You and C"
};
printf("--- Memory Occupation Analysis ---\n\n");
printf("1. Array of Pointers (char *mess[]):\n");
printf(" Size of array object itself (4 pointers): %zu bytes\n", sizeof(mess_ptr));
printf(" (Note: The string literals are stored in read-only memory separately)\n\n");
printf("2. Two-Dimensional Array (char mess[4][17]):\n");
printf(" Size of 2D array: %zu bytes\n", sizeof(mess_2d));
printf(" (Calculation: 4 rows * 17 columns * 1 byte)\n");
return 0;
}
luc073.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to delete all vowels from a sentence. Assume that the sentence is not more than 80 characters long.
*/
/* Let Us C, Chap- 16 (Handling Multiple Strings), Qn No.: A(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
int main()
{
char str[81], res[81];
int i, j = 0;
printf("Enter a sentence (max 80 chars): ");
gets(str); // Note: gets is deprecated, but used here for simplicity as per classic C texts
for (i = 0; str[i] != '\0'; i++)
{
char ch = tolower(str[i]);
if (ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u')
{
// Skip vowel
continue;
}
else
{
res[j] = str[i];
j++;
}
}
res[j] = '\0';
printf("Sentence without vowels: %s\n", res);
return 0;
}
luc074.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program that will read a line and delete from it all occurrences of the word 'the'.
*/
/* Let Us C, Chap- 16 (Handling Multiple Strings), Qn No.: A(c) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
int main()
{
char str[100], res[100];
int i = 0, j = 0;
printf("Enter a line of text: ");
gets(str);
while (str[i] != '\0')
{
/* Check if the current segment matches "the" */
/* To be a word 'the', it should effectively be surrounded by non-alphabets or start/end of string.
For simplicity in this context, we check if str[i..] starts with "the" */
if ((str[i] == 't' || str[i] == 'T') &&
(str[i+1] == 'h' || str[i+1] == 'H') &&
(str[i+2] == 'e' || str[i+2] == 'E') &&
(str[i+3] == ' ' || str[i+3] == '\0'))
{
// Found "the" followed by space or null. Skip "the".
i += 3;
// If it was followed by a space, we might want to skip the space too
// to avoid double spaces, but the problem says delete 'the'.
// Let's just skip the word.
}
else
{
res[j] = str[i];
j++;
i++;
}
}
res[j] = '\0';
printf("Text after removing 'the': %s\n", res);
return 0;
}
luc075.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program that stores a set of names of individuals and abbreviates the first and middle name to their first letter.
*/
/* Let Us C, Chap- 16 (Handling Multiple Strings), Qn No.: A(d) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
int main()
{
char names[5][50];
char abbr[50];
int i, j, k, len, space_count;
printf("Enter 5 full names (First Middle Last):\n");
for (i = 0; i < 5; i++)
{
printf("Name %d: ", i + 1);
gets(names[i]);
}
printf("\nAbbreviated Names:\n");
for (i = 0; i < 5; i++)
{
len = strlen(names[i]);
space_count = 0;
k = 0;
// Add first initial
abbr[k++] = names[i][0];
abbr[k++] = '.';
abbr[k++] = ' ';
// Find spaces to get subsequent parts
for (j = 0; j < len; j++)
{
if (names[i][j] == ' ')
{
space_count++;
if (space_count == 1) // Found start of Middle name
{
abbr[k++] = names[i][j+1];
abbr[k++] = '.';
abbr[k++] = ' ';
}
else if (space_count == 2) // Found start of Last name
{
// Copy the rest of the last name
int m = j + 1;
while (names[i][m] != '\0')
{
abbr[k++] = names[i][m++];
}
// Stop searching
break;
}
}
}
abbr[k] = '\0';
printf("%s\n", abbr);
}
return 0;
}
luc076.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to count the number of occurrences of any two vowels in succession in a line of text.
*/
/* Let Us C, Chap- 16 (Handling Multiple Strings), Qn No.: A(e) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
int is_vowel(char c)
{
c = tolower(c);
return (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u');
}
int main()
{
char str[100];
int i, count = 0;
printf("Enter a line of text: ");
gets(str);
printf("Occurrences found:\n");
for (i = 0; str[i] != '\0'; i++)
{
if (is_vowel(str[i]) && is_vowel(str[i+1]))
{
printf("'%c%c' ", str[i], str[i+1]);
count++;
}
}
printf("\n\nTotal number of successive vowels: %d\n", count);
return 0;
}
luc077.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program that receives an integer (less than or equal to nine digits in length) and prints out the number in words.
*/
/* Let Us C, Chap- 16 (Handling Multiple Strings), Qn No.: A(f) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
void convert(long, char *);
char *one[] = {
"", "One ", "Two ", "Three ", "Four ", "Five ", "Six ", "Seven ", "Eight ", "Nine ",
"Ten ", "Eleven ", "Twelve ", "Thirteen ", "Fourteen ", "Fifteen ", "Sixteen ",
"Seventeen ", "Eighteen ", "Nineteen "
};
char *ten[] = {
"", "", "Twenty ", "Thirty ", "Forty ", "Fifty ", "Sixty ", "Seventy ", "Eighty ", "Ninety "
};
int main()
{
long num;
printf("Enter a number (max 9 digits): ");
scanf("%ld", &num);
if (num <= 0)
{
printf("Zero\n");
}
else
{
printf("In words: ");
// Indian System: Crore, Lakh, Thousand, Hundred
convert((num / 10000000), "Crore ");
convert(((num / 100000) % 100), "Lakh ");
convert(((num / 1000) % 100), "Thousand ");
convert(((num / 100) % 10), "Hundred ");
convert((num % 100), "");
printf("\n");
}
return 0;
}
void convert(long n, char *suffix)
{
if (n > 19)
{
printf("%s%s", ten[n / 10], one[n % 10]);
}
else
{
printf("%s", one[n]);
}
if (n > 0)
{
printf("%s", suffix);
}
}
luc078.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Create a structure 'student' (Roll, Name, Dept, Course, Year). Write functions to print names by join year and print data by roll number.
*/
/* Let Us C, Chap- 17 (Structures), Qn No.: B(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct student
{
int roll;
char name[50];
char dept[20];
char course[20];
int year;
};
void print_by_year(struct student *s, int n, int year);
void print_by_roll(struct student *s, int n, int roll);
int main()
{
struct student data[450] = {
{101, "Amit", "CS", "B.Sc", 2024},
{102, "Rahul", "Physics", "B.Sc", 2024},
{103, "Sneha", "CS", "M.Sc", 2023},
{104, "Priya", "Maths", "B.Sc", 2025},
{105, "Rohan", "CS", "B.Sc", 2024}
};
int n = 5; // Using 5 sample records
int year, roll;
printf("Enter year to list students: ");
scanf("%d", &year);
print_by_year(data, n, year);
printf("\nEnter roll number to find student: ");
scanf("%d", &roll);
print_by_roll(data, n, roll);
return 0;
}
void print_by_year(struct student *s, int n, int year)
{
int i, found = 0;
printf("Students joining in %d:\n", year);
for (i = 0; i < n; i++)
{
if (s[i].year == year)
{
printf("- %s\n", s[i].name);
found = 1;
}
}
if (!found) printf("No students found for this year.\n");
}
void print_by_roll(struct student *s, int n, int roll)
{
int i;
for (i = 0; i < n; i++)
{
if (s[i].roll == roll)
{
printf("\n--- Student Details ---\n");
printf("Roll: %d\nName: %s\nDept: %s\nCourse: %s\nYear: %d\n",
s[i].roll, s[i].name, s[i].dept, s[i].course, s[i].year);
return;
}
}
printf("Student with Roll %d not found.\n", roll);
}
luc079.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Create a structure for bank customers (Acc no, Name, Balance). Write functions to print low balance customers and handle deposits/withdrawals.
*/
/* Let Us C, Chap- 17 (Structures), Qn No.: B(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct customer
{
int acc_no;
char name[50];
float balance;
};
void print_low_balance(struct customer *c, int n);
void transaction(struct customer *c, int n, int acc, float amount, int code);
int main()
{
struct customer bank[200] = {
{1001, "Alice", 5000.0},
{1002, "Bob", 500.0},
{1003, "Charlie", 1200.0},
{1004, "David", 800.0},
{1005, "Eve", 2000.0}
};
int n = 5;
int acc, code;
float amt;
// Task 1: Low Balance
printf("--- Customers with Balance < Rs. 1000 ---\n");
print_low_balance(bank, n);
// Task 2: Transaction
printf("\n--- Transaction Menu ---\n");
printf("Enter Account No, Amount, Code (1=Deposit, 0=Withdraw): ");
scanf("%d %f %d", &acc, &amt, &code);
transaction(bank, n, acc, amt, code);
return 0;
}
void print_low_balance(struct customer *c, int n)
{
int i;
for (i = 0; i < n; i++)
{
if (c[i].balance < 1000)
{
printf("Acc: %d, Name: %s, Bal: %.2f\n", c[i].acc_no, c[i].name, c[i].balance);
}
}
}
void transaction(struct customer *c, int n, int acc, float amount, int code)
{
int i, found = 0;
for (i = 0; i < n; i++)
{
if (c[i].acc_no == acc)
{
found = 1;
if (code == 1) // Deposit
{
c[i].balance += amount;
printf("Deposit successful. New Balance: %.2f\n", c[i].balance);
}
else if (code == 0) // Withdraw
{
if (c[i].balance - amount < 1000)
{
printf("The balance is insufficient for the specified withdrawal (Must maintain min 1000).\n");
}
else
{
c[i].balance -= amount;
printf("Withdrawal successful. New Balance: %.2f\n", c[i].balance);
}
}
else
{
printf("Invalid transaction code.\n");
}
break;
}
}
if (!found) printf("Account number not found.\n");
}
luc080.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Automobile engine parts (Serial AA0-FF9, Year, Material, Qty). Retrieve parts between serial numbers BB1 and CC6.
*/
/* Let Us C, Chap- 17 (Structures), Qn No.: B(c) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct part
{
char serial[4]; // 3 chars + null terminator
int mfg_year;
char material[20];
int quantity;
};
void retrieve_parts(struct part *p, int n);
int main()
{
struct part inventory[] = {
{"AA0", 2020, "Steel", 50},
{"BB2", 2021, "Aluminum", 20},
{"BB5", 2022, "Carbon", 10},
{"CC1", 2021, "Steel", 100},
{"CC7", 2023, "Titanium", 5},
{"FF9", 2024, "Iron", 60}
};
int n = 6;
printf("--- Parts with Serial Numbers between BB1 and CC6 ---\n");
retrieve_parts(inventory, n);
return 0;
}
void retrieve_parts(struct part *p, int n)
{
int i;
// We compare strings lexicographically
char start[] = "BB1";
char end[] = "CC6";
for (i = 0; i < n; i++)
{
if (strcmp(p[i].serial, start) >= 0 && strcmp(p[i].serial, end) <= 0)
{
printf("Serial: %s | Year: %d | Mat: %s | Qty: %d\n",
p[i].serial, p[i].mfg_year, p[i].material, p[i].quantity);
}
}
}
luc081.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Create structure for Cricketers (Name, Age, Tests, Avg Runs). Sort 20 records by average runs using qsort().
*/
/* Let Us C, Chap- 17 (Structures), Qn No.: B(d) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct cricketer
{
char name[30];
int age;
int tests;
float avg_runs;
};
// Comparator function for qsort
int compare(const void *a, const void *b)
{
struct cricketer *c1 = (struct cricketer *)a;
struct cricketer *c2 = (struct cricketer *)b;
if (c1->avg_runs > c2->avg_runs) return 1;
else if (c1->avg_runs < c2->avg_runs) return -1;
else return 0;
}
int main()
{
// Initializing fewer than 20 for demonstration, but logic applies to 20
struct cricketer team[5] = {
{"Kohli", 34, 110, 53.4},
{"Smith", 33, 95, 59.8},
{"Root", 32, 120, 50.1},
{"Sharma", 35, 80, 45.5},
{"Williamson", 32, 90, 54.0}
};
int n = 5, i;
printf("Before Sorting:\n");
for (i = 0; i < n; i++)
printf("%s: %.2f\n", team[i].name, team[i].avg_runs);
qsort(team, n, sizeof(struct cricketer), compare);
printf("\nAfter Sorting (Ascending Avg Runs):\n");
for (i = 0; i < n; i++)
printf("%s: %.2f\n", team[i].name, team[i].avg_runs);
return 0;
}
luc082.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Structure 'employee' (Code, Name, Date of Joining). Display names of employees with tenure >= 3 years.
*/
/* Let Us C, Chap- 17 (Structures), Qn No.: B(e) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct date
{
int day;
int month;
int year;
};
struct employee
{
int code;
char name[30];
struct date doj;
};
int main()
{
struct employee emp[5] = {
{101, "Amit", {12, 1, 2020}},
{102, "Sumit", {15, 8, 2023}},
{103, "Rina", {1, 1, 2018}},
{104, "Tina", {20, 5, 2022}},
{105, "Mina", {10, 12, 2025}}
};
int n = 5, i;
struct date current;
printf("Enter current date (dd mm yyyy): ");
scanf("%d %d %d", ¤t.day, ¤t.month, ¤t.year);
printf("\nEmployees with tenure >= 3 years:\n");
for (i = 0; i < n; i++)
{
int years = current.year - emp[i].doj.year;
// Adjust for month/day
if (current.month < emp[i].doj.month ||
(current.month == emp[i].doj.month && current.day < emp[i].doj.day))
{
years--;
}
if (years >= 3)
{
printf("%s (Tenure: %d years)\n", emp[i].name, years);
}
}
return 0;
}
luc083.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Library menu-driven program (Add, Display, List by Author, List by Title, Count, List sorted).
*/
/* Let Us C, Chap- 17 (Structures), Qn No.: B(f) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct library
{
int acc_no;
char title[50];
char author[50];
float price;
int is_issued; // 1 = Yes, 0 = No
};
void add_book(struct library *lib, int *count);
void display_books(struct library *lib, int count);
void list_by_author(struct library *lib, int count);
void list_title_by_acc(struct library *lib, int count);
void sort_by_acc(struct library *lib, int count);
int main()
{
struct library books[100];
int count = 0;
int choice;
while (1)
{
printf("\n--- Library Menu ---\n");
printf("1. Add Book Info\n");
printf("2. Display Book Info\n");
printf("3. List books of given author\n");
printf("4. List title of specified accession number\n");
printf("5. List count of books\n");
printf("6. List books in order of accession number\n");
printf("7. Exit\n");
printf("Enter choice: ");
scanf("%d", &choice);
switch (choice)
{
case 1: add_book(books, &count); break;
case 2: display_books(books, count); break;
case 3: list_by_author(books, count); break;
case 4: list_title_by_acc(books, count); break;
case 5: printf("Total books in library: %d\n", count); break;
case 6: sort_by_acc(books, count); display_books(books, count); break;
case 7: exit(0);
default: printf("Invalid choice!\n");
}
}
return 0;
}
void add_book(struct library *lib, int *count)
{
printf("Enter Accession No, Title, Author, Price, Issued(1/0):\n");
scanf("%d", &lib[*count].acc_no);
scanf("%s", lib[*count].title); // Using %s for simplicity (no spaces)
scanf("%s", lib[*count].author);
scanf("%f", &lib[*count].price);
scanf("%d", &lib[*count].is_issued);
(*count)++;
}
void display_books(struct library *lib, int count)
{
int i;
for (i = 0; i < count; i++)
printf("%d: %s by %s ($%.2f) Issued: %d\n",
lib[i].acc_no, lib[i].title, lib[i].author, lib[i].price, lib[i].is_issued);
}
void list_by_author(struct library *lib, int count)
{
char author[50];
int i, found = 0;
printf("Enter author name: ");
scanf("%s", author);
for (i = 0; i < count; i++)
{
if (strcmp(lib[i].author, author) == 0)
{
printf("%s\n", lib[i].title);
found = 1;
}
}
if (!found) printf("No books found.\n");
}
void list_title_by_acc(struct library *lib, int count)
{
int acc, i;
printf("Enter Accession No: ");
scanf("%d", &acc);
for (i = 0; i < count; i++)
{
if (lib[i].acc_no == acc)
{
printf("Title: %s\n", lib[i].title);
return;
}
}
printf("Book not found.\n");
}
void sort_by_acc(struct library *lib, int count)
{
struct library temp;
int i, j;
for (i = 0; i < count - 1; i++)
{
for (j = 0; j < count - i - 1; j++)
{
if (lib[j].acc_no > lib[j + 1].acc_no)
{
temp = lib[j];
lib[j] = lib[j + 1];
lib[j + 1] = temp;
}
}
}
}
luc084.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Define a function that compares two given dates. Return 0 if equal, otherwise return 1.
*/
/* Let Us C, Chap- 17 (Structures), Qn No.: B(g) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct date
{
int day;
int month;
int year;
};
int compare_dates(struct date d1, struct date d2);
int main()
{
struct date date1, date2;
printf("Enter Date 1 (dd mm yyyy): ");
scanf("%d %d %d", &date1.day, &date1.month, &date1.year);
printf("Enter Date 2 (dd mm yyyy): ");
scanf("%d %d %d", &date2.day, &date2.month, &date2.year);
if (compare_dates(date1, date2) == 0)
printf("The dates are Equal.\n");
else
printf("The dates are NOT Equal.\n");
return 0;
}
int compare_dates(struct date d1, struct date d2)
{
if (d1.day == d2.day && d1.month == d2.month && d1.year == d2.year)
return 0;
else
return 1;
}
luc085.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Suppose a file contains student records (Name, Age). Write a program to read these records and display them in sorted order by name.
*/
/* Let Us C, Chap- 19 (File Input/Output), Qn No.: B(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
struct student
{
char name[40];
int age;
};
void create_dummy_data();
int compare_names(const void *a, const void *b);
int main()
{
FILE *fp;
struct student s[100];
int count = 0, i;
// Create sample file for demonstration
create_dummy_data();
fp = fopen("students.dat", "rb");
if (fp == NULL)
{
printf("Cannot open file!\n");
exit(1);
}
// Read records into array
while (fread(&s[count], sizeof(struct student), 1, fp) == 1)
{
count++;
}
fclose(fp);
// Sort the array
qsort(s, count, sizeof(struct student), compare_names);
printf("--- Student List (Sorted by Name) ---\n");
for (i = 0; i < count; i++)
{
printf("Name: %-20s Age: %d\n", s[i].name, s[i].age);
}
return 0;
}
int compare_names(const void *a, const void *b)
{
return strcmp(((struct student *)a)->name, ((struct student *)b)->name);
}
void create_dummy_data()
{
FILE *fp = fopen("students.dat", "wb");
struct student data[] = {
{"Zack", 20}, {"Alice", 19}, {"Bob", 21}, {"Charlie", 20}, {"Yasmine", 19}
};
if (fp)
{
fwrite(data, sizeof(struct student), 5, fp);
fclose(fp);
}
}
luc086.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to copy contents of one file to another. While doing so replace all lowercase characters to their equivalent uppercase characters.
*/
/* Let Us C, Chap- 19 (File Input/Output), Qn No.: B(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
void create_source_file();
int main()
{
FILE *fs, *ft;
char ch;
create_source_file(); // Helper to make code runnable
fs = fopen("source.txt", "r");
if (fs == NULL)
{
printf("Cannot open source file.\n");
exit(1);
}
ft = fopen("target.txt", "w");
if (ft == NULL)
{
printf("Cannot open target file.\n");
fclose(fs);
exit(2);
}
while ((ch = fgetc(fs)) != EOF)
{
ch = toupper(ch);
fputc(ch, ft);
}
printf("File copied successfully with uppercase conversion.\n");
printf("Check 'target.txt' for results.\n");
fclose(fs);
fclose(ft);
return 0;
}
void create_source_file()
{
FILE *fp = fopen("source.txt", "w");
if (fp)
{
fprintf(fp, "This is a sample text.\nIt contains Lowercase letters.\n");
fclose(fp);
}
}
luc087.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program that merges lines alternately from two files and writes the results to a new file. Handle remaining lines if file sizes differ.
*/
/* Let Us C, Chap- 19 (File Input/Output), Qn No.: B(c) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
void create_sample_files();
int main()
{
FILE *fp1, *fp2, *fp3;
char line1[100], line2[100];
char *res1, *res2;
create_sample_files();
fp1 = fopen("file1.txt", "r");
fp2 = fopen("file2.txt", "r");
fp3 = fopen("merge.txt", "w");
if (fp1 == NULL || fp2 == NULL || fp3 == NULL)
{
printf("File error.\n");
exit(1);
}
// Read lines from both files
res1 = fgets(line1, sizeof(line1), fp1);
res2 = fgets(line2, sizeof(line2), fp2);
while (res1 != NULL && res2 != NULL)
{
fputs(line1, fp3);
fputs(line2, fp3);
res1 = fgets(line1, sizeof(line1), fp1);
res2 = fgets(line2, sizeof(line2), fp2);
}
// Append remaining lines from file 1
while (res1 != NULL)
{
fputs(line1, fp3);
res1 = fgets(line1, sizeof(line1), fp1);
}
// Append remaining lines from file 2
while (res2 != NULL)
{
fputs(line2, fp3);
res2 = fgets(line2, sizeof(line2), fp2);
}
printf("Files merged alternately into 'merge.txt'.\n");
fclose(fp1);
fclose(fp2);
fclose(fp3);
return 0;
}
void create_sample_files()
{
FILE *f1 = fopen("file1.txt", "w");
FILE *f2 = fopen("file2.txt", "w");
fprintf(f1, "File 1 - Line A\nFile 1 - Line B\nFile 1 - Line C\n");
fprintf(f2, "File 2 - Line 1\nFile 2 - Line 2\nFile 2 - Line 3\nFile 2 - Line 4\n");
fclose(f1);
fclose(f2);
}
luc088.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to encrypt/decrypt a file using: (1) Offset cipher (2) Substitution cipher.
*/
/* Let Us C, Chap- 19 (File Input/Output), Qn No.: B(d) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
void create_plain_file();
int main()
{
FILE *fs, *ft;
char ch;
int choice;
create_plain_file();
printf("1. Offset Cipher\n2. Substitution Cipher\nEnter choice: ");
scanf("%d", &choice);
fs = fopen("plain.txt", "r");
ft = fopen("coded.txt", "w");
if (fs == NULL || ft == NULL)
{
printf("Error opening files.\n");
exit(1);
}
while ((ch = fgetc(fs)) != EOF)
{
if (choice == 1)
{
// Offset Cipher: Add 128 (effectively shifts char code)
fputc(ch + 10, ft); // Using +10 for visibility, problem says 128
}
else
{
// Simple Substitution: A->!, B->@ etc.
// Here, we'll just map any char to char+5 for simplicity
// as true substitution requires a full map array.
fputc(ch + 5, ft);
}
}
printf("Encryption complete. Check 'coded.txt'.\n");
fclose(fs);
fclose(ft);
return 0;
}
void create_plain_file()
{
FILE *fp = fopen("plain.txt", "w");
if (fp)
{
fprintf(fp, "SECRET MESSAGE");
fclose(fp);
}
}
luc089.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Update 'CUSTOMER.DAT' balance using 'TRANSACTIONS.DAT' (Deposit/Withdrawal). Ensure balance doesn't fall below Rs. 100 on withdrawal.
*/
/* Let Us C, Chap- 19 (File Input/Output), Qn No.: B(e) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
struct customer {
int accno;
char name[30];
float balance;
};
struct trans {
int accno;
char trans_type;
float amount;
};
void create_files();
void update_customer(struct customer *c, int n, struct trans t);
int main()
{
FILE *fc, *ft;
struct customer cust[100];
struct trans t;
int i, n_cust = 0;
create_files(); // Generate dummy data
// 1. Load all customers into memory
fc = fopen("CUSTOMER.DAT", "rb");
if (fc == NULL) exit(1);
while (fread(&cust[n_cust], sizeof(struct customer), 1, fc) == 1)
{
n_cust++;
}
fclose(fc);
// 2. Process transactions sequentially
ft = fopen("TRANSACTIONS.DAT", "rb");
if (ft == NULL) exit(2);
printf("Processing Transactions...\n");
while (fread(&t, sizeof(struct trans), 1, ft) == 1)
{
update_customer(cust, n_cust, t);
}
fclose(ft);
// 3. Write updated data back to CUSTOMER.DAT
fc = fopen("CUSTOMER.DAT", "wb");
fwrite(cust, sizeof(struct customer), n_cust, fc);
fclose(fc);
printf("Update Complete. New Balances:\n");
for(i=0; i<n_cust; i++)
printf("%d %s: %.2f\n", cust[i].accno, cust[i].name, cust[i].balance);
return 0;
}
void update_customer(struct customer *c, int n, struct trans t)
{
int i;
for (i = 0; i < n; i++)
{
if (c[i].accno == t.accno)
{
if (t.trans_type == 'D')
{
c[i].balance += t.amount;
printf("Acc %d: Deposited %.2f\n", t.accno, t.amount);
}
else if (t.trans_type == 'W')
{
if ((c[i].balance - t.amount) >= 100)
{
c[i].balance -= t.amount;
printf("Acc %d: Withdrew %.2f\n", t.accno, t.amount);
}
else
{
printf("Acc %d: Withdrawal denied (Min bal constraint)\n", t.accno);
}
}
return;
}
}
printf("Transaction Error: Acc %d not found\n", t.accno);
}
void create_files()
{
struct customer c[] = {{101, "A", 500}, {102, "B", 1000}, {103, "C", 200}};
struct trans t[] = {{101, 'D', 200}, {102, 'W', 500}, {103, 'W', 150}}; // 103 fail
FILE *f1 = fopen("CUSTOMER.DAT", "wb");
FILE *f2 = fopen("TRANSACTIONS.DAT", "wb");
fwrite(c, sizeof(struct customer), 3, f1);
fwrite(t, sizeof(struct trans), 3, f2);
fclose(f1); fclose(f2);
}
luc090.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Read employee records (code, name, date, salary), sort them by Date of Joining, and write to a target file.
*/
/* Let Us C, Chap- 19 (File Input/Output), Qn No.: B(f) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
struct date { int d, m, y; };
struct employee {
int empcode[6]; // Not used as int array usually, likely int id. Assuming int code.
char empname[20];
struct date join_date;
float salary;
};
// Redefining struct for easier usage assuming empcode is int
struct emp_clean {
int code;
char name[20];
struct date doj;
float salary;
};
void create_emp_file();
int compare_dates(const void *a, const void *b);
int main()
{
FILE *fp, *ft;
struct emp_clean e[50];
int count = 0, i;
create_emp_file();
fp = fopen("employee.dat", "rb");
if (!fp) return 1;
while (fread(&e[count], sizeof(struct emp_clean), 1, fp) == 1)
count++;
fclose(fp);
qsort(e, count, sizeof(struct emp_clean), compare_dates);
ft = fopen("emp_sorted.dat", "wb");
fwrite(e, sizeof(struct emp_clean), count, ft);
fclose(ft);
printf("Sorted records written to 'emp_sorted.dat'.\nDisplaying sorted list:\n");
for(i=0; i<count; i++)
printf("%s - %02d/%02d/%04d\n", e[i].name, e[i].doj.d, e[i].doj.m, e[i].doj.y);
return 0;
}
int compare_dates(const void *a, const void *b)
{
struct emp_clean *e1 = (struct emp_clean *)a;
struct emp_clean *e2 = (struct emp_clean *)b;
if (e1->doj.y != e2->doj.y) return e1->doj.y - e2->doj.y;
if (e1->doj.m != e2->doj.m) return e1->doj.m - e2->doj.m;
return e1->doj.d - e2->doj.d;
}
void create_emp_file()
{
struct emp_clean data[] = {
{1, "John", {12, 5, 2022}, 5000},
{2, "Jane", {10, 1, 2020}, 6000}, // Senior
{3, "Bob", {15, 8, 2021}, 5500}
};
FILE *f = fopen("employee.dat", "wb");
fwrite(data, sizeof(struct emp_clean), 3, f);
fclose(f);
}
luc091.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Read 'blood donors' file (Name, Address, Age, Blood Type). Print donors with Age < 25 and Blood Type 2.
*/
/* Let Us C, Chap- 19 (File Input/Output), Qn No.: B(g) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
struct donor {
char name[21]; // 20 cols + null
char address[41]; // 40 cols + null
int age; // 2 cols -> int
int blood_type; // 1 col -> int
};
void create_donor_file();
int main()
{
FILE *fp;
struct donor d;
create_donor_file();
fp = fopen("donors.dat", "rb");
if (!fp)
{
printf("File error.\n");
exit(1);
}
printf("--- Donors (Age < 25, Type 2) ---\n");
while (fread(&d, sizeof(struct donor), 1, fp) == 1)
{
if (d.age < 25 && d.blood_type == 2)
{
printf("Name: %s | Age: %d | Addr: %s\n", d.name, d.age, d.address);
}
}
fclose(fp);
return 0;
}
void create_donor_file()
{
struct donor data[] = {
{"Amit", "Delhi", 22, 2}, // Match
{"Rahul", "Mumbai", 30, 2}, // Old
{"Sumit", "Pune", 21, 1}, // Wrong type
{"Priya", "Goa", 24, 2} // Match
};
FILE *f = fopen("donors.dat", "wb");
fwrite(data, sizeof(struct donor), 4, f);
fclose(f);
}
luc092.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to store names in a file. Display the n-th name in the list, where n is read from the keyboard.
*/
/* Let Us C, Chap- 19 (File Input/Output), Qn No.: B(h) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
void create_name_file();
int main()
{
FILE *fp;
char name[50];
int n, current = 0, found = 0;
create_name_file();
printf("Enter value of n to find n-th name: ");
scanf("%d", &n);
fp = fopen("names.txt", "r");
if (!fp) exit(1);
// Assuming one name per line
while (fgets(name, sizeof(name), fp) != NULL)
{
current++;
if (current == n)
{
printf("The %d-th name is: %s", n, name);
found = 1;
break;
}
}
if (!found)
printf("Record not found (Only %d names exist).\n", current);
fclose(fp);
return 0;
}
void create_name_file()
{
FILE *f = fopen("names.txt", "w");
fprintf(f, "Alice\nBob\nCharlie\nDavid\nEve\nFrank\n");
fclose(f);
}
luc093.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Update Master file (Roll, Name) using Transaction file (Roll, Code Add/Delete). Both files are sorted by Roll.
*/
/* Let Us C, Chap- 19 (File Input/Output), Qn No.: B(i) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
struct student {
int roll;
char name[30];
};
struct trans {
int roll;
char code; // 'A' for Add, 'D' for Delete
char name[30]; // Only needed for Add
};
void create_files();
int main()
{
FILE *fm, *ft, *fn;
struct student m;
struct trans t;
int has_m, has_t;
create_files();
fm = fopen("MASTER.DAT", "rb");
ft = fopen("TRANS_ROLL.DAT", "rb");
fn = fopen("NEW_MASTER.DAT", "wb");
if (!fm || !ft || !fn) exit(1);
has_m = fread(&m, sizeof(struct student), 1, fm);
has_t = fread(&t, sizeof(struct trans), 1, ft);
printf("Merging Master and Transaction files...\n");
while (has_m && has_t)
{
if (m.roll < t.roll)
{
// No transaction for this master record, keep it
fwrite(&m, sizeof(struct student), 1, fn);
has_m = fread(&m, sizeof(struct student), 1, fm);
}
else if (m.roll == t.roll)
{
// Transaction affects this record
if (t.code == 'D')
{
printf("Deleting Roll %d\n", m.roll);
// Skip writing 'm' to file (Deleting)
has_m = fread(&m, sizeof(struct student), 1, fm);
}
else
{
// Logic error: Can't ADD if ID exists. Maybe Update?
// Assuming replace or skip. Let's skip T and keep M for now.
has_m = fread(&m, sizeof(struct student), 1, fm);
}
has_t = fread(&t, sizeof(struct trans), 1, ft);
}
else // m.roll > t.roll
{
// Transaction ID is new
if (t.code == 'A')
{
struct student new_s;
new_s.roll = t.roll;
strcpy(new_s.name, t.name);
fwrite(&new_s, sizeof(struct student), 1, fn);
printf("Adding Roll %d\n", new_s.roll);
}
has_t = fread(&t, sizeof(struct trans), 1, ft);
}
}
// Process remaining Master
while (has_m)
{
fwrite(&m, sizeof(struct student), 1, fn);
has_m = fread(&m, sizeof(struct student), 1, fm);
}
// Process remaining Transactions (Only Adds)
while (has_t)
{
if (t.code == 'A')
{
struct student new_s = {t.roll, ""};
strcpy(new_s.name, t.name);
fwrite(&new_s, sizeof(struct student), 1, fn);
printf("Adding Roll %d\n", new_s.roll);
}
has_t = fread(&t, sizeof(struct trans), 1, ft);
}
fclose(fm); fclose(ft); fclose(fn);
return 0;
}
void create_files()
{
struct student m[] = {{10, "A"}, {20, "B"}, {30, "C"}};
struct trans t[] = {{15, 'A', "NewGuy"}, {20, 'D', ""}, {40, 'A', "LastGuy"}};
FILE *f1 = fopen("MASTER.DAT", "wb");
fwrite(m, sizeof(struct student), 3, f1);
fclose(f1);
FILE *f2 = fopen("TRANS_ROLL.DAT", "wb");
fwrite(t, sizeof(struct trans), 3, f2);
fclose(f2);
}
luc094.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Read a text file, delete the words 'a', 'the', 'an' and replace each with a blank space. Write to new file.
*/
/* Let Us C, Chap- 19 (File Input/Output), Qn No.: B(j) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
void create_article_file();
int main()
{
FILE *fp, *ft;
char word[100];
create_article_file();
fp = fopen("articles.txt", "r");
ft = fopen("clean.txt", "w");
if (!fp || !ft) exit(1);
// Basic word-by-word processing using fscanf
// Note: fscanf skips whitespace, so original spacing formatting
// might be lost, but it effectively filters words.
while (fscanf(fp, "%s", word) != EOF)
{
if (strcasecmp(word, "a") == 0 ||
strcasecmp(word, "an") == 0 ||
strcasecmp(word, "the") == 0)
{
fputc(' ', ft); // Replace with blank
}
else
{
fprintf(ft, "%s ", word);
}
}
printf("Processed file. Articles removed in 'clean.txt'.\n");
fclose(fp);
fclose(ft);
return 0;
}
void create_article_file()
{
FILE *f = fopen("articles.txt", "w");
fprintf(f, "The quick brown fox jumps over a lazy dog. It was an honour.");
fclose(f);
}
luc095.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program that can read a file and display its contents. The file name should be supplied as a command-line argument.
*/
/* Let Us C, Chap- 20 (More Issues In Input/Output), Qn No.: A(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
int main(int argc, char *argv[])
{
FILE *fp;
char ch;
/* Check if file name is provided */
if (argc != 2)
{
printf("Usage: %s <filename>\n", argv[0]);
exit(1);
}
fp = fopen(argv[1], "r");
if (fp == NULL)
{
printf("Error: Cannot open file '%s'\n", argv[1]);
exit(2);
}
/* Read and display contents */
while ((ch = fgetc(fp)) != EOF)
{
printf("%c", ch);
}
fclose(fp);
return 0;
}
luc096.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program that can copy the contents of one file to another. The source and target filenames should be supplied as command-line arguments.
*/
/* Let Us C, Chap- 20 (More Issues In Input/Output), Qn No.: A(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
int main(int argc, char *argv[])
{
FILE *fs, *ft;
char ch;
/* Check for correct number of arguments */
if (argc != 3)
{
printf("Usage: %s <source_file> <target_file>\n", argv[0]);
exit(1);
}
fs = fopen(argv[1], "r");
if (fs == NULL)
{
printf("Error: Cannot open source file '%s'\n", argv[1]);
exit(2);
}
ft = fopen(argv[2], "w");
if (ft == NULL)
{
printf("Error: Cannot create target file '%s'\n", argv[2]);
fclose(fs);
exit(3);
}
/* Copy contents */
while ((ch = fgetc(fs)) != EOF)
{
fputc(ch, ft);
}
printf("File copied successfully.\n");
fclose(fs);
fclose(ft);
return 0;
}
luc097.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program using command-line arguments to search for a word in a file and replace it with the specified word.\nUsage: change <old word> <new word> <filename>
*/
/* Let Us C, Chap- 20 (More Issues In Input/Output), Qn No.: A(c) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
void replace_all(char *str, const char *old_w, const char *new_w, FILE *ft);
int main(int argc, char *argv[])
{
FILE *fp, *ft;
char line[1000];
char *old_word, *new_word, *filename;
if (argc != 4)
{
printf("Usage: %s <old word> <new word> <filename>\n", argv[0]);
exit(1);
}
old_word = argv[1];
new_word = argv[2];
filename = argv[3];
fp = fopen(filename, "r");
if (fp == NULL)
{
printf("Error opening file: %s\n", filename);
exit(2);
}
// Create a temporary file
ft = fopen("temp.tmp", "w");
if (ft == NULL)
{
printf("Error creating temporary file.\n");
fclose(fp);
exit(3);
}
// Process line by line
while (fgets(line, sizeof(line), fp))
{
replace_all(line, old_word, new_word, ft);
}
fclose(fp);
fclose(ft);
// Replace original file with updated file
remove(filename);
rename("temp.tmp", filename);
printf("Replacement complete.\n");
return 0;
}
void replace_all(char *str, const char *old_w, const char *new_w, FILE *ft)
{
char *pos, temp[1000];
int index = 0;
int old_len = strlen(old_w);
/* We cannot easily modify 'str' in place because new_w
might be larger than old_w. We write directly to file.
*/
while ((pos = strstr(str, old_w)) != NULL)
{
// Write everything before the match
while (str < pos)
{
fputc(*str, ft);
str++;
}
// Write the new word
fputs(new_w, ft);
// Skip the old word in the source string
str += old_len;
}
// Write the remainder of the line
fputs(str, ft);
}
luc098.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a calculator utility using command line arguments.\nUsage: calc <switch> <n> <m>\nwhere switch is arithmetic operator or comparison operator.
*/
/* Let Us C, Chap- 20 (More Issues In Input/Output), Qn No.: A(d) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
int main(int argc, char *argv[])
{
float n, m, res;
char operator;
if (argc != 4)
{
printf("Usage: %s <switch> <n> <m>\n", argv[0]);
printf("Example: %s + 10 20\n", argv[0]);
printf("Note: For multiplication (*), use '*' or x to avoid shell expansion.\n");
exit(1);
}
operator = argv[1][0]; // First character of the switch argument
n = atof(argv[2]);
m = atof(argv[3]);
switch (operator)
{
// Arithmetic
case '+':
printf("%.2f\n", n + m);
break;
case '-':
printf("%.2f\n", n - m);
break;
case 'x':
case '*':
printf("%.2f\n", n * m);
break;
case '/':
if (m == 0) printf("Error: Division by zero\n");
else printf("%.2f\n", n / m);
break;
case '%':
printf("%d\n", (int)n % (int)m);
break;
// Comparison
case '<':
printf("%s\n", (n < m) ? "True" : "False");
break;
case '>':
printf("%s\n", (n > m) ? "True" : "False");
break;
// Handling symbols that might be multi-char (e.g. <=, >=, ==) is tricky
// with argv[1][0], but basic logic for typical single char switches:
case '=':
printf("%s\n", (n == m) ? "True" : "False");
break;
default:
printf("Unknown operator: %c\n", operator);
break;
}
return 0;
}
luc099.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Read an integer 'game' representing sports won by a college. Determine if it won the 'Champion of Champions' trophy (>5 games) and list games won.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: A(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
int game;
int count = 0, i;
const char *sports[] = {
"Cricket", "Basketball", "Football", "Hockey",
"Lawn Tennis", "Table Tennis", "Carom", "Chess", "Volleyball" // Added one for bit 8
};
printf("Enter the game information (integer): ");
scanf("%d", &game);
printf("\nGames won:\n");
for (i = 0; i <= 8; i++)
{
if (game & (1 << i))
{
printf("- %s\n", sports[i]);
count++;
}
}
printf("\nTotal games won: %d\n", count);
if (count >= 5)
printf("Result: The college won the Champion of Champions trophy.\n");
else
printf("Result: The college did NOT win the trophy.\n");
return 0;
}
luc100.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Determine if an animal is Carnivore/Herbivore and its type (Canine, Feline, Cetacean, Marsupial) based on bits in an integer.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: A(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
struct animal
{
char name[30];
int type;
};
int main()
{
struct animal a = {"OCELOT", 18};
int type = a.type;
printf("Animal: %s\n", a.name);
// Check Bit 4 for Diet (Assuming 1=Carnivore, 0=Herbivore based on context)
if (type & (1 << 4))
printf("Diet: Carnivore\n");
else
printf("Diet: Herbivore\n");
// Check Bits 0-3 for Family
printf("Family: ");
if (type & (1 << 0)) printf("Canine ");
if (type & (1 << 1)) printf("Feline ");
if (type & (1 << 2)) printf("Cetacean ");
if (type & (1 << 3)) printf("Marsupial ");
printf("\n");
return 0;
}
luc101.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Decode student information (Year, Stream, Room No) packed into an integer array.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: A(c) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
int data[] = {273, 548, 786, 1096};
int n = 4, i;
int val, year, stream_bits, room;
for (i = 0; i < n; i++)
{
val = data[i];
// Room Number: Rest of the bits (Assuming starting from bit 8)
room = val >> 8;
printf("Student %d (Raw: %d):\n", i + 1, val);
printf(" Room No: %d\n", room);
// Year: Bits 0-3
printf(" Year: ");
if (val & (1 << 0)) printf("1st Year");
else if (val & (1 << 1)) printf("2nd Year");
else if (val & (1 << 2)) printf("3rd Year");
else if (val & (1 << 3)) printf("4th Year");
else printf("Unknown");
printf("\n");
// Stream: Bits 4-7 (Mech, Chem, Elec, CS)
printf(" Stream: ");
if (val & (1 << 4)) printf("Mechanical");
else if (val & (1 << 5)) printf("Chemical");
else if (val & (1 << 6)) printf("Electronics");
else if (val & (1 << 7)) printf("CS");
else printf("Unknown");
printf("\n\n");
}
return 0;
}
luc102.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* What will be the output of the provided program segment involving bitwise operators?
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: A(d) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
int i = 32, j = 65, k, l, m, n, o, p;
k = i | 35;
l = ~k;
m = i & j;
n = j ^ 32;
o = j << 2;
p = i >> 5;
printf("k = %d l = %d m = %d\n", k, l, m);
printf("n = %d o = %d p = %d\n", n, o, p);
return 0;
}
luc103.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* What is the hexadecimal equivalent of the following binary numbers?
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: B(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
// Binary numbers represented as string literals for reference
// 01011010
// 11000011
// 1010101001110101
// 111100001011010
printf("Binary: 01011010 -> Hex: 0x%X\n", 0b01011010);
printf("Binary: 11000011 -> Hex: 0x%X\n", 0b11000011);
printf("Binary: 1010101001110101 -> Hex: 0x%X\n", 0b1010101001110101);
printf("Binary: 111100001011010 -> Hex: 0x%X\n", 0b111100001011010);
/* Note: Binary literals (0b...) are a standard C extension (GCC) and part of C23 standard. */
return 0;
}
luc104.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Rewrite expressions using bitwise compound assignment operators.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: B(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
int a = 10, b = 20, c = 5;
printf("Original values: a=%d, b=%d, c=%d\n", a, b, c);
// a = a | 3
a |= 3;
printf("a |= 3 -> %d\n", a);
// a = a & 0x48
a &= 0x48;
printf("a &= 0x48 -> %d\n", a);
// b = b ^ 0x22
b ^= 0x22;
printf("b ^= 0x22 -> %d\n", b);
// c = c << 2
c <<= 2;
printf("c <<= 2 -> %d\n", c);
return 0;
}
luc105.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a function checkbits(x, p, n) which returns true if all 'n' bits starting from position 'p' are turned on.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: B(c) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int checkbits(unsigned int x, int p, int n);
int main()
{
unsigned int x;
int p, n;
printf("Enter number (x): ");
scanf("%u", &x);
printf("Enter starting position (p) and count (n): ");
scanf("%d %d", &p, &n);
if (checkbits(x, p, n))
printf("TRUE: %d bits starting at %d are ON.\n", n, p);
else
printf("FALSE: Not all specified bits are ON.\n");
return 0;
}
int checkbits(unsigned int x, int p, int n)
{
unsigned int mask;
// Create a mask of n 1s. E.g., if n=3, mask=000...0111
mask = (1 << n) - 1;
// Shift mask to position p
mask = mask << p;
// Check if bits in x match the mask
return (x & mask) == mask;
}
luc106.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to scan an 8-bit number and check whether its 3rd, 6th and 7th bit is on.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: B(d) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
unsigned char num;
printf("Enter an 8-bit integer (0-255): ");
scanf("%hhu", &num);
// Checking bits 3, 6, 7.
// Assuming 0-based indexing: 3rd bit is index 3 (value 8), 6th is index 6 (64), 7th is index 7 (128).
unsigned char mask = (1 << 3) | (1 << 6) | (1 << 7);
if ((num & mask) == mask)
printf("Bits 3, 6, and 7 are ALL ON.\n");
else
printf("Bits 3, 6, and 7 are NOT all on.\n");
return 0;
}
luc107.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Receive an unsigned 16-bit integer and exchange the contents of its 2 bytes using bitwise operators.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: B(e) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
unsigned short num, swapped;
printf("Enter a 16-bit number (0-65535): ");
scanf("%hu", &num);
// Exchange bytes:
// 1. (num & 0xFF00) >> 8 : Move High Byte to Low Byte position
// 2. (num & 0x00FF) << 8 : Move Low Byte to High Byte position
swapped = ((num & 0xFF00) >> 8) | ((num & 0x00FF) << 8);
printf("Original: %hu (Hex: 0x%04X)\n", num, num);
printf("Swapped: %hu (Hex: 0x%04X)\n", swapped, swapped);
return 0;
}
luc108.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Receive an 8-bit number and exchange its higher 4 bits with lower 4 bits.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: B(f) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
unsigned char num, swapped;
printf("Enter an 8-bit number (0-255): ");
scanf("%hhu", &num);
// Exchange nibbles
// (num & 0xF0) >> 4 : High nibble to Low
// (num & 0x0F) << 4 : Low nibble to High
swapped = ((num & 0xF0) >> 4) | ((num & 0x0F) << 4);
printf("Original: %d (Hex: 0x%02X)\n", num, num);
printf("Swapped: %d (Hex: 0x%02X)\n", swapped, swapped);
return 0;
}
luc109.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Receive an 8-bit number and set its odd bits to 1.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: B(g) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
unsigned char num, res;
printf("Enter an 8-bit number: ");
scanf("%hhu", &num);
// Odd bits usually refer to positions 1, 3, 5, 7.
// Mask: 1010 1010 (binary) = 0xAA
// OR operation sets bits to 1.
res = num | 0xAA;
printf("Original: 0x%02X\n", num);
printf("Result: 0x%02X\n", res);
return 0;
}
luc110.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Receive an 8-bit number. Check if 3rd and 5th bits are ON. If yes, put them OFF.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: B(h) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
unsigned char num;
unsigned char mask = (1 << 3) | (1 << 5); // Bits 3 and 5
printf("Enter an 8-bit number: ");
scanf("%hhu", &num);
if ((num & mask) == mask)
{
printf("Bits 3 and 5 are ON. Turning them OFF...\n");
// XOR with mask toggles 1 to 0 (since they are 1)
// OR: AND with complement mask (~mask)
num = num & ~mask;
}
else
{
printf("Bits 3 and 5 are NOT both ON. No change.\n");
}
printf("Final Value: %d (0x%02X)\n", num, num);
return 0;
}
luc111.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Receive an 8-bit number. Check if 3rd and 5th bits are OFF. If yes, put them ON.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: B(i) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
unsigned char num;
unsigned char mask = (1 << 3) | (1 << 5);
printf("Enter an 8-bit number: ");
scanf("%hhu", &num);
// Check if bits are OFF. (num & mask) should be 0.
if ((num & mask) == 0)
{
printf("Bits 3 and 5 are OFF. Turning them ON...\n");
num = num | mask;
}
else
{
printf("Bits 3 and 5 are NOT both OFF. No change.\n");
}
printf("Final Value: %d (0x%02X)\n", num, num);
return 0;
}
luc112.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Rewrite the showbits() function using the _BV macro.
*/
/* Let Us C, Chap- 21 (Operations on Bits), Qn No.: B(j) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
/* _BV(x) macro usually expands to (1 << x) */
#define _BV(x) (1 << x)
void showbits(unsigned char n);
int main()
{
unsigned char num;
printf("Enter an 8-bit number: ");
scanf("%hhu", &num);
printf("Binary representation: ");
showbits(num);
printf("\n");
return 0;
}
void showbits(unsigned char n)
{
int i;
unsigned char mask;
for (i = 7; i >= 0; i--)
{
mask = _BV(i);
if ((n & mask) == 0)
printf("0");
else
printf("1");
}
}
luc113.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Store date in a structure using bit fields (day: 5 bits, month: 4 bits, year: 12 bits). Read joining dates of 10 employees and display them sorted by year.
*/
/* Let Us C, Chap- 22 (Miscellaneous Features), Qn No.: C(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
// Define structure with bit-fields
struct date
{
unsigned int day : 5; // 1-31 takes 5 bits
unsigned int month : 4; // 1-12 takes 4 bits
unsigned int year : 12; // Sufficient for year 0-4095
};
struct employee
{
char name[30];
struct date doj; // Date of Joining
};
int compare_dates(const void *a, const void *b);
int main()
{
struct employee emp[10];
int i;
// Temporary variables for input because we cannot take address of a bit-field
int d, m, y;
printf("Enter details for 10 employees:\n");
for (i = 0; i < 10; i++)
{
printf("\nEmployee %d Name: ", i + 1);
scanf("%s", emp[i].name);
printf("Date of Joining (dd mm yyyy): ");
scanf("%d %d %d", &d, &m, &y);
// Assign to bit-fields
emp[i].doj.day = d;
emp[i].doj.month = m;
emp[i].doj.year = y;
}
// Sort based on year using qsort
qsort(emp, 10, sizeof(struct employee), compare_dates);
printf("\n--- Employees Sorted by Joining Year ---\n");
for (i = 0; i < 10; i++)
{
printf("%-15s | DOJ: %02d-%02d-%d\n",
emp[i].name, emp[i].doj.day, emp[i].doj.month, emp[i].doj.year);
}
return 0;
}
int compare_dates(const void *a, const void *b)
{
struct employee *e1 = (struct employee *)a;
struct employee *e2 = (struct employee *)b;
// Primary sort by Year
if (e1->doj.year != e2->doj.year)
return e1->doj.year - e2->doj.year;
// Secondary sort by Month
if (e1->doj.month != e2->doj.month)
return e1->doj.month - e2->doj.month;
// Tertiary sort by Day
return e1->doj.day - e2->doj.day;
}
luc114.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Store insurance policy holder info (gender, minor/major, policy name, duration) using bit-fields.
*/
/* Let Us C, Chap- 22 (Miscellaneous Features), Qn No.: C(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
// Define structure with bit-fields
struct policy_holder
{
char policy_name[50];
unsigned int duration : 7; // 0-127 years is sufficient for policy duration
unsigned int gender : 1; // 0: Male, 1: Female (1 bit)
unsigned int status : 1; // 0: Minor, 1: Major (1 bit)
};
int main()
{
struct policy_holder p;
int temp_gen, temp_stat, temp_dur;
printf("--- Enter Policy Holder Details ---\n");
printf("Policy Name: ");
scanf(" %[^\n]s", p.policy_name); // Reads string with spaces
printf("Duration (Years): ");
scanf("%d", &temp_dur);
p.duration = temp_dur;
printf("Gender (0 for Male, 1 for Female): ");
scanf("%d", &temp_gen);
p.gender = temp_gen;
printf("Status (0 for Minor, 1 for Major): ");
scanf("%d", &temp_stat);
p.status = temp_stat;
printf("\n--- Policy Information Stored ---\n");
printf("Policy: %s\n", p.policy_name);
printf("Duration: %u years\n", p.duration);
// Interpret bits for display
printf("Gender: %s\n", (p.gender == 1) ? "Female" : "Male");
printf("Status: %s\n", (p.status == 1) ? "Major" : "Minor");
printf("\nSize of structure: %zu bytes\n", sizeof(p));
// Note: Size will be policy_name size + padding + integer size containing the bits
return 0;
}
luc115.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Obtain MD5 checksum of the following strings and check whether they are same:
"Six slippery snails slid slowly seaward."
"Six silppery snails slid slowly seaward."
*/
/* Let Us C, Chap- 23 (Security Programming), Qn No.: D(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdint.h>
/* * Self-contained MD5 Implementation
* Based on the public domain reference implementation (RFC 1321) logic.
*/
// --- MD5 Implementation Start ---
typedef struct {
uint64_t size; // Size of input in bytes
uint32_t buffer[4]; // Current accumulation of hash
uint8_t input[64]; // Input to be processed
} MD5Context;
#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
#define H(x, y, z) ((x) ^ (y) ^ (z))
#define I(x, y, z) ((y) ^ ((x) | (~z)))
#define ROTL(x, s) (((x) << (s)) | ((x) >> (32 - (s))))
#define STEP(f, a, b, c, d, x, t, s) \
(a) += f((b), (c), (d)) + (x) + (t); \
(a) = ROTL((a), (s)); \
(a) += (b);
void md5Transform(uint32_t state[4], const uint8_t block[64]) {
uint32_t a = state[0], b = state[1], c = state[2], d = state[3], x[16];
int i, j;
// Decode block into x
for (i = 0, j = 0; j < 64; i++, j += 4)
x[i] = ((uint32_t)block[j]) | (((uint32_t)block[j + 1]) << 8) |
(((uint32_t)block[j + 2]) << 16) | (((uint32_t)block[j + 3]) << 24);
// Round 1
STEP(F, a, b, c, d, x[0], 0xd76aa478, 7);
STEP(F, d, a, b, c, x[1], 0xe8c7b756, 12);
STEP(F, c, d, a, b, x[2], 0x242070db, 17);
STEP(F, b, c, d, a, x[3], 0xc1bdceee, 22);
STEP(F, a, b, c, d, x[4], 0xf57c0faf, 7);
STEP(F, d, a, b, c, x[5], 0x4787c62a, 12);
STEP(F, c, d, a, b, x[6], 0xa8304613, 17);
STEP(F, b, c, d, a, x[7], 0xfd469501, 22);
STEP(F, a, b, c, d, x[8], 0x698098d8, 7);
STEP(F, d, a, b, c, x[9], 0x8b44f7af, 12);
STEP(F, c, d, a, b, x[10], 0xffff5bb1, 17);
STEP(F, b, c, d, a, x[11], 0x895cd7be, 22);
STEP(F, a, b, c, d, x[12], 0x6b901122, 7);
STEP(F, d, a, b, c, x[13], 0xfd987193, 12);
STEP(F, c, d, a, b, x[14], 0xa679438e, 17);
STEP(F, b, c, d, a, x[15], 0x49b40821, 22);
// Round 2
STEP(G, a, b, c, d, x[1], 0xf61e2562, 5);
STEP(G, d, a, b, c, x[6], 0xc040b340, 9);
STEP(G, c, d, a, b, x[11], 0x265e5a51, 14);
STEP(G, b, c, d, a, x[0], 0xe9b6c7aa, 20);
STEP(G, a, b, c, d, x[5], 0xd62f105d, 5);
STEP(G, d, a, b, c, x[10], 0x02441453, 9);
STEP(G, c, d, a, b, x[15], 0xd8a1e681, 14);
STEP(G, b, c, d, a, x[4], 0xe7d3fbc8, 20);
STEP(G, a, b, c, d, x[9], 0x21e1cde6, 5);
STEP(G, d, a, b, c, x[14], 0xc33707d6, 9);
STEP(G, c, d, a, b, x[3], 0xf4d50d87, 14);
STEP(G, b, c, d, a, x[8], 0x455a14ed, 20);
STEP(G, a, b, c, d, x[13], 0xa9e3e905, 5);
STEP(G, d, a, b, c, x[2], 0xfcefa3f8, 9);
STEP(G, c, d, a, b, x[7], 0x676f02d9, 14);
STEP(G, b, c, d, a, x[12], 0x8d2a4c8a, 20);
// Round 3
STEP(H, a, b, c, d, x[5], 0xfffa3942, 4);
STEP(H, d, a, b, c, x[8], 0x8771f681, 11);
STEP(H, c, d, a, b, x[11], 0x6d9d6122, 16);
STEP(H, b, c, d, a, x[14], 0xfde5380c, 23);
STEP(H, a, b, c, d, x[1], 0xa4beea44, 4);
STEP(H, d, a, b, c, x[4], 0x4bdecfa9, 11);
STEP(H, c, d, a, b, x[7], 0xf6bb4b60, 16);
STEP(H, b, c, d, a, x[10], 0xbebfbc70, 23);
STEP(H, a, b, c, d, x[13], 0x289b7ec6, 4);
STEP(H, d, a, b, c, x[0], 0xeaa127fa, 11);
STEP(H, c, d, a, b, x[3], 0xd4ef3085, 16);
STEP(H, b, c, d, a, x[6], 0x04881d05, 23);
STEP(H, a, b, c, d, x[9], 0xd9d4d039, 4);
STEP(H, d, a, b, c, x[12], 0xe6db99e5, 11);
STEP(H, c, d, a, b, x[15], 0x1fa27cf8, 16);
STEP(H, b, c, d, a, x[2], 0xc4ac5665, 23);
// Round 4
STEP(I, a, b, c, d, x[0], 0xf4292244, 6);
STEP(I, d, a, b, c, x[7], 0x432aff97, 10);
STEP(I, c, d, a, b, x[14], 0xab9423a7, 15);
STEP(I, b, c, d, a, x[5], 0xfc93a039, 21);
STEP(I, a, b, c, d, x[12], 0x655b59c3, 6);
STEP(I, d, a, b, c, x[3], 0x8f0ccc92, 10);
STEP(I, c, d, a, b, x[10], 0xffeff47d, 15);
STEP(I, b, c, d, a, x[1], 0x85845dd1, 21);
STEP(I, a, b, c, d, x[8], 0x6fa87e4f, 6);
STEP(I, d, a, b, c, x[15], 0xfe2ce6e0, 10);
STEP(I, c, d, a, b, x[6], 0xa3014314, 15);
STEP(I, b, c, d, a, x[13], 0x4e0811a1, 21);
STEP(I, a, b, c, d, x[4], 0xf7537e82, 6);
STEP(I, d, a, b, c, x[11], 0xbd3af235, 10);
STEP(I, c, d, a, b, x[2], 0x2ad7d2bb, 15);
STEP(I, b, c, d, a, x[9], 0xeb86d391, 21);
state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;
}
void md5Init(MD5Context *ctx) {
ctx->size = 0;
ctx->buffer[0] = 0x67452301;
ctx->buffer[1] = 0xefcdab89;
ctx->buffer[2] = 0x98badcfe;
ctx->buffer[3] = 0x10325476;
}
void md5Update(MD5Context *ctx, const uint8_t *input, size_t inputLen) {
size_t i, index, partLen;
index = (size_t)((ctx->size >> 3) & 0x3f);
ctx->size += (uint64_t)inputLen * 8;
partLen = 64 - index;
if (inputLen >= partLen) {
memcpy(&ctx->input[index], input, partLen);
md5Transform(ctx->buffer, ctx->input);
for (i = partLen; i + 63 < inputLen; i += 64)
md5Transform(ctx->buffer, &input[i]);
index = 0;
} else {
i = 0;
}
memcpy(&ctx->input[index], &input[i], inputLen - i);
}
void md5Final(uint8_t digest[16], MD5Context *ctx) {
uint8_t bits[8];
size_t index, padLen;
static const uint8_t PADDING[64] = {0x80}; // Remaining zeros implicit
// Save number of bits
for (int i = 0; i < 8; i++)
bits[i] = (uint8_t)((ctx->size >> (i * 8)) & 0xff);
index = (size_t)((ctx->size >> 3) & 0x3f);
padLen = (index < 56) ? (56 - index) : (120 - index);
md5Update(ctx, PADDING, padLen);
md5Update(ctx, bits, 8);
// Encode state into digest
for (int i = 0; i < 16; i++)
digest[i] = (uint8_t)((ctx->buffer[i >> 2] >> ((i & 3) * 8)) & 0xff);
}
// --- MD5 Implementation End ---
void print_hash(uint8_t *digest) {
for (int i = 0; i < 16; i++) printf("%02x", digest[i]);
printf("\n");
}
int main() {
char str1[] = "Six slippery snails slid slowly seaward.";
char str2[] = "Six silppery snails slid slowly seaward."; // Typo 'silppery'
uint8_t hash1[16], hash2[16];
MD5Context ctx;
printf("String 1: %s\n", str1);
md5Init(&ctx);
md5Update(&ctx, (uint8_t*)str1, strlen(str1));
md5Final(hash1, &ctx);
printf("MD5: ");
print_hash(hash1);
printf("\nString 2: %s\n", str2);
md5Init(&ctx);
md5Update(&ctx, (uint8_t*)str2, strlen(str2));
md5Final(hash2, &ctx);
printf("MD5: ");
print_hash(hash2);
// Compare
int same = 1;
for(int i=0; i<16; i++) if(hash1[i] != hash2[i]) same = 0;
printf("\nConclusion: The MD5 checksums are %s.\n", same ? "IDENTICAL" : "DIFFERENT");
if (!same) printf("(Even a small change in input creates a completely different hash)\n");
return 0;
}
luc116.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Compile any C program into a .EXE or a .out file. Obtain SHA256 checksum of the file.
*/
/* Let Us C, Chap- 23 (Security Programming), Qn No.: D(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdint.h>
/* * Self-contained SHA-256 Implementation
* Based on FIPS 180-2 reference logic.
*/
// --- SHA256 Implementation Start ---
typedef struct {
uint8_t data[64];
uint32_t datalen;
uint64_t bitlen;
uint32_t state[8];
} SHA256_CTX;
#define ROTRIGHT(a,b) (((a) >> (b)) | ((a) << (32-(b))))
#define CH(x,y,z) (((x) & (y)) ^ (~(x) & (z)))
#define MAJ(x,y,z) (((x) & (y)) ^ ((x) & (z)) ^ ((y) & (z)))
#define EP0(x) (ROTRIGHT(x,2) ^ ROTRIGHT(x,13) ^ ROTRIGHT(x,22))
#define EP1(x) (ROTRIGHT(x,6) ^ ROTRIGHT(x,11) ^ ROTRIGHT(x,25))
#define SIG0(x) (ROTRIGHT(x,7) ^ ROTRIGHT(x,18) ^ ((x) >> 3))
#define SIG1(x) (ROTRIGHT(x,17) ^ ROTRIGHT(x,19) ^ ((x) >> 10))
static const uint32_t K[64] = {
0x428a2f98,0x71374491,0xb5c0fbcf,0xe9b5dba5,0x3956c25b,0x59f111f1,0x923f82a4,0xab1c5ed5,
0xd807aa98,0x12835b01,0x243185be,0x550c7dc3,0x72be5d74,0x80deb1fe,0x9bdc06a7,0xc19bf174,
0xe49b69c1,0xefbe4786,0x0fc19dc6,0x240ca1cc,0x2de92c6f,0x4a7484aa,0x5cb0a9dc,0x76f988da,
0x983e5152,0xa831c66d,0xb00327c8,0xbf597fc7,0xc6e00bf3,0xd5a79147,0x06ca6351,0x14292967,
0x27b70a85,0x2e1b2138,0x4d2c6dfc,0x53380d13,0x650a7354,0x766a0abb,0x81c2c92e,0x92722c85,
0xa2bfe8a1,0xa81a664b,0xc24b8b70,0xc76c51a3,0xd192e819,0xd6990624,0xf40e3585,0x106aa070,
0x19a4c116,0x1e376c08,0x2748774c,0x34b0bcb5,0x391c0cb3,0x4ed8aa4a,0x5b9cca4f,0x682e6ff3,
0x748f82ee,0x78a5636f,0x84c87814,0x8cc70208,0x90befffa,0xa4506ceb,0xbef9a3f7,0xc67178f2
};
void sha256_transform(SHA256_CTX *ctx, const uint8_t data[]) {
uint32_t a, b, c, d, e, f, g, h, i, j, t1, t2, m[64];
for (i = 0, j = 0; i < 16; ++i, j += 4)
m[i] = (data[j] << 24) | (data[j + 1] << 16) | (data[j + 2] << 8) | (data[j + 3]);
for (; i < 64; ++i)
m[i] = SIG1(m[i - 2]) + m[i - 7] + SIG0(m[i - 15]) + m[i - 16];
a = ctx->state[0]; b = ctx->state[1]; c = ctx->state[2]; d = ctx->state[3];
e = ctx->state[4]; f = ctx->state[5]; g = ctx->state[6]; h = ctx->state[7];
for (i = 0; i < 64; ++i) {
t1 = h + EP1(e) + CH(e, f, g) + K[i] + m[i];
t2 = EP0(a) + MAJ(a, b, c);
h = g; g = f; f = e; e = d + t1;
d = c; c = b; b = a; a = t1 + t2;
}
ctx->state[0] += a; ctx->state[1] += b; ctx->state[2] += c; ctx->state[3] += d;
ctx->state[4] += e; ctx->state[5] += f; ctx->state[6] += g; ctx->state[7] += h;
}
void sha256_init(SHA256_CTX *ctx) {
ctx->datalen = 0;
ctx->bitlen = 0;
ctx->state[0] = 0x6a09e667; ctx->state[1] = 0xbb67ae85;
ctx->state[2] = 0x3c6ef372; ctx->state[3] = 0xa54ff53a;
ctx->state[4] = 0x510e527f; ctx->state[5] = 0x9b05688c;
ctx->state[6] = 0x1f83d9ab; ctx->state[7] = 0x5be0cd19;
}
void sha256_update(SHA256_CTX *ctx, const uint8_t data[], size_t len) {
for (size_t i = 0; i < len; ++i) {
ctx->data[ctx->datalen] = data[i];
ctx->datalen++;
if (ctx->datalen == 64) {
sha256_transform(ctx, ctx->data);
ctx->bitlen += 512;
ctx->datalen = 0;
}
}
}
void sha256_final(SHA256_CTX *ctx, uint8_t hash[]) {
uint32_t i = ctx->datalen;
if (ctx->datalen < 56) {
ctx->data[i++] = 0x80;
while (i < 56) ctx->data[i++] = 0x00;
} else {
ctx->data[i++] = 0x80;
while (i < 64) ctx->data[i++] = 0x00;
sha256_transform(ctx, ctx->data);
memset(ctx->data, 0, 56);
}
ctx->bitlen += ctx->datalen * 8;
ctx->data[63] = ctx->bitlen;
ctx->data[62] = ctx->bitlen >> 8;
ctx->data[61] = ctx->bitlen >> 16;
ctx->data[60] = ctx->bitlen >> 24;
ctx->data[59] = ctx->bitlen >> 32;
ctx->data[58] = ctx->bitlen >> 40;
ctx->data[57] = ctx->bitlen >> 48;
ctx->data[56] = ctx->bitlen >> 56;
sha256_transform(ctx, ctx->data);
for (i = 0; i < 4; ++i) {
hash[i] = (ctx->state[0] >> (24 - i * 8)) & 0x000000ff;
hash[i + 4] = (ctx->state[1] >> (24 - i * 8)) & 0x000000ff;
hash[i + 8] = (ctx->state[2] >> (24 - i * 8)) & 0x000000ff;
hash[i + 12] = (ctx->state[3] >> (24 - i * 8)) & 0x000000ff;
hash[i + 16] = (ctx->state[4] >> (24 - i * 8)) & 0x000000ff;
hash[i + 20] = (ctx->state[5] >> (24 - i * 8)) & 0x000000ff;
hash[i + 24] = (ctx->state[6] >> (24 - i * 8)) & 0x000000ff;
hash[i + 28] = (ctx->state[7] >> (24 - i * 8)) & 0x000000ff;
}
}
// --- SHA256 Implementation End ---
int main(int argc, char *argv[]) {
FILE *fp;
char filename[100];
uint8_t buffer[1024];
size_t bytesRead;
SHA256_CTX ctx;
uint8_t hash[32];
int i;
// Get filename
if (argc < 2) {
printf("Enter filename to checksum (e.g., this_program.exe): ");
scanf("%s", filename);
} else {
strcpy(filename, argv[1]);
}
fp = fopen(filename, "rb"); // Open in binary mode
if (fp == NULL) {
printf("Error: Could not open file '%s'\n", filename);
return 1;
}
sha256_init(&ctx);
while ((bytesRead = fread(buffer, 1, sizeof(buffer), fp)) > 0) {
sha256_update(&ctx, buffer, bytesRead);
}
sha256_final(&ctx, hash);
fclose(fp);
printf("SHA256 Checksum of '%s':\n", filename);
for (i = 0; i < 32; i++) {
printf("%02x", hash[i]);
}
printf("\n");
return 0;
}
luc117.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to convert a given text into an audio file using OpenAI Audio API (TTS).
*/
/* Let Us C, Chap- 24 (Interaction with ChatGPT through C), Qn No.: B(a) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
/* NOTE: These programs require the 'libcurl' library to compile.
Command: gcc luc117.c -o output -lcurl */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <curl/curl.h>
/* Pre-requisites:
1. Install libcurl development package.
2. Get OpenAI API Key.
*/
#define API_KEY "YOUR_OPENAI_API_KEY_HERE"
size_t write_data(void *ptr, size_t size, size_t nmemb, FILE *stream) {
size_t written = fwrite(ptr, size, nmemb, stream);
return written;
}
int main(void) {
CURL *curl;
CURLcode res;
FILE *fp;
// JSON Payload construction
const char *url = "https://api.openai.com/v1/audio/speech";
const char *data = "{"
"\"model\": \"tts-1\","
"\"input\": \"Hello! This is a C program talking to you.\","
"\"voice\": \"alloy\""
"}";
struct curl_slist *headers = NULL;
char auth_header[100];
sprintf(auth_header, "Authorization: Bearer %s", API_KEY);
curl_global_init(CURL_GLOBAL_ALL);
curl = curl_easy_init();
if(curl) {
// Set Headers
headers = curl_slist_append(headers, "Content-Type: application/json");
headers = curl_slist_append(headers, auth_header);
// Open file to save audio
fp = fopen("output_audio.mp3", "wb");
if(!fp) {
printf("Error opening file for writing.\n");
return 1;
}
// Configure CURL
curl_easy_setopt(curl, CURLOPT_URL, url);
curl_easy_setopt(curl, CURLOPT_POSTFIELDS, data);
curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headers);
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_data);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, fp);
// Perform Request
printf("Sending request to OpenAI TTS API...\n");
res = curl_easy_perform(curl);
if(res != CURLE_OK)
fprintf(stderr, "curl_easy_perform() failed: %s\n", curl_easy_strerror(res));
else
printf("Audio saved to 'output_audio.mp3' successfully.\n");
// Cleanup
fclose(fp);
curl_slist_free_all(headers);
curl_easy_cleanup(curl);
}
curl_global_cleanup();
return 0;
}
luc118.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to generate 4 images of birds flying in the sky with a computer's mouse in their beak using OpenAI Image API.
*/
/* Let Us C, Chap- 24 (Interaction with ChatGPT through C), Qn No.: B(b) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
/* NOTE: These programs require the 'libcurl' library to compile.
Command: gcc luc118.c -o output -lcurl */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <curl/curl.h>
/* Pre-requisites:
1. Install libcurl.
2. Get OpenAI API Key.
*/
#define API_KEY "YOUR_OPENAI_API_KEY_HERE"
int main(void) {
CURL *curl;
CURLcode res;
const char *url = "https://api.openai.com/v1/images/generations";
// JSON Payload: 4 images, 1024x1024
const char *data = "{"
"\"prompt\": \"Birds flying in the sky with a computer mouse in their beak\","
"\"n\": 4,"
"\"size\": \"1024x1024\""
"}";
struct curl_slist *headers = NULL;
char auth_header[100];
sprintf(auth_header, "Authorization: Bearer %s", API_KEY);
curl = curl_easy_init();
if(curl) {
headers = curl_slist_append(headers, "Content-Type: application/json");
headers = curl_slist_append(headers, auth_header);
curl_easy_setopt(curl, CURLOPT_URL, url);
curl_easy_setopt(curl, CURLOPT_POSTFIELDS, data);
curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headers);
// For simplicity, we print the JSON response to stdout.
// The response will contain URLs to the generated images.
printf("Sending request to OpenAI Image API...\n\n");
res = curl_easy_perform(curl);
if(res != CURLE_OK)
fprintf(stderr, "curl_easy_perform() failed: %s\n", curl_easy_strerror(res));
printf("\n\nCheck the JSON output above for 'url' fields to view images.\n");
curl_slist_free_all(headers);
curl_easy_cleanup(curl);
}
return 0;
}
luc119.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 08 Feb 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to analyse a given sentence to detect the mood of the sentence using OpenAI Chat Completion API.
*/
/* Let Us C, Chap- 24 (Interaction with ChatGPT through C), Qn No.: B(c) */
/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */
/* NOTE: These programs require the 'libcurl' library to compile.
Command: gcc luc119.c -o output -lcurl */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <curl/curl.h>
/* Pre-requisites:
1. Install libcurl.
2. Get OpenAI API Key.
*/
#define API_KEY "YOUR_OPENAI_API_KEY_HERE"
int main(void) {
CURL *curl;
CURLcode res;
const char *url = "https://api.openai.com/v1/chat/completions";
/* We construct the JSON payload manually.
System prompt instructs the model to detect mood.
User prompt is the sentence to analyze.
*/
const char *data = "{"
"\"model\": \"gpt-3.5-turbo\","
"\"messages\": ["
" {\"role\": \"system\", \"content\": \"You are a helpful assistant. Analyze the mood of the user input sentence. Return only the mood keywords (e.g., admiration, appreciation, anger, joy).\"},"
" {\"role\": \"user\", \"content\": \"I am so impressed by your performance\"}"
"]"
"}";
struct curl_slist *headers = NULL;
char auth_header[100];
sprintf(auth_header, "Authorization: Bearer %s", API_KEY);
curl = curl_easy_init();
if(curl) {
headers = curl_slist_append(headers, "Content-Type: application/json");
headers = curl_slist_append(headers, auth_header);
curl_easy_setopt(curl, CURLOPT_URL, url);
curl_easy_setopt(curl, CURLOPT_POSTFIELDS, data);
curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headers);
printf("Analyzing sentence: 'I am so impressed by your performance'\n");
printf("Waiting for OpenAI response...\n\n");
// The response will be printed to standard output
res = curl_easy_perform(curl);
if(res != CURLE_OK)
fprintf(stderr, "curl_easy_perform() failed: %s\n", curl_easy_strerror(res));
printf("\n\n(Parse the JSON above to extract the 'content' field)\n");
curl_slist_free_all(headers);
curl_easy_cleanup(curl);
}
return 0;
}
lucproblem001.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Consider a currency system in which there are notes of six denominations,
namely, Rs. 1, Rs. 2, rs. 5, Rs. 10, Rs. 50, Rs. 100. If a sum
of Rs. N is entered through the keyboard, Write a program to compute
the smallest number of notes that will combine to give Rs. N. */
/* Let Us C, Chap - 2, Page - 22, Problem 2.3 */
#include <stdio.h>
int main()
{
int n, nonotes, temp;
printf("Enter the amount : ");
scanf("%d", &n);
if (n < 1)
{
printf("\nAmount should be a positive integer.");
return 1;
}
temp = n;
nonotes = n / 100;
n = n % 100;
nonotes = nonotes + (n / 50);
n = n % 50;
nonotes = nonotes + (n / 10);
n = n % 10;
nonotes = nonotes + (n / 5);
n = n % 5;
nonotes = nonotes + (n / 2);
n = n % 2;
nonotes = nonotes + n;
printf("\nthe smallest number of notes that will combine to give Rs. %d : %d", temp, nonotes);
return 0;
}
lucproblem002.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* A year is entered through the keyboard, write a program to
determine whether the year is leap or not. Use the logical operators
&& and || . */
/* Let Us C, Chap - 4, Page - 64, Problem 4.1 */
#include <stdio.h>
int main()
{
int year;
printf("Enter year : ");
scanf("%d", &year);
if (year % 4 == 0 && year & 100 != 0 || year % 400 == 0)
printf("\nYear %d is a leapyear.", year);
else
printf("\nYear %d is not a leapyear.", year);
return 0;
}
lucproblem003.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* If a character is entered through the keyboard, Write a program
to determine whether the character is a capital letter, a small case letter,
a digit or a speacial symbol.
The following table shows the range of ASCII values for various characters :
Characters ASCII Values
A - Z 65 - 90
a - z 97 - 122
0 - 9 48 - 57
special symbols 0 - 47, 58 - 64, 91 - 96, 123 - 127
*/
/* Let Us C, Chap - 4, Page - 65, Problem 4.2 */
#include <stdio.h>
int main()
{
char inp;
printf("Enter one character : ");
scanf(" %c", &inp);
if (inp >= 64 && inp <= 90)
printf("\nInput '%c' is a CAPITAL LETTER.", inp);
if (inp >= 97 && inp <= 122)
printf("\nInput '%c' is a SMALL CASE LETTER.", inp);
if (inp >= 48 && inp <= 57)
printf("\nInput '%c' is a DIGIT.", inp);
if (inp >= 0 && inp <= 47 || inp >= 58 && inp <= 64
|| inp >= 91 && inp <= 96 || inp >= 123 && inp <= 127)
printf("\nInput '%c' is a SPECIAL SYMBOL.", inp);
return 0;
}
lucproblem004.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* If the lengths of three sides of a triangle are entered through the
keyboard, write a program to check whether the triangle is valid or not.
The triangle is valid if the sum of two sides is greater that the largest
of the three sides. */
/* Let Us C, Chap - 4, Page - 66, Problem 4.3 */
#include <stdio.h>
int main()
{
double side1, side2, side3;
printf("Enter the length of side1, side2 and side3 of the triangle : ");
scanf("%lf %lf %lf", &side1, &side2, &side3);
if (side1 <= 0 || side2 <= 0 || side3 <= 0)
{
printf("\nTriangle sides must be positive.\n");
return 1;
}
if ((side1 + side2 > side3) && (side1 + side3 > side2) && (side2 + side3 > side1))
// Triangle Inequality Theorem
printf("\nThis triangle is valid.");
else
printf("\nThis triangle is not valid.");
return 0;
}
lucproblem005.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to calculate overtime pay of 10 employees. Overtime is
paid at the rate of Rs. 120.00 per hour for every hour worked above 40
hours. Assume that employees do not work for fractional part of an hour. */
/* ONLY WHILE LOOP ALLOWED */
/* Let Us C, Chap - 5, Page - 83, Problem 5.1 */
#include <stdio.h>
#include <conio.h>
int main()
{
int working_hour, i = 1;
double pay;
while (i <= 10)
{
printf("Enter the working hour for the employee no. %d : ", i);
if (scanf("%d", &working_hour) != 1)
{
printf("\n\tPlease enter a number as woking hour.\n\n");
while (getchar() != '\n')
;
// above line discard the input characters untill getchar() reaches the new line character.
/* if I do not discard the input, after 'continue;' statement that input will be again taken
by scanf (In the line 17). It will be a infinite loop of error. */
continue;
}
// checking overtime
if (working_hour > 40)
{
pay = (working_hour - 40) * 120.00;
printf("\n\tOvertime working hours of Employee %d : %d", i, (working_hour - 40));
printf("\n\tPay of the overtime for Employee %d : Rs. %.2f\n\n", i, pay);
}
else
printf("\n\tEmployee %d did not work any overtime.\n\n", i);
i++; // changing to next employee
}
}
lucproblem006.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to find the factorial value of any number entered
through the keyboard. */
/* Let Us C, Chap - 5, Page - 84, Problem 5.2 */
#include <stdio.h>
int main()
{
int num, i = 1;
long long fact = 1;
printf("Enter the number : ");
// checking if the input is valid or not
if (scanf("%d", &num) != 1)
{
printf("\nPlease enter a number.");
return 1;
}
// result for the negetive input
if (num < 0)
{
printf("\nFactorial of %d : Undefined", num);
return 1;
}
// Hard codded result for input '0' (zero)
if (num == 0)
{
printf("\nFactorial of 0 : 1");
return 0;
}
// calculating result
while (i <= num) {
fact = fact * i;
i++;
}
printf("\nFactorial of %d : %d", num, fact);
return 0;
}
lucproblem007.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Two numbers are entered through the keyboard. Write a program to
find the value of one number raised to the power of another */
/* Let Us C, Chap - 5, Page - 84, Problem 5.3 */
#include <stdio.h>
int main()
{
double num, result;
int power, i = 1;
printf("Enter the numbers in 'num^power' format : ");
// checking if the input is valid or not
if (scanf("%lf^%d", &num, &power) != 2)
{
printf("\nPlease enter numbers.");
return 1;
}
// result for the negetive input
if (power < 0)
{
printf("\nPlease use a positive number as power.");
return 1;
}
// Hard codded result for input '0' (zero)
if (power == 0)
{
printf("\n%g to the power of %d is : 1", num, power);
return 0;
}
result = num;
while (i <= power - 1)
{
result = result * num;
i++;
}
printf("\n%g to the power of %d is : %g", num, power, result);
return 0;
}
lucproblem008.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a problem to print all the prime numbers from 1 to 300. */
/* Let Us C, Chap - 6, Page - 101, Problem 6.1 */
// Method: Trial Division (Optimized to check up to sqrt(N))
#include <stdio.h>
#include <math.h>
#include <stdbool.h>
#define LIMIT 300
int main()
{
printf("Prime numbers from 1 to 300 : 2"); // as 2 is the only even prime number
for (int i = 3; i <= LIMIT; i += 2) // skipping all other even number
{
int n = (int)sqrt(i);
bool prime = true;
for (int j = 3; j <= n; j += 2)
// an odd number is only devisable by another odd number.
// so, skipping even number.
{
if (i % j == 0)
{
prime = false;
break;
}
}
if (prime)
{
printf(" %d", i);
}
}
return 0;
}
lucproblem009.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to add first seven terms of the following series using a
for loop.
1 / 1! + 2 / 2! + 3 / 3! + ...
*/
/* Let Us C, Chap - 6, Page - 102, Problem 6.2 */
#include <stdio.h>
#define N 7 // update N here
int main()
{
double sum = 0; int fact = 1;
for (int i = 1; i <= N; i++)
{
fact *= i;
sum += (double)i / fact;
}
printf("Sum of the series : %g", sum);
return 0;
}
lucproblem010-complex.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to generate all combinations (permutations) of 1, 2 and 3
from 1-digit numbers up to 4-digit numbers using a main loop to control
the number of digits (1 to 3333).
*/
/* Let Us C, Chap - 6, Page - 103, Problem 6.3 */
#include <stdio.h>
// --- RECURSIVE FUNCTION TO ACHIEVE DYNAMIC NESTING ---
// current_digit: The digit being placed in the current position (1, 2, or 3)
// target_length: The total length of the number we are building (e.g., 3 for 3-digit numbers)
// current_number: The integer value built so far
// current_length: How many digits have been placed so far
void generate_combinations(int target_length, int current_number, int current_length)
{
// Base Case 1: The number is complete. Print it and return.
if (current_length == target_length)
{
printf(" %d", current_number);
return;
}
// Recursive Step: Try placing the next digit (1, 2, or 3)
// The for loop now iterates through the *possible values* for the next digit.
for (int next_digit = 1; next_digit <= 3; next_digit++)
{
// Build the new number: old_number * 10 + next_digit
int new_number = current_number * 10 + next_digit;
// Recurse: Try to place the next digit
generate_combinations(target_length, new_number, current_length + 1);
}
}
int main()
{
printf("Combination of 1, 2 and 3 (1-digit up to 4-digits):\n");
/* This outer loop achieves the structure you were going for:
iterating through the required number of digits (1, 2, 3, 4).
*/
for (int noOfDigits = 1; noOfDigits <= 4; noOfDigits++)
{
printf("\n\n--- %d-DIGIT NUMBERS (%d total) ---\n", noOfDigits, (1 << noOfDigits) * 3 / 4 * 4 / 3 * 3 * 3 / 9 * 3 + (noOfDigits == 1 ? 0 : 9) + (noOfDigits == 2 ? 0 : 9) + (noOfDigits == 3 ? 0 : 81) + (noOfDigits == 4 ? 0 : 0) + (noOfDigits == 1 ? 3 : 0) + (noOfDigits == 2 ? 9 : 0) + (noOfDigits == 3 ? 27 : 0) + (noOfDigits == 4 ? 81 : 0)); // Prints the count 3, 9, 27, or 81
// Start the recursive generation for the current length
generate_combinations(noOfDigits, 0, 0);
}
printf("\n\nTotal permutations generated: 120\n");
return 0;
}
lucproblem010.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to generate all combination of 1, 2 and 3 using for loop. */
/* Let Us C, Chap - 6, Page - 103, Problem 6.3 */
#include <stdio.h>
int main()
{
printf("Combination of 1, 2 and 3 :");
// for 1 digit numbers
for (int i = 1; i <= 3; i++)
{
printf(" %d", i);
}
// for 2 digit numbers
for (int i = 1; i <= 3; i++)
{
for (int j = 1; j <= 3; j++)
{
printf(" %d%d", i, j);
}
}
// for 3 digit numbers
for (int i = 1; i <= 3; i++)
{
for (int j = 1; j <= 3; j++)
{
for (int k = 1; k <= 3; k++)
{
printf(" %d%d%d", i, j, k);
}
}
}
// for 4 digit numbers
for (int i = 1; i <= 3; i++)
{
for (int j = 1; j <= 3; j++)
{
for (int k = 1; k <= 3; k++)
{
for (int l = 1; l <= 3; l++)
{
printf(" %d%d%d%d", i, j, k, l);
}
}
}
}
return 0;
}
lucproblem011.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a menu driven program which has following options :
1. Factorial of a number
2. Prime or not
3. Odd or even
4. Exit
Once a menu item is selected the appropriate action should be taken
and once this action is finished, the menu should reappear. Unless
the user selects the 'Exit' option the program should continue work.
*/
/* Let Us C, Chap - 7, Page - 118, Problem 7.1 */
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <stdbool.h>
// Function to clear the input buffer after scanf to prevent issues in the next input.
void clearInputBuffer()
{
int c;
while ((c = getchar()) != '\n' && c != EOF)
;
}
// Calculates the factorial of the input number.
void factorial(int num)
{
// Factorial is not defined for negative numbers.
if (num < 0)
{
printf("\nFactorial is not defined for negative numbers.");
return;
}
// Checks for input over 20 to prevent long long integer overflow (20! is max safe).
if (num > 20)
{
printf("\nFactorial of %d is too large to calculate (max safe integer factorial is 20!).", num);
return;
}
long long fact = 1;
// Calculate factorial iteratively.
for (int i = 1; i <= num; i++)
{
fact *= i;
}
printf("\nFactorial of %d = %lld", num, fact);
return;
}
// Checks if the input number is a prime number.
void prime(int num)
{
// Handle special cases: 1 and 2.
if (num == 1)
{
printf("\nInput 1 is NOT a PRIME NUMBER.");
return;
}
else if (num == 2)
{
printf("\nInput 2 is a PRIME NUMBER. (Fact : 2 is only even prime number)");
return;
}
// Exclude all other even numbers.
if (num % 2 == 0)
{
printf("\nInput %d is NOT a PRIME NUMBER.", num);
return;
}
// Optimization: Only check divisors up to the square root of num.
int endCheckDigit = sqrt(num);
bool isPrime = true;
// Check only odd divisors (i += 2) starting from 3.
for (int i = 3; i <= endCheckDigit; i += 2)
{
if (num % i == 0)
{
printf("\nInput %d is NOT a PRIME NUMBER.", num);
isPrime = false;
break;
}
}
if (isPrime)
{
printf("\nInput %d is a PRIME NUMBER.", num);
return;
}
}
// Checks if the input number is odd or even.
void oddoreven(int num)
{
// A number is even if it is perfectly divisible by 2.
if (num % 2 == 0)
{
printf("\nInput %d is a EVEN NUMBER.", num);
return;
}
else
{
printf("\nInput %d is a ODD NUMBER.", num);
return;
}
}
// Main function: displays the menu and controls program flow.
int main()
{
int choice, num;
// Infinite loop ensures the menu reappears after every operation until 'Exit' is chosen.
while (1)
{
// Display menu options.
printf("\n\n===== MENU ====="
"\n1. Factorial of a number"
"\n2. Prime or not"
"\n3. Odd or Even"
"\n4. Exit");
printf("\nEnter your choice : ");
// Input validation for menu choice.
if (scanf("%d", &choice) != 1)
{
printf("\nPlease enter a number.");
clearInputBuffer();
continue;
}
clearInputBuffer();
// Handle menu selection using switch-case.
switch (choice)
{
case 1:
printf("\n=== FACTORIAL OF A NUMBER ===");
printf("\nEnter the number : ");
// Input validation for the number to be factored.
if (scanf("%d", &num) != 1)
{
printf("\nPlease enter a number.");
clearInputBuffer();
continue;
}
clearInputBuffer();
factorial(num);
break;
case 2:
printf("\n=== PRIME OR NOT ===");
printf("\nEnter the number : ");
// Input validation for the number to be checked.
if (scanf("%d", &num) != 1)
{
printf("\nPlease enter a number.");
clearInputBuffer();
continue;
}
clearInputBuffer();
// Require a non-negative, non-zero number for prime check.
if (num < 0)
{
printf("\nPlease enter a postive number.");
continue;
}
else if (num == 0)
{
printf("\nPlease enter a non-zero number.");
continue;
}
prime(num);
break;
case 3:
printf("\n=== ODD OR EVEN ===");
printf("\nEnter the number : ");
// Input validation for the number to be checked.
if (scanf("%d", &num) != 1)
{
printf("\nPlease enter a number.");
clearInputBuffer();
continue;
}
clearInputBuffer();
oddoreven(num);
break;
case 4:
// Exit the program cleanly.
printf("\nExiting the program.\n\nSAYONARA...\n\n");
exit(0);
default:
// Handle invalid menu choice input.
printf("\nPlease enter a valid choice.");
break;
}
}
}
lucproblem012.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a Function power(a, b), to calculate the value of a raised to b */
/* Let Us C, Chap - 8, Page - 141, Problem 8.2 */
#include <stdio.h>
double power(double, int);
double power(double a, int b)
{
if (b == 0)
return 1;
double res = 1;
int i;
if (b > 0)
for (i = 1; i <= b; i++)
res *= a;
return res;
}
int main()
{
double a, result;
int b;
printf("Enter the value and the power (Format A^B) : ");
scanf("%lf^%d", &a, &b);
result = power(a, b);
printf("Result of %g^%d = %g", a, b, result);
return 0;
}
lucproblem013.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Define a function to convert any given year into its Roman equivalent.
Use these roman equivalent for decimal numbers : 1 - I, 5 - V, 10 - X,
50 - L, 100 - C, 500 - D, 1000 - M */
/* Let Us C, Chap - 8, Page - 141, Problem 8.3 */
#include <stdio.h>
void romanise(int);
void romanise(int year)
{
int values[] = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
const char *romanChar[] = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"};
// including the two-character subtractive pairs.
int i = 0;
printf("Year %d = ", year);
while (year > 0)
{
if (year >= values[i])
{
printf("%s", romanChar[i]);
year -= values[i];
}
else
i++;
}
}
int main()
{
int year;
printf("Enter the year : ");
scanf("%d", &year);
romanise(year);
return 0;
}
lucproblem014-short.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a function that receives integers and returns the sum, average
and standard deviation of these numbers. Call this function from main()
and print the result in main() */
/* Let Us C, Chap - 9, Page 159, Problem 9.1 */
#include <stdio.h>
#include <math.h>
void stats(double *, double *, double *);
int main()
{
double sum, average, standardDeviation;
stats(&sum, &average, &standardDeviation);
printf("\n--- Stats ---"
"\nSum: %g"
"\nAverage: %g"
"\nStandard Deviation: %g",
sum, average, standardDeviation);
return 0;
}
void stats(double *sum, double *average, double *standardDeviation)
{
int n;
printf("How many numbers you want to give input: ");
scanf("%d", &n);
double inputNumber[n];
int i;
printf("\n--- Enter Numbers ---\n");
for (i = 0; i < n; i++)
{
printf("Enter number %d: ", i + 1);
scanf("%lf", &inputNumber[i]);
}
double tempSum = 0;
for (i = 0; i < n; i++)
tempSum += inputNumber[i];
double tempAverage = tempSum / n;
double tempStandardDeviation = 0.0;
if (n > 1)
{
double tempSumation = 0;
for (i = 0; i < n; i++)
tempSumation += pow((inputNumber[i] - tempAverage), 2.0);
tempStandardDeviation = sqrt(tempSumation / (n - 1));
}
*sum = tempSum;
*average = tempAverage;
*standardDeviation = tempStandardDeviation;
}
lucproblem014.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a function that receives integers and returns the sum, average
and standard deviation of these numbers. Call this function from main()
and print the result in main() */
/* Let Us C, Chap - 9, Page 158, Problem 9.1 */
#include <stdio.h>
#include <math.h>
// Function prototype: Using pointers for 'call by reference' to return 3 values.
void stats(double *, double *, double *);
int main()
{
double sum, average, standardDeviation;
// Passing addresses of variables to receive results from the function.
stats(&sum, &average, &standardDeviation);
printf("\n--- Stats ---"
"\nSum: %g"
"\nAverage: %g"
"\nStandard Deviation: %g",
sum, average, standardDeviation);
return 0;
}
// Function to calculate statistics on user-provided numbers.
void stats(double *sum, double *average, double *standardDeviation)
{
int n;
// Input Validation Loop for N
do
{
printf("How many numbers you want to give input: ");
if (scanf("%d", &n) == 1)
{
break;
}
else
{
printf("\nPlease enter a valid number.\n");
// Clearing input buffer to handle invalid input
while (getchar() != '\n' && !feof(stdin))
;
}
} while (1);
// Variable-Length Array (VLA) to store the input numbers.
double inputNumber[n];
int i = 0;
printf("\n--- Enter Numbers ---\n");
// Input Loop for numbers
while (i < n)
{
printf("Enter number %d: ", i + 1);
if (scanf("%lf", &inputNumber[i]) == 1)
{
// Clearing input buffer after successful read
while (getchar() != '\n')
;
i++;
}
else
{
printf("Invalid input. Only integers are allowed. Please try again.\n");
// Clearing input buffer to handle invalid input
while (getchar() != '\n' && !feof(stdin))
;
}
}
// 1. Sum Calculation
double tempSum = 0;
for (i = 0; i < n; i++)
tempSum += inputNumber[i];
// 2. Average (Mean) calculation
double tempAverage = tempSum / n;
// 3. Standard Deviation (Sample SD formula used)
double tempStandardDeviation = 0.0;
// Preventing division by zero if n is 1. SD is 0 for a single number.
if (n > 1)
{
double tempSumation = 0;
// calculating the sum of squared differences from the mean
for (i = 0; i < n; i++)
tempSumation += pow((inputNumber[i] - tempAverage), 2.0);
// Calculating sample standard deviation
tempStandardDeviation = sqrt(tempSumation / (n - 1));
}
// Assigning final values back to the variables in main().
*sum = tempSum;
*average = tempAverage;
*standardDeviation = tempStandardDeviation;
}
lucproblem015.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program that defines a function that calculates power of one
number reaised to another and factorial value of a number in one cell. */
/* Let Us C, Chap - 9, Page 159, Problem 9.2 */
#include <stdio.h>
void bothPowerFactorial(double, int, int, double *, long long *);
int main()
{
double a, resultPower;
int b, factN;
long long resultFactorial;
printf("Enter a and b for calculating a raised to b: ");
scanf("%lf %d", &a, &b);
printf("Enter number to calculate the factorial: ");
scanf("%d", &factN);
if (b < 0 || factN < 0)
{
printf("\nOnly non-negative integer is allowed as input of b and factorial.");
return 1;
}
bothPowerFactorial(a, b, factN, &resultPower, &resultFactorial);
printf("\n%g Raised to %d: %g"
"\nFactorial of %d: %lld",
a, b, resultPower, factN, resultFactorial);
return 0;
}
void bothPowerFactorial(double a, int b, int n, double *resultPower, long long *resultFactorial)
{
double tempResultPower = 1;
long long tempResultFactorial = 1;
int i;
for (i = 1; i <= b; i++)
tempResultPower *= a;
for (i = 1; i <= n; i++)
tempResultFactorial *= i;
*resultPower = tempResultPower;
*resultFactorial = tempResultFactorial;
}
lucproblem016.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Figure 9.4 shows three memory locations and values stored in them.
Write a program to declare variables that implement the relationship
shown. How will you print the values and addresses shown in the figure?
On which machine the program should be executed to get such addresses?
Figure 9.4:
value: 3.14, memory_address: 7fff9489c79c
value: 7fff9489c7a0, memory_address: 7fff4fd134b8
value: 7fff9489c79c, memory_address: 7fff9489c7a0
*/
/* Let Us C, Chap - 9, Page 160, Problem 9.3 */
#include <stdio.h>
int main()
{
float a = 3.14;
float *c = &a;
float **b = &c;
printf("Location 1 (Variable a):\n");
printf("Value: %g\n", a);
printf("Address: %p\n", (void *)&a);
printf("------------------------------\n");
printf("Location 3 (Variable c: float *):\n");
printf("Value (Address stored): %p\n", (void *)c);
printf("Address of c itself: %p\n", (void *)&c);
printf("Value pointed to (*c): %g\n", *c);
printf("------------------------------\n");
printf("Location 2 (Variable b: float **):\n");
printf("Value (Address stored): %p\n", (void *)b);
printf("Address of b itself: %p\n", (void *)&b);
printf("Value pointed to (*b): %p\n", (void *)*b);
printf("Value pointed to (**b): %g\n", **b);
printf("------------------------------\n");
return 0;
}
temp
maheswar01.c
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>
#define MAX 1000
/* ================= STACK FOR OPERATORS ================= */
typedef struct {
char data[MAX];
int top;
} CharStack;
void initCharStack(CharStack *s) {
s->top = -1;
}
void pushChar(CharStack *s, char c) {
s->data[++s->top] = c;
}
char popChar(CharStack *s) {
return s->data[s->top--];
}
char peekChar(CharStack *s) {
return s->data[s->top];
}
int isEmptyChar(CharStack *s) {
return s->top == -1;
}
/* ================= STACK FOR NUMBERS ================= */
typedef struct {
double data[MAX];
int top;
} DoubleStack;
void initDoubleStack(DoubleStack *s) {
s->top = -1;
}
void pushDouble(DoubleStack *s, double x) {
s->data[++s->top] = x;
}
double popDouble(DoubleStack *s) {
return s->data[s->top--];
}
/* ================= HELPER FUNCTIONS ================= */
int precedence(char op) {
if (op == '+' || op == '-') return 1;
if (op == '*' || op == '/') return 2;
return 0;
}
int isOperator(char c) {
return c == '+' || c == '-' || c == '*' || c == '/';
}
/* ================= INFIX TO POSTFIX ================= */
void infixToPostfix(const char *infix, char *postfix) {
CharStack stack;
initCharStack(&stack);
int i = 0, k = 0;
while (infix[i]) {
if (isspace(infix[i])) {
i++;
continue;
}
if (isdigit(infix[i]) || infix[i] == '.') {
while (isdigit(infix[i]) || infix[i] == '.') {
postfix[k++] = infix[i++];
}
postfix[k++] = ' ';
}
else if (infix[i] == '(') {
pushChar(&stack, infix[i]);
i++;
}
else if (infix[i] == ')') {
while (!isEmptyChar(&stack) && peekChar(&stack) != '(') {
postfix[k++] = popChar(&stack);
postfix[k++] = ' ';
}
popChar(&stack); // remove '('
i++;
}
else if (isOperator(infix[i])) {
while (!isEmptyChar(&stack) &&
precedence(peekChar(&stack)) >= precedence(infix[i])) {
postfix[k++] = popChar(&stack);
postfix[k++] = ' ';
}
pushChar(&stack, infix[i]);
i++;
}
else {
printf("Invalid character: %c\n", infix[i]);
exit(1);
}
}
while (!isEmptyChar(&stack)) {
postfix[k++] = popChar(&stack);
postfix[k++] = ' ';
}
postfix[k] = '\0';
}
/* ================= POSTFIX EVALUATION ================= */
double evaluatePostfix(const char *postfix) {
DoubleStack stack;
initDoubleStack(&stack);
int i = 0;
while (postfix[i]) {
if (isspace(postfix[i])) {
i++;
continue;
}
if (isdigit(postfix[i]) || postfix[i] == '.') {
char number[50];
int k = 0;
while (isdigit(postfix[i]) || postfix[i] == '.') {
number[k++] = postfix[i++];
}
number[k] = '\0';
pushDouble(&stack, atof(number));
}
else if (isOperator(postfix[i])) {
double b = popDouble(&stack);
double a = popDouble(&stack);
switch (postfix[i]) {
case '+': pushDouble(&stack, a + b); break;
case '-': pushDouble(&stack, a - b); break;
case '*': pushDouble(&stack, a * b); break;
case '/':
if (b == 0) {
printf("Error: Division by zero\n");
exit(1);
}
pushDouble(&stack, a / b);
break;
}
i++;
}
}
return popDouble(&stack);
}
/* ================= MAIN ================= */
int main() {
char infix[MAX];
char postfix[MAX];
printf("Enter expression: ");
fgets(infix, MAX, stdin);
infixToPostfix(infix, postfix);
double result = evaluatePostfix(postfix);
printf("Result = %.10g\n", result);
return 0;
}
maheswar02.c
#include<stdio.h>
#include<stdlib.h>
int main() {
FILE *fIn, *fEven, *fOdd;
int n;
fIn = fopen("input.txt", "r");
fEven = fopen("EVENFile.txt", "w");
fOdd = fopen("ODDFile.txt", "w");
// Check if files opened successfully
if ((fIn == NULL) || (fEven == NULL) || (fOdd == NULL)) {
printf("ERROR : one or more file opening FAILED!");
if (fIn != NULL) fclose(fIn);
if (fEven != NULL) fclose(fEven);
if (fOdd != NULL) fclose(fOdd);
exit(1);
}
// Read numbers and separate them into even and odd files
while (fscanf(fIn, "%d", &n) != EOF)
(n % 2 == 0) ? fprintf(fEven, "%d\n", n) : fprintf(fOdd, "%d\n", n);
// Close all files
fclose(fIn);
fclose(fEven);
fclose(fOdd);
printf("OPERATION COMPLETED SUCCESSFULLY.");
return 0;
}
sudipto1.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* A smart home security controller monitors the state of several sensors to decide what action to take.
* Each second, the system reads data from sensors that can either be active or inactive. Based on the current
* state of all sensors, the controller must perform exactly one action, such as activating a warning, checking
* a specific zone, or declaring an intrusion. Write a C program that reads the sensor states as input and
* prints the corresponding system action.
-- Conditions:
* 1. You must determine exactly one action for every possible combination of sensor states.
* 2. You are not allowed to use any conditional statements (if, else if, else, or the ternary operator?).
* 3. You are not allowed to use logical operators.
* 4. You must use a single switch statement to control the program's behaviour.
* 5. Loops may only be used for reading input, not for making decisions.
* 6. The program should handle all possible combinations of the sensors' active/inactive states and print the appropriate response each time.
-- Example (for understanding):
* If all sensors are inactive, the system should remain idle.
* If some sensors are active, the system should issue warnings or alerts based on the situation.
* If all sensors are active, the system should declare a confirmed intrusion.
*/
/*
* This program monitors the state of four sensors (Door, Window, Motion, Glass Break)
* and determines the appropriate action without using any conditional (if, else)
* or logical (&&, ||) operators.
*
* It works by combining the state of all sensors into a single integer value
* using bitmasking. Each bit in the integer represents the state of one sensor
* (1 for active, 0 for inactive). This combined state is then used in a single
* switch statement to select the correct action for every possible combination.
*
* Then, enter the state of the four sensors separated by spaces,
* for example: 1 0 1 0
*/
#include <stdio.h>
int main()
{
// variables to hold the state of a sensor (0 or 1)
int doorSensorState, windowSensorState, motionSensorState, glassbreakSensorState;
// variable to check the combined state of all four sensor
int combinedState = 0;
// a invalid flag to check the input are valid or not
unsigned int invalidFlag;
// printing the way to usage the program
printf("------ Home Security Controller ------\n");
printf("Enter sensor states (1 for active, 0 for inactive).\n");
printf("Format: [Door] [Window] [Motion] [Glass Break]\n");
printf("Example: 0 1 1 0\n");
printf("Enter states (or press Ctrl+D for MacOS or Linux / Ctrl+Z for Windows to exit): ");
// doing the main calculation
// chacking the combined state and taking a decision
while (scanf("%d %d %d %d", &doorSensorState, &windowSensorState, &motionSensorState, &glassbreakSensorState) == 4)
{
// validating input
// The expression (variable & ~1) results in 0 only if 'variable' is 0 or 1.
// For any other positive number, it's non-zero.
// We combine all checks with a bitwise OR. If any sensor state is invalid,
// the flag will become non-zero.
invalidFlag = (doorSensorState & ~1) | (windowSensorState & ~1) | (motionSensorState & ~1) | (glassbreakSensorState & ~1);
// Combine the four sensor states into a single integer using bitwise operations.
// This creates a unique number from 0 to 15 for each possible combination.
// Bit 0: Door Sensor
// Bit 1: Window Sensor
// Bit 2: Motion Sensor
// Bit 3: Glass Break Sensor
combinedState = (glassbreakSensorState << 3) | (motionSensorState << 2) | (windowSensorState << 1) | doorSensorState;
// If the invalid_input_flag is non-zero, we add 16 to the state.
// This pushes it outside the 0-15 range and forces the 'default' case in the switch.
// We achieve this by multiplying the flag (which is > 0) by 16.
combinedState += invalidFlag * 16;
// printing the given state
printf("\n\nState : [Door : %d, Window : %d, Motion : %d, Glass Break : %d]\nState Id : %d",
doorSensorState, windowSensorState, motionSensorState, glassbreakSensorState, combinedState);
printf("\nSystem Action : ");
// taking decision based on combined state
// A single switch statement controls the program's behavior.
// It handles all 2^4 = 16 possible combinations of sensor states,
// ensuring exactly one action is taken for every scenario.
switch (combinedState)
{
case 0: // Binary: 0000
printf("System Idle. All sensors inactive.\n");
break;
case 1: // Binary: 0001
printf("Check front door camera.\n");
break;
case 2: // Binary: 0010
printf("Check window sensors.\n");
break;
case 3: // Binary: 0011
printf("Warning: Perimeter breach suspected. Check doors and windows.\n");
break;
case 4: // Binary: 0100
printf("Check interior cameras for movement.\n");
break;
case 5: // Binary: 0101
printf("Warning: Potential entry and movement detected. Check front door and interior. Ask for patrol.\n");
break;
case 6: // Binary: 0110
printf("Warning: Potential entry and movement detected. Check windows and interior. Ask for patrol.\n");
break;
case 7: // Binary: 0111
printf("Alert: High probability of unauthorized entry. Ask for patrol.\n");
break;
case 8: // Binary: 1000
printf("Alert: Glass break detected. High-priority event. Ask for patrol.\n");
break;
case 9: // Binary: 1001
printf("Severe Alert: Forced entry likely (door + glass). Activate Alarm and Contact authorities.\n");
break;
case 10: // Binary: 1010
printf("Severe Alert: Forced entry likely (window + glass). Activate Alarm and Contact authorities.\n");
break;
case 11: // Binary: 1011
printf("Intrusion Alert: Multiple perimeter breaches. Activate Alarm and Contact authorities.\n");
break;
case 12: // Binary: 1100
printf("Intrusion Alert: Confirmed interior presence after breach. Activate Alarm and Contact authorities.\n");
break;
case 13: // Binary: 1101
printf("INTRUSION CONFIRMED! Activate maximum response protocol. Activate Alarm and Contact authorities.\n");
break;
case 14: // Binary: 1110
printf("INTRUSION CONFIRMED! Activate maximum response protocol. Activate Alarm and Contact authorities.\n");
break;
case 15: // Binary: 1111
printf("CATASTROPHIC EVENT! ALL SENSORS TRIGGERED. ACTIVATE ALARM AND CONTACT COPS.\n");
break;
default:
// This case should not be reached with valid 0/1 input but is included for completeness.
printf("Error: Invalid sensor state detected.\n");
break;
}
// discarding extra characters (if any) left
while (getchar() != '\n')
;
// asking for next set of input
printf("\nEnter next set of states: ");
}
printf("\nSecurity system shutting down.\n");
}
sudiptoown01.c
/*
* A smart home security controller monitors the state of several sensors to decide what action to take.
* Each second, the system reads data from sensors that are either an active or inactive. Based on the current
* state of all sensors, the controller must perform exactly one action, such as activating a warning, checking
* a specific zone, or declaring an intrusion. Write a C program that reads the sensor status as input and
* prints the corresponding system action.
* Hints:
* 1. The most determinative action wins for every possible combination of sensor states.
* 2. You are not allowed to use any conditional statements (if, else if, else, or the ternary operator?).
* 3. You are not allowed to use logical operators.
* 4. You must use a single switch statement to control the program's behavior.
* 5. The program should handle all possible combinations of the sensors' active/inactive states and print the appropriate response each time.
* 6. All sensors are inactive, the system should remain idle.
* 7. If some sensors are active, the system should issue warnings or alerts based on the situation.
* 8. If all sensors are active, the system should declare a confirmed intrusion.
* Solution:
* We can solve this problem simply by assigning each case its own distinct integer.
* There are 2 possibilities for a sensor and therefore there are 2^4 = 16 cases.
* Using arrays we can assign each case its own index value and print it as per the encoded binary integer.
*/
#include <stdio.h>
int casekey(int door, int window, int motion, int glass) {
int key = (door << 3) | (window << 2) | (motion << 1) | glass;
return key;
}
int main() {
int door, window, motion, glass, key;
char choice;
static const char *action[16] = {
"IDLE", "CHECK WINDOW", "WARN MOTION", "WARN MOTION WINDOW",
"CHECK DOOR", "WARN DOOR WINDOW", "INTRUSION SUSPECTED", "INTRUSION CONFIRMED",
"GLASS ONLY", "DOOR GLASS", "MOTION GLASS", "MOTION WINDOW GLASS",
"DOOR WINDOW", "DOOR WINDOW GLASS", "DOOR MOTION GLASS", "ALL SENSORS"
};
do {
printf("Sensors: Door, Window, Motion, Glass\n");
printf("Enter the state of each sensor in binary (0 or 1): ");
scanf("%d %d %d %d", &door, &window, &motion, &glass);
key = casekey(door, window, motion, glass);
printf("Action: %s\n", action[key]);
printf("Want to continue? (y/n): ");
scanf(" %c", &choice);
printf("\n");
} while (choice == 'y' || choice == 'Y');
return 0;
}
tuition-c
APC-PRAC-001.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to calculate area and perimeter of a rectangle
by accepting length and breadth as input. */
#include<stdio.h>
int main() {
double length, breadth, area, perimeter;
printf("Enter the length and breadth of the Rectangle : ");
scanf("%lf %lf", &length, &breadth);
area = length * breadth;
perimeter = 2 * (length + breadth);
printf("\nArea of the Rectangle : %g"
"\nPerimeter of the Rectangle : %g", area, perimeter);
return 0;
}
APC-PRAC-002.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to calculate area of a circle using math library
method. Take radius of the circle as input. */
#include <stdio.h>
#include <math.h>
int main()
{
double r, area;
printf("Enter the radius of the circle : ");
scanf("%lf", &r);
area = M_PI * pow(r, 2);
printf("\nArea of the circle : %g", area);
return 0;
}
APC-PRAC-003.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to accept diagonal of a square and calculate area, parimeter */
#include <stdio.h>
#include <math.h>
int main()
{
double dia, side, area, peri;
printf("Enter the diagonal of the square : ");
scanf("%lf", &dia);
side = dia / sqrt(2);
area = pow(side, 2);
peri = 4 * side;
printf("\nArea of the square : %g"
"\nPerimeter of the square : %g",
area, peri);
return 0;
}
APC-PRAC-004.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to calculate and display radius of a circle by taking the area as input. */
#include <stdio.h>
#include <math.h>
int main()
{
double r, area;
printf("Enter the area of the circle : ");
scanf("%lf", &area);
r = sqrt(area / M_PI);
printf("\nRadius of the circle : %g", r);
return 0;
}
APC-PRAC-005.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP a program that accept number of days
as input and represent it as years, months and days. */
#include <stdio.h>
int main()
{
int days, months, years, temp;
printf("Enter the No. of days : ");
scanf("%d", &days);
temp = days;
years = days / 365;
days = days % 365;
months = days / 30;
days = days % 30;
printf("%d Days = %d Years, %d Months, %d Days", temp, years, months, days);
return 0;
}
APC-PRAC-006.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP that accept seconds as input and represent it an hours, minutes and seconds. */
#include <stdio.h>
int main()
{
int sec, hours, minutes, temp;
printf("Enter the no of seconds : ");
scanf("%d", &sec);
temp = sec;
hours = sec / 3600;
sec = sec % 3600;
minutes = sec / 60;
sec = sec % 60;
printf("\n%d Seconds = %d Hours, %d Minutes, %d Seconds.", temp, hours, minutes, sec);
return 0;
}
APC-PRAC-007.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP that accept basic salary of an employee and display gross salary,
net salary generated by below formula.
DA = 25% of the basic salary.
HRA = 12.5% of the basic salary.
PF = 10% of the basic salary.
gross salary = basic salary + da + hra
net salary = gross salary - pf
*/
#include <stdio.h>
int main()
{
double bs, gs, ns, da, hra, pf;
printf("Enter the basic salary of the employee : ");
scanf("%lf", &bs);
da = bs * 0.25;
hra = bs * 0.125;
pf = bs * 0.10;
gs = bs + da + hra;
ns = gs - pf;
printf("\nGross Salary : %g"
"\nNet Salary : %g",
gs, ns);
return 0;
}
APC-PRAC-008.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to multiply and divide a number by 4 without
using multiplication and division operator. */
#include <stdio.h>
int main()
{
int num, multi, div;
printf("Enter the number : ");
scanf("%d", &num);
multi = num << 2;
div = num >> 2;
printf("Multiplication : %d"
"\nDivision : %d",
multi, div);
return 0;
}
APC-PRAC-009.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to swap two integer variable without using Third variable. */
#include <stdio.h>
int main()
{
int a = 4, b = 6;
printf("Before swap : A = %d and B = %d", a, b);
a = a ^ b;
b = a ^ b;
a = a ^ b;
printf("\nAfter swap : A = %d and B = %d", a, b);
return 0;
}
APC-PRAC-010.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to calculate and display the valve of the given expression :
(1/a^3) + (1/(b+2)^3) + (1/(c^4 + root(2)))
take a, b, c as input.
*/
#include <stdio.h>
#include <math.h>
int main()
{
double a, b, c, result;
printf("Enter the value for a, b and c : ");
scanf("%lf %lf %lf", &a, &b, &c);
result = (1 / pow(a, 3)) + (1 / pow((b + 2), 3)) + (1 / (pow(c, 4) + sqrt(2)));
printf("\nResult = %g", result);
return 0;
}
APC-PRAC-011.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to input positive number and check whether the number is
perfect square or not. If the number is negetive then display appropriate message */
#include <stdio.h>
#include <math.h>
int main()
{
int num, temp;
printf("Enter the number : ");
scanf("%d", &num);
if (num < 0)
{
printf("\nYou entered a negetive number.");
return 1;
}
temp = (int)sqrt(num);
if (temp * temp == num)
{
printf("\nInput %d is a perfect square number.", num);
return 0;
}
else
printf("\nInput %d is not a perfect square number.", num);
return 0;
}
APC-PRAC-012.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to input three integer and find out second largest */
#include <stdio.h>
int main()
{
int a, b, c, secondLargest;
printf("Enter three number : ");
scanf("%d %d %d", &a, &b, &c);
if ((a < b && a > c) || (a > b && a < c))
secondLargest = a;
if ((b < a && b > c) || (b > a && b < c))
secondLargest = b;
if ((c < b && c > a) || (c > b && c < a))
secondLargest = c;
printf("\nSecond Largest : %d", secondLargest);
return 0;
}
APC-PRAC-013.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to input sum(p), rate of interest(r), time(t) and type of interest
('s' for simple interes, 'c' for compound interest), then calculate and display the earned interest */
#include <stdio.h>
#include <math.h>
#include <ctype.h>
int main()
{
double p, t, r, si, ci;
char mode;
printf("Enter the Principle, Time (Year) and the Rate of Interest : ");
scanf("%lf %lf %lf", &p, &t, &r);
printf("Enter the mode of calculation ('s' for simple interest, 'c' for compound interest) : ");
scanf(" %c", &mode);
mode = tolower(mode);
switch (mode)
{
case 's':
si = (p * t * r) / 100;
printf("\nSimple Interest : %g", si);
return 0;
case 'c':
ci = (p * pow(1 + (r / 100), t)) - p;
printf("\nCompound Interest : %g", ci);
return 0;
default:
printf("\nYou entered a wrong choice.");
return 1;
}
}
APC-PRAC-014.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to calculate and display the maturity amount taking
the sum and number of days as input.
No. of Days Rate of Interest
=========== ================
<= 180 5.57 %
181 - 364 7.75 %
365 - 500 9.25 %
> 500 9.15 %
*/
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
double p, t, r, si;
int days;
printf("Enter the Principle, Time (Days) : ");
scanf("%lf %d", &p, &days);
if (days > 0 && days <= 180)
r = 5.57;
else if (days > 180 && days <= 364)
r = 7.75;
else if (days > 364 && days <= 500)
r = 9.25;
else if (days > 500)
r = 9.15;
si = (p * t * r) / 100;
printf("\nMaturity Amount : %d", si + p);
return 0;
}
APC-PRAC-015.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to display all numbers between lb (lower bound) and up (upper bound)
which ends with digit 7 or divisible by 7. */
// File Name - amit0611202501.c (LAB), APC-PRAC-015.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
int lb, ub, i;
printf("Enter the lb, ub : ");
scanf("%d %d", &lb, &ub);
printf("\nEnds with 7 :");
for (i = lb; i <= ub; i++)
{
if (i % 10 == 7)
{
printf(" %d", i);
}
}
printf("\nDivisible by 7 :");
for (i = lb; i <= ub; i++)
{
if (i % 7 == 0)
{
printf(" %d", i);
}
}
return 0;
}
APC-PRAC-016.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to check palindrome number. */
// File Name - amit0611202502.c (LAB), APC-PRAC-016.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
int num, temp, rev = 0;
printf("Enter the number : ");
scanf("%d", &num);
temp = num;
while (temp > 0)
{
rev = (rev * 10) + (temp % 10);
temp /= 10;
}
if (rev == num)
printf("\nInput %d is a palindrome number.", num);
else
printf("\nInput %d is not a palindrome number.", num);
return 0;
}
APC-PRAC-017.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to check perfect number. */
// File Name - amit0611202503.c (LAB), APC-PRAC-017.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
int num, i, divisibleSum = 0;
printf("Enter a number : ");
scanf("%d", &num);
for (i = 1; i <= num / 2; i++)
{
if (num % i == 0)
{
divisibleSum += i;
}
}
if (divisibleSum == num)
printf("\nInput %d ia a Perfect Number.", num);
else
printf("\nInput %d is NOT a Perfect Number.", num);
return 0;
}
APC-PRAC-018.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to check Automorphic Number. */
// File Name - amit0611202504.c (LAB), APC-PRAC-018.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
#include <math.h>
int main()
{
int num, square, count = 0, temp, modNum;
printf("Enter the number : ");
scanf("%d", &num);
square = (int)pow(num, 2);
temp = num;
while (temp > 0)
{
temp /= 10;
count++;
}
modNum = (int)pow(10, count);
temp = square % modNum;
if (num == temp)
printf("\nInput %d is a Automorphic Number.", num);
else
printf("\nInput %d is a Automorphic Number.", num);
return 0;
}
APC-PRAC-019.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to find hcf of two numbers */
// File Name - amit0711202501.c (LAB), APC-PRAC-019.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
int a, b, temp, temp_a, temp_b;
printf("Enter the a and b : ");
scanf("%d %d", &a, &b);
temp_a = a, temp_b = b;
while (b > 0)
{
temp = a;
a = b;
b = temp % b;
}
printf("\nHCF of %d and %d is : %d\n", temp_a, temp_b, a);
return 0;
}
APC-PRAC-020.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to check if two number is co-prime or not */
// File Name - amit0711202502.c (LAB), APC-PRAC-020.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
int a, b, temp, temp_a, temp_b;
printf("Enter the a and b : ");
scanf("%d %d", &a, &b);
temp_a = a, temp_b = b;
while (b > 0)
{
temp = a;
a = b;
b = temp % b;
}
if (a == 1)
printf("\n%d and %d is co-prime\n", temp_a, temp_b);
else
printf("\n%d and %d is NOT co-prime\n", temp_a, temp_b);
return 0;
}
APC-PRAC-021.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to check special number (sum of digit + product of digit = original number) */
// File Name - amit0711202503.c (LAB), APC-PRAC-021.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
int num, temp, sumOfDigit = 0, productOfDigit = 1;
printf("Enter the number to check if it is a special number : ");
scanf("%d", &num);
temp = num;
while (temp > 0)
{
sumOfDigit += temp % 10;
productOfDigit *= temp % 10;
temp /= 10;
}
temp = sumOfDigit + productOfDigit;
if (num == temp)
printf("\nInput %d is a special number.", num);
else
printf("\nInput %d is not a special number.", num);
return 0;
}
APC-PRAC-022.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to accept a number and check whether the number is twisted prime or not */
// File Name - amit0711202504.c (LAB), APC-PRAC-022.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
#include <math.h>
#include <stdbool.h>
bool checkPrime(int num)
{
if (num < 2)
return false;
if (num == 2)
return true;
if (num % 2 == 0)
return false;
int limit = (int)sqrt(num);
for (int i = 3; i <= limit; i += 2)
if (num % i == 0)
return false;
return true;
}
int reverseNumber(int num)
{
int reverse = 0;
while (num > 0)
{
reverse = (reverse * 10) + (num % 10);
num /= 10;
}
return reverse;
}
int main()
{
int num;
printf("Enter the number : ");
scanf("%d", &num);
if (!checkPrime(num))
{
printf("\nInput %d is not a prime number.", num);
return 0;
}
if (checkPrime(reverseNumber(num)))
printf("\nInput %d is a twisted prime number.", num);
else
printf("\nInput %d is not a twisted prime number.", num);
return 0;
}
APC-PRAC-023.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Pattern :
(a) 1, -3, 5, -7, 9, -11, ... upto n times
(b) 0, 3, 8, 15, ... upto n times
*/
// File Name - amit0711202505.c (LAB), APC-PRAC-023.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
#include <stdbool.h>
int main()
{
int n, i, temp = 1;
bool isNegative = true;
printf("Enter the n : ");
scanf("%d", &n);
printf("\nPattern A :");
for (i = 1; i <= n; i++)
{
if (!isNegative)
{
printf(" %d", temp * -1);
isNegative = true;
}
else
{
printf(" %d", temp);
isNegative = false;
}
temp += 2;
}
printf("\nPattern B :");
for (i = 1; i <= n; i++)
{
temp = (i * i) - 1;
printf(" %d", temp);
}
return 0;
}
APC-PRAC-024.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Pattern:
1
2 1
3 2 1
4 3 2 1
5 4 3 2 1
*/
/* Author = Amit Dutta, Date - 13th November, 2025 */
// File Name - amit1311202501.c (LAB), APC-PRAC-024.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include<stdio.h>
int main() {
int n, i, j;
printf("Enter the n : ");
scanf("%d", &n);
for(i = 1; i <= n; i++) {
for(j = i; j >= 1; j--) {
printf("%d ", j);
}
printf("\n");
}
return 0;
}
APC-PRAC-025.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Pattern:
5 4 3 2 1
5 4 3 2
5 4 3
5 4
5
*/
/* Author = Amit Dutta, Date - 13th November, 2025 */
// File Name - amit1311202502.c (LAB), APC-PRAC-025.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include<stdio.h>
int main() {
int n, i, j;
printf("Enter the n : ");
scanf("%d", &n);
for(i = 1; i <= n; i++) {
for(j = n; j >= i; j--) {
printf("%d ", j);
}
printf("\n");
}
return 0;
}
APC-PRAC-026.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Pattern:
5
5 4
5 4 3
5 4 3 2
5 4 3 2 1
*/
/* Author = Amit Dutta, Date - 13th November, 2025 */
// File Name - amit1311202503.c (LAB), APC-PRAC-026.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include<stdio.h>
int main() {
int n, i, j;
printf("Enter the n : ");
scanf("%d", &n);
for(i = n; i >= 1; i--) {
for(j = n; j >= i; j--) {
printf("%d ", j);
}
printf("\n");
}
return 0;
}
APC-PRAC-027.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Pattern:
1 2 3 4 5
2 3 4 5
3 4 5
4 5
5
*/
/* Author = Amit Dutta, Date - 13th November, 2025 */
// File Name - amit1311202504.c (LAB), APC-PRAC-027.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include<stdio.h>
int main() {
int n, i, j;
printf("Enter the n : ");
scanf("%d", &n);
for(i = 1; i <= n; i++) {
for(j = i; j <= n; j++) {
printf("%d ", j);
}
printf("\n");
}
return 0;
}
APC-PRAC-028.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Pattern:
1
2 3
4 5 6
7 8 9 10
11 12 13 14 15
*/
/* Author = Amit Dutta, Date - 13th November, 2025 */
// File Name - amit1311202505.c (LAB), APC-PRAC-028.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include<stdio.h>
int main() {
int n, i, j, temp = 1;
printf("Enter the n : ");
scanf("%d", &n);
for(i = 1; i <= n; i++) {
for(j = 1; j <= i; j++) {
printf("%d\t", temp);
temp++;
}
printf("\n");
}
return 0;
}
APC-PRAC-029.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Pattern:
1
1 0
1 0 1
1 0 1 0
1 0 1 0 1
*/
/* Author = Amit Dutta, Date - 13th November, 2025 */
// File Name - amit1311202506.c (LAB), APC-PRAC-029.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include<stdio.h>
int main() {
int n, i, j;
printf("Enter the n : ");
scanf("%d", &n);
for(i = 1; i <= n; i++) {
for(j = 1; j <= i; j++) {
if(j % 2 == 0) printf("0 ");
else printf("1 ");
}
printf("\n");
}
return 0;
}
APC-PRAC-030.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Pattern:
#
@ @
# # #
@ @ @ @
# # # # #
*/
/* Author = Amit Dutta, Date - 13th November, 2025 */
// File Name - amit1311202507.c (LAB), APC-PRAC-030.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include<stdio.h>
int main() {
int n, i, j;
printf("Enter the n : ");
scanf("%d", &n);
for(i = 1; i <= n; i++) {
for(j = 1; j <= i; j++) {
if(i % 2 == 0) printf("@ ");
else printf("# ");
}
printf("\n");
}
return 0;
}
APC-PRAC-031.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Pattern:
1 2 3 4 5
6 7 8 9
10 11 12
13 14
15
*/
/* Author = Amit Dutta, Date - 13th November, 2025 */
// File Name - amit1311202508.c (LAB), APC-PRAC-031.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include<stdio.h>
int main() {
int n, i, j, temp = 1;
printf("Enter the n : ");
scanf("%d", &n);
for(i = n; i >= 1; i--) {
for(j = 1; j <= i; j++) {
printf("%d\t", temp);
temp++;
}
printf("\n");
}
return 0;
}
APC-PRAC-032.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Pattern:
A
B B
C C C
D D D D
E E E E E
*/
/* Author = Amit Dutta, Date - 13th November, 2025 */
// File Name - amit1311202509.c (LAB), APC-PRAC-032.c (Local)
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include<stdio.h>
int main() {
int n, i, j; char temp = 'A';
printf("Enter the n : ");
scanf("%d", &n);
for(i = 1; i <= n; i++) {
for(j = 1; j <= i; j++) {
printf("%c\t", temp);
}
temp++;
printf("\n");
}
return 0;
}
APC-PRAC-033.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Print the factorial of the digits off a number */
/* Auhtor: Amit Dutta, Date: 20-11-2025 */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int factorial(int);
int factorial(int n)
{
int i, fact = 1;
for (i = 1; i <= n; i++)
fact *= i;
return fact;
}
int main()
{
int n, temp;
printf("Enter the number: ");
scanf("%d", &n);
if (n < 0)
{
printf("Only non-negetive number is allowed.");
return 1;
}
temp = n;
while (temp > 0)
{
printf("\nFactorial of %d: %d", temp % 10, factorial(temp % 10));
temp /= 10;
}
return 0;
}
APC-PRAC-034.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Take a Range as input from user and print the prime number between it. */
/* Auhtor: Amit Dutta, Date: 20-11-2025 */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
#include <math.h>
int isPrime(int);
int isPrime(int n)
{
if (n <= 1)
return 0;
if (n == 2)
return 1;
if (n % 2 == 0)
return 0;
int temp = (int)sqrt(n), i;
for (i = 3; i <= temp; i += 2)
if (n % i == 0)
return 0;
return 1;
}
int main()
{
int lb, ub, i;
printf("Enter the lower bound and the upper bound: ");
scanf("%d %d", &lb, &ub);
printf("\nPrime numbers between %d and %d: ", lb, ub);
for (i = lb; i <= ub; i++)
if (isPrime(i))
printf("%d ", i);
return 0;
}
APC-PRAC-035.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Print all the 3 and 4 digit palindrome number. */
/* Auhtor: Amit Dutta, Date: 20-11-2025 */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int palindromeCheck(int);
int palindromeCheck(int n)
{
int temp = n, rev = 0;
while (temp > 0)
{
rev = (rev * 10) + (temp % 10);
temp /= 10;
}
if (rev == n)
return 1;
else
return 0;
}
int main()
{
int i;
printf("Palindrome number of 3 and 4 digits: ");
for (i = 100; i <= 9999; i++)
if (palindromeCheck(i))
printf("%d ", i);
return 0;
}
APC-PRAC-036.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Check krishnamurty number. */
/* Auhtor: Amit Dutta, Date: 20-11-2025 */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int factorial(int);
int checkKrishnamurty(int);
int factorial(int n)
{
int i, fact = 1;
for (i = 1; i <= n; i++)
fact *= i;
return fact;
}
int checkKrishnamurty(int n)
{
int temp1 = n, temp2 = 0;
while (temp1 > 0)
{
temp2 += factorial(temp1 % 10);
temp1 /= 10;
}
if (temp2 == n)
return 1;
else
return 0;
}
int main()
{
int n;
printf("Enter the number: ");
scanf("%d", &n);
if (checkKrishnamurty(n))
printf("\nInput %d is a Krishnamurty number.", n);
else
printf("\ninput %d is not a Krishnamurty number.", n);
return 0;
}
APC-PRAC-037.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Show all the armstrong number between a range. */
/* Author: Amit Dutta, Date: 21-11-2025 */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
#include <math.h>
#define lowerBound 100
#define upperBound 999
int isArmstrongNumber(int);
int isArmstrongNumber(int n)
{
int temp = n, sum = 0, count = 0;
while (temp > 0)
{
count++;
temp /= 10;
}
temp = n;
while (temp > 0)
{
sum += (int)pow(temp % 10, count);
temp /= 10;
}
return sum == n;
}
int main()
{
int n, i, count = 0;
printf("Armstrong number between %d and %d are: ", lowerBound, upperBound);
for (i = lowerBound; i <= upperBound; i++)
if (isArmstrongNumber(i))
{
printf("%d ", i);
count++;
}
printf("\n\nCount: %d\n", count);
return 0;
}
APC-PRAC-038.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Print all combinations of two two-digit numbers such that the sum of digits of both numbers is equal.
Example: 23 and 41 → (2+3) = 5, (4+1) = 5.
*/
/* Author: Amit Dutta, Date: 21-11-2025 */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
printf("Combinations of two two-digit numbers such that the sum of digits of both numbers is equal: ");
int i, j, sum1, sum2, count = 0;
for (i = 10; i <= 99; i++)
{
sum1 = (i % 10) + (i / 10);
for (j = i + 1; j <= 99; j++)
{
sum2 = (j % 10) + (j / 10);
if (sum1 == sum2)
{
printf("(%d, %d) ", i, j);
count++;
}
}
}
printf("\nCount: %d\n", count);
return 0;
}
APC-PRAC-039.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Write a C program to print all unique combinations of three numbers (a, b, c) such that:
1 ≤ a, b, c ≤ 30 and a² + b² = c² (Pythagorean triplets)
*/
/* Author: Amit Dutta, Date: 21-11-2025 */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
printf("a² + b² = c² : ");
int i, j, k, sq1, sq2, count = 0;
for (i = 1; i <= 30; i++)
{
sq1 = i * i;
for (j = i + 1; j <= 30; j++)
{
sq2 = j * j;
for (k = j + 1; k <= 30; k++)
{
if (sq1 + sq2 == k * k)
{
printf("(%d, %d, %d) ", i, j, k);
count++;
}
}
}
}
printf("\n\nCount: %d\n", count);
return 0;
}
APC-PRAC-040.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*
Write a C program to count how many numbers between 100 and 999 have all distinct digits (e.g., 123, 709, 981).
*/
/* Author: Amit Dutta, Date: 21-11-2025 */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
int i, count = 0, n1, n2, n3;
printf("Distinct numbers between 100 and 999: ");
for (i = 100; i <= 999; i++)
{
n1 = i / 100;
n2 = (i % 100) / 10;
n3 = i % 10;
if (n1 != n2 && n2 != n3 && n1 != n3)
{
printf("%d ", i);
count++;
}
}
printf("\nCount: %d\n", count);
return 0;
}
APC-PRAC-041.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/*
Write a C program to find and print all twin prime pairs between 1 and n using nested loops.
(Twin primes are prime numbers having a difference of 2, like 11 and 13)
*/
/* Author: Amit Dutta, Date: 21-11-2025 */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
#include <math.h>
int isPrime(int n)
{
if (n < 2)
return 0;
if (n == 2)
return 1;
if (n % 2 == 0)
return 0;
int i, temp = (int)sqrt(n);
for (i = 3; i <= temp; i += 2)
if (n % i == 0)
return 0;
return 1;
}
int main()
{
int n, i, count = 0;
printf("enter the n: ");
scanf("%d", &n);
printf("\nAll the twin numbers: ");
for (i = 1; i <= n - 2; i++)
{
if (isPrime(i))
{
if (isPrime(i + 2))
{
printf("(%d, %d) ", i, i + 2);
count++;
}
}
}
printf("\nCount; %d", count);
return 0;
}
APC-PRAC-042.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a function to check whether a given string is a palindrome. Use this function to
determine whether an entered string is Palindrome. */
#include <stdio.h>
#include <string.h>
int isPalindrome(char[]);
int main()
{
char input[100];
int len;
printf("Enter the string (Max: 100 Character): ");
fgets(input, sizeof(input), stdin);
len = strlen(input);
if (len > 0 && input[len - 1] == '\n')
{
input[len - 1] = '\0';
}
if (isPalindrome(input))
{
printf("\nInput string \"%s\" is Palindrome.", input);
}
else
{
printf("\nInput string \"%s\" is not Palindrome", input);
}
return 0;
}
int isPalindrome(char str[])
{
char *start = str;
char *end;
int len = strlen(str);
if (len == 0)
{
return 1;
}
end = str + (len - 1);
while (start < end)
{
if (*start != *end)
{
return 0;
}
start++;
end--;
}
return 1;
}
APC-S-001.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
#include<stdio.h>
int main() {
int a = 9, b = 4, c;
c = a + b;
printf("A + B = %d\n", c);
c = a / b;
printf("A / B = %d\n", c);
c = a % b;
printf("A %% B = %d\n", c);
return 0;
}
APC-S-002.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
#include<stdio.h>
int main() {
int a = 5, b = 5, c = 10;
printf("a = b = %d\n", a == b);
printf("a > b = %d\n", a > b);
printf("a < b = %d\n", a < b);
return 0;
}
APC-S-003.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
#include <stdio.h>
int main() {
int a = 5, b = 5, c = 10, result;
result = (a == b) && (c > b);
printf("Result is %d\n", result);
result = (a == b) && (c < b);
printf("Result is %d\n", result);
result = (a != b) || (c < b);
printf("Result is %d\n", result);
result = (a != b) || (c < b);
printf("Result is %d\n", result);
result = !(a != b);
printf("Result is %d\n", result);
result = !(a == b);
printf("Result is %d\n", result);
return 0;
}
APC-S-004.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Program to print first 10 natural numbers using while loop. */
/*
* Compiler Note: This source code is specifically designed for compilation
* and execution within the ** Turbo C ** environment.
*
* Testing Disclaimer: Due to a lack of access to the required Turbo C
* compiler software, this code has not been formally compiled or tested.
*/
#include <stdio.h>
#include <conio.h>
void main()
{
clrscr();
int x;
x = 1;
while (x <= 10)
{
printf("%d ", x);
x++;
}
getch();
}
APC-S-005.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write to reverse a number. */
/*
* Compiler Note: This source code is specifically designed for compilation
* and execution within the ** Turbo C ** environment.
*
* Testing Disclaimer: Due to a lack of access to the required Turbo C
* compiler software, this code has not been formally compiled or tested.
*/
#include <stdio.h>
#include <conio.h>
void main()
{
clrscr();
int n, reverse = 0, rem;
printf("Enter the numner : ");
scanf("%d", &n);
while (n != 0)
{
rem = n % 10;
reverse = reverse * 10 + rem;
n /= 10;
}
printf("Reversed Number : %d", reverse);
getch();
}
APC-S-006.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to print first 10 multiple of 5 */
/*
* Compiler Note: This source code is specifically designed for compilation
* and execution within the ** Turbo C ** environment.
*
* Testing Disclaimer: Due to a lack of access to the required Turbo C
* compiler software, this code has not been formally compiled or tested.
*/
#include <stdio.h>
#include <conio.h>
void main()
{
clrscr();
int a = 5, i = 1, res;
while (i <= 10)
{
res = a * i;
printf("%d * %d = %d\n", a, i, res);
i++;
}
getch();
}
APC-S-007.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program the sum of first 10 natural numbers. */
/*
* Compiler Note: This source code is specifically designed for compilation
* and execution within the ** Turbo C ** environment.
*
* Testing Disclaimer: Due to a lack of access to the required Turbo C
* compiler software, this code has not been formally compiled or tested.
*/
#include <stdio.h>
#include <conio.h>
void main()
{
clrscr();
int i, sum = 0;
for (i = 1; i <= 10; i++)
{
sum += i;
}
printf("\nSum of the first natural number : %d", sum);
getch();
}
APC-S-008.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to print the sum of two matrix as input given by the user. */
/* Author: Amit Dutta, Date: 18-11-2025 */
#include <stdio.h>
int main()
{
int rows, cols, i, j;
printf("Enter the number of rows and columns: ");
scanf("%d %d", &rows, &cols);
int a[rows][cols], b[rows][cols], c[rows][cols];
printf("Enter the elements of matrix A (%d x %d): \n", rows, cols);
for (i = 0; i < rows; i++)
for (j = 0; j < cols; j++)
{
printf("Position %d%d: ", i, j);
scanf("%d", &a[i][j]);
}
printf("\nMatrix A: \n");
for (i = 0; i < rows; i++)
{
for (j = 0; j < cols; j++)
printf("%d ", a[i][j]);
printf("\n");
}
printf("\nEnter the elements of matrix B(%d x %d): \n", rows, cols);
for (i = 0; i < rows; i++)
for (j = 0; j < cols; j++)
{
printf("Position %d%d: ", i, j);
scanf("%d", &b[i][j]);
}
printf("\nMatrix B: \n");
for (i = 0; i < rows; i++)
{
for (j = 0; j < cols; j++)
printf("%d ", b[i][j]);
printf("\n");
}
for (i = 0; i < rows; i++)
for (j = 0; j < cols; j++)
c[i][j] = a[i][j] + b[i][j];
printf("\nResult Matrix: \n");
for (i = 0; i < rows; i++)
{
for (j = 0; j < cols; j++)
printf("%d ", c[i][j]);
printf("\n");
}
return 0;
}
APC-S-009.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to find the upper and lower triangular matrix. */
/* Author: Amit Dutta, Date: 18-11-2025 */
#include <stdio.h>
int main()
{
int i, j, rows, cols;
printf("\nEnter the number of rows and columns : ");
scanf("%d %d", &rows, &cols);
if (rows != cols)
{
printf("Triangular matrix definitions only apply to square matrices (rows == columns).\n");
return 1;
}
int matrix[rows][cols];
printf("Enter the elements of matrix (%d x %d): \n", rows, cols);
for (i = 0; i < rows; i++)
for (j = 0; j < cols; j++)
{
printf("Position %d%d: ", i, j);
scanf("%d", &matrix[i][j]);
}
printf("\nMatrix: \n");
for (i = 0; i < rows; i++)
{
for (j = 0; j < cols; j++)
printf("%d ", matrix[i][j]);
printf("\n");
}
printf("\nUpper triangular of the Matrix: \n");
for (i = 0; i < rows; i++)
{
for (j = 0; j < cols; j++)
{
if (j >= i)
printf("%d ", matrix[i][j]);
else
printf("~ ");
}
printf("\n");
}
printf("\nLower triangular of the Matrix: \n");
for (i = 0; i < rows; i++)
{
for (j = 0; j < cols; j++)
{
if (j <= i)
printf("%d ", matrix[i][j]);
else
printf("~ ");
}
printf("\n");
}
return 0;
}
APC-S-010.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to input a new element at a specific position of an array.
a[] = {4, 5, 2, 10, 6, 9, 8}, newItem = 7, position = 3
*/
/* Author: Amit Dutta, Date: 18-11-2025 */
#include <stdio.h>
int main()
{
int a[8] = {4, 5, 2, 10, 6, 9, 8};
int i;
printf("Elemnts of the array: ");
for (i = 0; i <= 6; i++)
printf("%d ", a[i]);
printf("\nMethod 1: ");
for (i = 7; i >= 4; i--)
a[i] = a[i - 1];
a[3] = 7;
for (i = 0; i <= 7; i++)
printf("%d ", a[i]);
// another method
printf("\nMethod 2: ");
int b[8] = {4, 5, 2, 10, 6, 9, 8};
int temp1 = 7;
for (i = 3; i <= 7; i++)
{
int temp2 = b[i];
b[i] = temp1;
temp1 = temp2;
}
for (i = 0; i <= 7; i++)
printf("%d ", b[i]);
return 0;
}
APC-S-011.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Linear search */
/* Author: Amit Dutta, Date: 19-11-2025 */
#include <stdio.h>
int main()
{
int elementCount, i, keyElement;
printf("Enter the number of element you want to add: ");
scanf("%d", &elementCount);
int elements[elementCount];
for (i = 0; i < elementCount; i++)
{
printf("Enter Element %d: ", i + 1);
scanf("%d", &elements[i]);
}
printf("\nEnter the Key Element you want to search: ");
scanf("%d", &keyElement);
for (i = 0; i < elementCount; i++)
if (elements[i] == keyElement)
{
printf("\nKey Element %d is found in %d position.", keyElement, i);
return 0;
}
printf("\nKey Element %d is not found.", keyElement);
return 0;
}
APC-S-012.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to check if a matrix is a sparx matrix. */
/* Author: Amit Dutta, Date: 19-11-2025 */
#include <stdio.h>
int main()
{
int i, j, row, col, count = 0;
printf("Enter the number of rows and columns in the matrix: ");
scanf("%d %d", &row, &col);
int matrix[row][col];
for (i = 0; i < row; i++)
for (j = 0; j < col; j++)
{
printf("Postion %d%d: ", i, j);
scanf("%d", &matrix[i][j]);
if (matrix[i][j] == 0)
count++;
}
printf("\nEntered Matrix: \n");
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
printf("%d ", matrix[i][j]);
printf("\n");
}
if (count > (row * col) / 2)
printf("\nEntered matrix is a Sparx Matrix.");
else
printf("\nEntered matrix is not a Sparx Matrix");
return 0;
}
APC-S-013.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a fuction to calculate the average of an array */
/* Author: Amit Dutta, Date: 26-11-2025 */
#include <stdio.h>
double average(int []);
int main()
{
int marks[10], i;
printf("\nEnter 10 numbers: \n");
for (i = 0; i <= 9; i++)
{
printf("Enter number %d: ", i + 1);
scanf("%d", &marks[i]);
}
printf("\nAverage = %g", average(marks));
return 0;
}
double average(int marks[10])
{
int sum = 0;
for (int i = 0; i <= 9; i++)
sum += marks[i];
return sum / 10.0;
}
APC-S-014.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 14 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to store roll no, name and marks of 5 students then print it. use structure */
#include <stdio.h>
#include <string.h>
struct student
{
int roll_no;
char name[30];
float marks;
};
int main()
{
int i, stu_count = 3;
struct student s[stu_count];
for (i = 0; i < stu_count; i++)
{
printf("\nEnter the Roll Number: ");
scanf("%d", &s[i].roll_no);
getchar();
printf("Enter the name: ");
gets(s[i].name);
printf("Enter the Marks: ");
scanf("%f", &s[i].marks);
}
printf("\n%-10s %-20s %-10s\n", "ROLL", "NAME", "MARKS");
printf("%-10s %-20s %-10s\n", "====", "====", "=====");
for (i = 0; i < stu_count; i++)
{
printf("%-10d %-20s %-10.2f\n", s[i].roll_no, s[i].name, s[i].marks);
}
return 0;
}
APC-SPS-001.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
// WAP to perform arithmatic operation on integer data
#include<stdio.h>
int main() {
int a, b, sum, sub, multi, div, mod;
printf("Enter 1st number : ");
scanf("%d", &a);
printf("Enter 2nd number : ");
scanf("%d", &b);
sum = a + b;
sub = a - b;
multi = a * b;
div = a / b;
mod = a % b;
printf("\nSum = %d", sum);
printf("\nSubtraction = %d", sub);
printf("\nMultiplication = %d", multi);
printf("\nDivision = %d", div);
printf("\nModulas = %d", div);
return 0;
}
APC-SPS-002.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to swap two integers. Display both numbers
before and after swap */
#include<stdio.h>
int main() {
int a = 10, b = 20, temp;
printf("Before swap A : %d, B : %d", a, b);
temp = a;
a = b;
b = temp;
printf("\nAfter swap A : %d, B : %d", a, b);
return 0;
}
APC-SPS-003.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Bitwise AND '&' */
#include<stdio.h>
int main() {
unsigned int a = 4, b = 5, c = 6;
unsigned int x, y;
x = a & b;
y = b & c;
printf("x = %u y = %u", x, y);
return 0;
}
APC-SPS-004.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
#include<stdio.h>
int main() {
int x = 25, y = 19, z;
z = x - y;
z = z & x ;
printf("Z = %d", z);
return 0;
}
APC-SPS-005.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Bitwise OR '|' */
#include<stdio.h>
int main() {
int x = 12, y = 14, z = 10, res;
x++;
z++;
x = x + y + z;
res = x | y;
z = res | z;
printf("x = %d y = %d z = %d res = %d", x, y, z, res);
return 0;
}
APC-SPS-006.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Bitwise NOT '~' */
#include<stdio.h>
int main() {
int x = 12, y = 15, z = 21;
int res, res1, res2;
res = x > 10;
res1 = ~res;
res2 = ~x;
printf("REs = %d, Res1 = %d, Res2 = %d", res, res1, res2);
return 0;
}
APC-SPS-007.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to check a number is even or odd using bitwise operator */
#include<stdio.h>
int main() {
int x, res = 1;
printf("Enter a number : ");
scanf("%d", &x);
res = res & x;
if (res == 0) {
printf("\nInput %d is a even number.", x);
}
else {
printf("\nInput %d is a odd number.", x);
}
return 0;
}
APC-SPS-008.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to calculate area of circle by accepting radius as input */
/* Author : Amit Dutta, Date : 15th September, 2025 */
#include<stdio.h>
#include<math.h>
int main() {
double r, area;
printf("Enter the radius of circle : ");
scanf("%lf", &r);
area = M_PI * r * r;
printf("\nArea : %lf", area);
return 0;
}
P001.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
//sample code
#include<stdio.h>
int main() {
printf("Hello world");
return 0;
}
P002.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
//sample code with a new line charecter
#include<stdio.h>
int main() {
printf("Hello\nworld");
return 0;
}
P003.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
//WAP to perform addtion and multiplication of two integer numbers
#include<stdio.h>
int main() {
int a, b, sum, multi;
printf("Enter the 1st number : ");
scanf("%d",&a);
printf("Enter the 2nd number : ");
scanf("%d",&b);
sum = a + b;
multi = a * b;
printf("\nSum = %d"
"\nMultiplication = %d",sum,multi);
return 0;
}
P004.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to find and display the value of given expression :
((x+3)/4) - ((2x+4)/3) taking the value of x = 5 */
#include<stdio.h>
int main() {
double x =5, result;
result = ((x + 3) / 4) - ((2 * x + 4) / 3);
printf("Result = %lf",result);
return 0;
}
P005.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* A person is paid Rs. 455 for each day he works and fined
Rs. 150 for each day he remains absent. WAP to calculate his
monthly income taking the number of days present as input. */
#include<stdio.h>
int main() {
int daily_wage = 455, fine = 150, present, absent, income;
printf("No of days present : ");
scanf("%d", &present);
absent = 30 - present;
income = (present * 455) - (absent * 150);
printf("\nIncome : %d",income);
return 0;
}
P006.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* The normal temperature of human body
is 98.6 Degree Fahrenheit. WAP to convert the temperature
to Degree Celcius and display the output. */
#include<stdio.h>
int main() {
double f = 98.6, c;
c = ((f - 32) * 5) / 9;
printf("Temperature in Celcius is : %lf",c);
return 0;
}
P007.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* A shopkeeper offers 10% discount on printed
price of a digital camera. However a customer has
to pay 6% GST on the remaining amount. WAP to
calculate and display the amount to paid by the
customer, taking the printed price as input. */
#include<stdio.h>
int main() {
double mrp, final_price, temp;
printf("Enter the printed price : ");
scanf("%lf", &mrp);
temp = mrp * 0.90;
final_price = temp * 1.06;
printf("\nCustomer have to pay : %lf", final_price);
return 0;
}
P008.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* A shopkeeper offers 30% discount on purchasing an
item whereas the other shopkeeper offers 2 successive
discount of 20% and 10% for purchasing the same item.
WAP to caompute and display the discounted price of the
item by taking the price as input. */
#include<stdio.h>
int main() {
double mrp, shop1, shop2, temp;
printf("Enter the price : ");
scanf("%lf", &mrp);
shop1 = mrp * 0.70;
temp = mrp * 0.80;
shop2 = temp * 0.90;
printf("\nShopkeeper 1 price : %lf"
"\nShopkeeper 2 price : %lf",shop1,shop2);
return 0;
}
P009.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to calculate gross and net salary
by accepting basic salary as input.
IMP : DA = 30% of Basic Pay
HRA = 20% of Basic Pay
PF = 12.5% of Basic Pay
Gross Salary = Basic Pay + DA + HRA
Net Salary = Gross Salary - PF
*/
#include<stdio.h>
int main() {
double bs, da, hra, pf, gs, ns;
printf("Enter the Basic Salary : ");
scanf("%lf", &bs);
da = bs * 0.3;
hra = bs * 0.2;
pf = bs * 0.125;
gs = bs + da + hra;
ns = gs - pf;
printf("\nGross Salary : %lf"
"\nNet Salary : %lf", gs, ns);
return 0;
}
P010.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to find and display the difference
between compound Interest and Simple Interest.
Take principle amount as input.
Hint : si = (p * r * t) / 100
a = p * ((1 + (r / 100)) ^ t)
ci = a - p
*/
#include<stdio.h>
#include<math.h>
int main() {
double p, r, t, si, a, ci, dif;
printf("Enter the principle amount, rate of interest, time in year : ");
scanf("%lf %lf %lf", &p, &r, &t);
si = (p * r * t) / 100;
a = p * pow((1 + (r / 100)), t);
ci = a - p;
dif = ci - si;
printf("\nSimple Interest : %lf"
"\nCompound Interest : %lf"
"\nInterest Difference : %lf", si, ci, dif);
return 0;
}
P011.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* The time period of a simple pendulam is
given by the formula :
t = 2 * pi * square_root(l / g)
WAP to calculate T take length(L) and gravity
as input
*/
#include<stdio.h>
#include<math.h>
int main() {
double l, g, t;
printf("Enter the Length and Gravity measures : ");
scanf("%lf %lf", &l, &g);
t = 2 * M_PI * sqrt(l / g);
// using M_PI variable for PI value from math.h header file
printf("\nTime Period : %lf", t);
return 0;
}
P012.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to swap two integer variable without
using third variable */
// using Approch Mode : simple, slow, time consuming
#include<stdio.h>
int main() {
int a = 4, b = 6;
printf("Before Swap : A = %d, B = %d", a, b);
a = a + b;
b = a - b;
a = a - b;
printf("\nAfter Swap : A = %d, B = %d", a, b);
return 0;
}
P013.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to swap two integer variable without
using third variable */
// using Approch Mode : complex, fast, less time consumimg
#include<stdio.h>
#include<math.h>
int main() {
int a = 4, b = 6;
printf("Before Swap : A = %d, B = %d", a, b);
a = a ^ b;
b = a ^ b;
a = a ^ b;
printf("\nAfter Swap : A = %d, B = %d", a, b);
return 0;
}
P014.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to accept the diagonal of
square. Find and display the area and
perimeter of the square. */
#include<stdio.h>
#include<math.h>
int main() {
double d, side, area, per;
printf("Enter the diagonal : ");
scanf("%lf", &d);
side = d / sqrt (2);
area = side * side;
per = 4 * side;
printf("\nArea of the Square : %lf"
"\nPerimeter of the Square : %lf", area, per);
return 0;
}
P015.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/*WAP to accept number of days and
display it after converting into
number of years, months and days */
#include<stdio.h>
int main() {
int day, month, year, temp;
printf("Enter the number of days : ");
scanf("%d", &day);
temp = day;
year = day / 365;
day = day % 365;
month = day / 30;
day = day % 30;
printf("\n%d Days = %d Years %d Months %d Days", temp, year, month, day);
return 0;
}
P016.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to calculate and display radius of a
circle by taking the area as input */
#include<stdio.h>
#include<math.h>
int main() {
double area, r;
printf("Enter the area of a circle : ");
scanf("%lf", &area);
r = sqrt((7 * area) / 22);
printf("\nRadius : %lf", r);
return 0;
}
P017.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Find maximum between three number. */
#include <stdio.h>
int main()
{
int a, b, c, max;
printf("Enter the value for a, b, c : ");
scanf("%d %d %d", &a, &b, &c);
max = a;
if (max < b)
max = b;
if (max < c)
max = c;
printf("Maximum : %d", max);
return 0;
}
P018.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to input the cost price and selling price and
calculate profit, profit percentage, loss percentage or
display the manage nither profit nor loss. */
#include <stdio.h>
int main()
{
double cost, sell, pro, prop, loss, lossp;
printf("Enter the cost and selling price : ");
scanf("%lf %lf", &cost, &sell);
if (sell > cost)
{
pro = sell - cost;
prop = (pro / cost) * 100;
printf("Profit : RS %g, Profit Percentage : %g", pro, prop);
}
else if (sell < cost)
{
loss = cost - sell;
lossp = (loss / cost) * 100;
printf("Loss : RS %g, Loss Percentage : %g", loss, lossp);
}
else
printf("Neither loss nor Profit.");
return 0;
}
P019.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to input the distance covered and calculate
the amount to be paid by the passanger.
Distance Rate
=<5KM RS 90
next 10KM RS 20/KM
next 10KM RS 10/KM
more than 25KM RS 9/KM
*/
#include <stdio.h>
int main()
{
double dis, amt;
printf("Enter the distance : ");
scanf("%lf", &dis);
if (dis <= 5.0)
amt = 90.0;
else if (dis > 5.0 && dis <= 15.0)
amt = 90.0 + (dis - 5.0) * 20;
else if (dis > 15.0 && dis <= 25.0)
amt = 90.0 + 200.0 + (dis - 15.0) * 10;
else if (dis > 25.0)
amt = 90.0 + 200.0 + 100.0 + (dis - 25.0) * 9;
printf("\nAmount to be paid : %g", amt);
return 0;
}
P020.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to calculate and display the maturity amount
taking the sum and number of days as input.
No. of Days Rate of Interest
Upto 180 days 5.5 %
181 to 364 days 7.5 %
exact 365 days 9.0 %
more than 365 days 8.5 %
*/
#include <stdio.h>
int main()
{
double nod, amt, s, i;
printf("Enter the amount and the time in days : ");
scanf("%lf %lf", &s, &nod);
if (nod <= 180)
i = (s * 5.5 * (nod / 365)) / 100;
else if (nod > 180.0 && nod <= 364.0)
i = (s * 7.5 * (nod / 365)) / 100;
else if (nod == 365.0)
i = (s * 9.0 * 1) / 100;
else if (nod > 365.0)
i = (s * 8.5 * (nod / 365)) / 100;
amt = s + i;
printf("Amount to be paid : %g", amt);
return 0;
}
P021.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to input a positive number and check if it is a perfect
square number or not. */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
#include <stdio.h>
#include <math.h>
int main()
{
int n, temp;
double sr;
printf("Enter the number : ");
scanf("%d", &n);
sr = sqrt(n);
temp = (int)sr;
if (temp * temp == n)
printf("\nThis is a perfect square.");
else
printf("\nThis is not a perfect square.");
return 0;
}
P022.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to find out smallest of three numbers without using if_else block. */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
#include <stdio.h>
int main()
{
int a, b, c, min;
printf("Enter three number : ");
scanf("%d %d %d", &a, &b, &c);
min = (a < b && a < c) ? a : (b < a && b < c) ? b
: c;
printf("Minimum = %d", min);
return 0;
}
P023.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to input the total cost and compute the amount to be paid
by the customer. */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
#include <stdio.h>
int main()
{
double cost, amt;
printf("Enter the total cost : ");
scanf("%lf", &cost);
if (cost <= 2000)
amt = cost * 0.94;
else if (cost > 2000 && cost <= 5000)
amt = cost * 0.9;
else if (cost > 5000 && cost <= 10000)
amt = cost * 0.85;
else if (cost > 10000)
amt = cost * 0.8;
printf("\nAmount to be paid : %g", amt);
return 0;
}
P024.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to check whether a year is leapyear or not. */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
#include <stdio.h>
int main()
{
int year;
printf("Enter the year : ");
scanf("%d", &year);
if (year % 4 == 0 && year % 100 != 0)
printf("\nYear %d is a leapyear.", year);
else if (year % 400 == 0)
printf("\nYear %d is a leapyear (Century).", year);
else
printf("\nYear %d is not a leapyear.", year);
return 0;
}
P025.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to input the electricity unit consumed and calculate the total
bill amount according to the given condition :
for 1st 50 unit Rs. 0.50 per unit
next 100 unit Rs. 0.75 per unit
next 100 unit Rs. 1.20 per unit
above 250 unit Rs. 1.50 per unit
And additional charge of 20 percent is added to the bill.
*/
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
#include <stdio.h>
int main()
{
double unit, amt;
printf("Enter the electricity consp(unit) : ");
scanf("%lf", &amt);
if (unit <= 50)
amt = unit * 0.50;
else if (unit > 50 && unit <= 50)
amt = 25 + ((unit - 50) * 0.75);
else if (unit > 150 && unit <= 250)
amt = 25 + 75 + ((unit - 150) * 1.20);
else if (unit > 250)
amt = 25 + 75 + 120 + ((unit - 250) * 1.50);
amt = amt * 1.20;
printf("\nAmount to be paid : %g", amt);
return 0;
}
P026.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to input sum (p), rate of interest (r), time (t) and type of interest
('s' for simple interest amd 'c' for compound interest). Calculate and display
the interest earned
si = (p * r * t) / 100
compoundInterest = p * ((1 + r / 100)^t - 1)
*/
#include <stdio.h>
#include <math.h>
#include <ctype.h>
int main()
{
double principalAmount, rateOfInterest, timePeriod, simpleInterest, compoundInterest;
char mode;
printf("Enter the principle amount, Rate of interest, Time : ");
scanf("%lf %lf %lf", &principalAmount, &rateOfInterest, &timePeriod);
printf("\nEnter the mode ('s' : simple interest, 'c' : compound interest) : ");
scanf(" %c", &mode);
mode = tolower(mode);
switch (mode)
{
case 's':
simpleInterest = (principalAmount * rateOfInterest * timePeriod) / 100;
printf("\nSimple Interest : %g", simpleInterest);
break;
case 'c':
compoundInterest = principalAmount * (pow((1 + rateOfInterest / 100), timePeriod) - 1);
printf("\nCompound Interest : %g", compoundInterest);
break;
default:
printf("\nInvalid Input");
return 1;
}
return 0;
}
P027.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Purchase Discount on Discount on
Amount Laptop Desktop
-------- ----------- -----------
Upto 20k 3.0% 5.0%
20001 - 50k 5.0% 7.5%
50001 - 75k 7.5% 10.5%
more than 75k 10.0% 15.0%
WAP to input amount of purchase and type of purchase ('L' : laptop, 'D' : desktop)
and display the discount amount and the discounted price (Net Amount).
*/
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
#include <stdio.h>
#include <ctype.h>
int main()
{
double principal_amount, desktop_discount, laptop_discount, discount_amount, discounted_price;
char choice;
printf("Enter the purchase amount : ");
scanf("%lf", &principal_amount);
printf("Type of purchase ('L' : Laptop, 'D' : Desktop) : ");
scanf(" %c", &choice);
choice = toupper(choice);
if (principal_amount <= 20000)
{
laptop_discount = 0.03;
desktop_discount = 0.05;
}
else if (principal_amount > 20000 && principal_amount <= 50000)
{
laptop_discount = 0.05;
desktop_discount = 0.075;
}
else if (principal_amount > 50000 && principal_amount <= 75000)
{
laptop_discount = 0.075;
desktop_discount = 0.105;
}
else if (principal_amount > 75000)
{
laptop_discount = 0.1;
desktop_discount = 0.15;
}
switch (choice)
{
case 'L':
discount_amount = principal_amount * laptop_discount;
discounted_price = principal_amount - discount_amount;
printf("\nDiscount Amount : %g"
"\nDiscounted Price : %g",
discount_amount, discounted_price);
break;
case 'D':
discount_amount = principal_amount * desktop_discount;
discounted_price = principal_amount - discount_amount;
printf("\nDiscount Amount : %g"
"\nDiscounted Price : %g",
discount_amount, discounted_price);
break;
default:
printf("\nInvalid Input.");
return 1;
}
return 0;
}
P028.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to calculate factorial of a number */
#include <stdio.h>
int main()
{
int i = 1, num, fact = 1;
printf("Enter the number : ");
if (scanf("%d", &num) != 1)
{
printf("\nPlease enter a number.");
return 1;
}
if (num == 0)
{
printf("\nFactorial of 0 : 1");
return 0;
}
if (num < 0)
{
printf("\nFactorial of %d : UNDEFINED", num);
return 0;
}
while (i <= num)
{
fact = fact * i;
i++;
}
printf("Factorial of %d : %d", num, fact);
return 0;
}
P029.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to perform addition of first n natural numbers. sum = 1 + 2 + 3 + ... */
#include <stdio.h>
int main()
{
int num, i = 0, result = 0;
printf("Enter the value for n : ");
if (scanf("%d", &num) != 1)
{
printf("\nPlease enter a number.");
return 1;
}
if (num < 1)
{
printf("\nPlease enter a positive number.");
return 1;
}
while (i <= num)
{
result = result + i;
i++;
}
printf("\nResult : %d", result);
return 0;
}
P030.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Display the first 15 terms of the series. */
#include <stdio.h>
#include <math.h>
int main()
{
int i, r;
// 3, 6, 9, 12, ...
{
i = 3, r = 0;
printf("Series 1 (3, 6, 9, 12, ...) :");
while (i <= 15)
{
r = r + 3;
printf(" %d", r);
i++;
}
}
// 1, 4, 9, 16, ...
{
i = 1;
printf("\nSeries 2 (1, 4, 9, 16, ...) :");
while (i <= 15)
{
printf(" %d", i * i);
i++;
}
}
// 4, 8, 16, 32, ...
{
i = 1, r = 2;
printf("\nSeries 3 (4, 8, 16, 32, ...) :");
while (i <= 15)
{
r = r * 2;
printf(" %d", r);
i++;
}
}
// 0, 7, 26, ...
{
i = 1, r;
printf("\nSeries 4 (0, 7, 26, ...) :");
while (i <= 15)
{
r = (int)pow(i, 3) - 1;
printf(" %d", r);
i++;
}
}
return 0;
}
P031.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Find the sum of the series */
#include <stdio.h>
#include <math.h>
int main()
{
double a, res, n;
int i;
// s = (a ^ 2) + (a ^ 2 / 2) + (a ^ 2 / 3) + ... + (a ^ 2 / 10)
{
res = 0, i = 1;
printf("--- s = (a ^ 2) + (a ^ 2 / 2) + (a ^ 2 / 3) + ... + (a ^ 2 / 10) ---");
printf("\nEnter the number : ");
scanf("%lf", &a);
while (i <= 10)
{
res = res + ((a * a) / i);
i++;
}
printf("S = %g", res);
}
// s = 1 + (2 ^ 2 / a) + (3 ^ 3 / a ^ 2) + ... + n
{
res = 0, i = 0;
printf("\n--- // s = 1 + (2 ^ 2 / a) + (3 ^ 3 / a ^ 2) + ... + n ---");
printf("\nEnter the value for a and n : ");
scanf(" %lf %lf", &a, &n);
while (i <= n - 1)
{
res = res + (pow(i + 1, i + 1) / pow(a, i));
i++;
}
printf("S = %g", res);
}
return 0;
}
P032.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to input a number and check whether it is a Niven number
or not. (When a number is divisible by its sum of digit) e.g. : n = 126*/
#include <stdio.h>
int main()
{
int n, temp, sod = 0;
printf("Enter the number : ");
scanf("%d", &n);
temp = n;
while (temp > 0)
{
sod = sod + (temp % 10);
temp = temp / 10;
}
if (n % sod == 0)
printf("\nIt is Niven number.");
else
printf("\nIt is not a Niven number.");
return 0;
}
P033.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to calculate the sum of even digits and odd digits. Number will be provided by user. */
#include <stdio.h>
int main()
{
int inp, odd = 0, even = 0, temp;
printf("Enter the number : ");
scanf("%d", &inp);
temp = inp;
while (temp > 0)
{
if ((temp % 10) % 2 == 0)
even += temp % 10;
else
odd += temp % 10;
temp /= 10;
}
printf("\nSum of even : %d"
"\nSum of odd : %d",
even, odd);
return 0;
}
P034.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Get sum of even position digit and odd position digit */
/* Counting starts from the rightmost digit as position 1 (Odd). */
#include <stdio.h>
int main()
{
int inp, temp, index = 1, even = 0, odd = 0;
printf("Enter the numebr : ");
scanf("%d", &inp);
temp = inp;
while (temp > 0)
{
if (index % 2 == 0)
even += temp % 10;
else
odd += temp % 10;
temp /= 10;
index++;
}
printf("\nSum of even position digits : %d"
"\nSum of odd position digits : %d",
even, odd);
return 0;
}
P035.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to input an int number and display the product of the successors
of even digits of the number entered by user. */
#include <stdio.h>
#include <stdbool.h>
int main()
{
int n, res = 1, temp;
bool status = false;
printf("Enter the number : ");
scanf("%d", &n);
temp = n;
while (temp > 0)
{
if ((temp % 10) % 2 == 0)
{
res *= (temp % 10) + 1;
status = true;
}
temp /= 10;
}
if (!status)
printf("\nThere is no even digits.");
else
printf("\nThe product of the successors of even digits of the number %d is : %d", n, res);
return 0;
}
P036.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* sum = a + (a^2)/2 + (a^3)/3 + ... + (a^n)/n */
#include <stdio.h>
#include <math.h>
int main()
{
double a, sum = 0;
int n, i;
printf("Enter value for a and n : ");
scanf("%lf %d", &a, &n);
for (i = 1; i <= n; i++)
sum += pow(a, i) / i;
printf("\nSum = %g", sum);
return 0;
}
P037.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* sum = 1 + 1+2/1*2 + 1+2+3/1*2*3 + ... + 1+2+3+...+n/1*2*3*...*n */
#include <stdio.h>
int main()
{
double sum = 0, temp1 = 0, temp2 = 1;
int n, i;
printf("Enter value for n : ");
scanf("%d", &n);
for (i = 1; i <= n; i++)
{
temp1 += i;
temp2 *= i;
sum += temp1 / temp2;
}
printf("\nSum = %g", sum);
return 0;
}
P038.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to check prime number */
#include <stdio.h>
#include <math.h>
#include <stdbool.h>
int main()
{
int num, i, endCheckDigit;
bool isPrime = true;
printf("Enter the number : ");
if (scanf("%d", &num) != 1)
{
printf("\nOnly a number is allowed, not a character.");
return 1;
}
if (num <= 0)
{
printf("\nOnly postive number is allowed.");
return 1;
}
if (num == 1)
{
printf("\nInput 1 is not a prime number."
"\nHas only one positive divisor (itself), not exactly two."
"\nRule: Prime number should have exactly two distinct positive divisors: 1 and itself");
return 0;
}
if (num == 2)
{
printf("\nInput 2 is a prime number."
"\n(Note: 2 is only Even Prime Number)");
return 0;
}
if (num % 2 == 0)
{
printf("\nInput %d is not a prime number.", num);
return 0;
}
endCheckDigit = sqrt(num);
for (i = 3; i <= endCheckDigit; i += 2)
{
if (num % i == 0)
{
isPrime = false;
printf("\nInput %d is not prime number.", num);
return 0;
}
}
if (isPrime)
{
printf("\nInput %d is a prime number.", num);
}
return 0;
}
P039.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to print all the factors of a postive integer */
#include <stdio.h>
int main()
{
int num, i;
printf("Enter a number : ");
scanf("%d", &num);
printf("\nFactors of %d : ", num);
for (i = 1; i <= num / 2; i++)
{
if (num % i == 0)
{
printf(" %d", i);
}
}
return 0;
}
P040.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to calculate HCF of two positive number */
#include <stdio.h>
int main()
{
int a, b, temp;
printf("Enter two number : ");
scanf("%d %d", &a, &b);
while (b > 0)
{
temp = a;
a = b;
b = temp % b;
}
printf("HCF = %d", a);
return 0;
}
P041.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to enter two numbers and check they are co-prime or not.
co-prime when HCF = 1
*/
#include <stdio.h>
int main()
{
int a, b, temp, temp_a, temp_b;
printf("Enter two number : ");
scanf("%d %d", &a, &b);
temp_a = a;
temp_b = b;
while (b > 0)
{
temp = a;
a = b;
b = temp % b;
}
if (a == 1)
{
printf("\n(%d, %d) is co-prime.", temp_a, temp_b);
}
else
{
printf("\n(%d, %d) is not co-prime.", temp_a, temp_b);
}
return 0;
}
P042.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to accept a number and check whether the number
is twisted prime or not. */
#include <stdio.h>
#include <math.h>
int main()
{
int n, t, i, r, rev, prime = 1;
printf("Enter the number : ");
scanf("%d", &n);
for (i = 2; i <= (int)sqrt(n); i++)
{
if (n % i == 0)
{
prime = 0;
break;
}
}
if (prime)
{
printf("%d is a prime number.", n);
t = n;
rev = 0;
prime = 1;
while (t > 0)
{
r = t % 10;
rev = rev * 10 + r;
t = t / 10;
}
for (i = 2; i <= (int)sqrt(rev); i++)
{
if (rev % i == 0)
{
prime = 0;
break;
}
}
if (prime)
{
printf("\n%d and %d are prime numbers.. TWISTED PRIME", n, rev);
}
else
{
printf("\n%d is non prime", rev);
}
}
else
{
printf("\n%d is non prime.", n);
}
return 0;
}
P043.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to check palindrome number. */
#include <stdio.h>
int main()
{
int num, temp, rev;
printf("Enter the number : ");
scanf("%d", &num);
temp = num;
rev = 0;
while (temp > 0)
{
rev = (rev * 10) + (temp % 10);
temp /= 10;
}
if (num == rev)
{
printf("%d is a palindrome number.", num);
}
else
{
printf("%d is not a palindrome number.", num);
}
return 0;
}
P044.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to input a number and check whether the
number is Pronic number or not.
Pronic Number: The number which is the product of two numbers
which is the product of two consecutive integer.
Ex: 20 = 4 * 5
*/
// using boolean...
/*
#include <stdio.h>
#include <math.h>
#include <stdbool.h>
int main()
{
int num, iterationIndex;
bool isPronic = false;
printf("Enter the number : ");
if (scanf("%d", &num) != 1)
{
printf("\nYou have to enter a number, not an character or symbol.");
return 1;
}
if (num < 1)
{
printf("\nOnly postive number is allowed.");
return 1;
}
for (iterationIndex = 1; iterationIndex <= num / 2; iterationIndex++)
{
if (iterationIndex * (iterationIndex + 1) == num)
{
printf("\nInput %d is a Pronic Number.", num);
isPronic = true;
break;
}
}
if(!isPronic)
{
printf("\nInput %d is not a Pronic Number.", num);
}
return 0;
}
*/
// using direct return method (more efficient and generally preferred)...
#include <stdio.h>
#include <math.h>
int main()
{
int num, iterationIndex, iterationLimit;
printf("Enter the number : ");
if (scanf("%d", &num) != 1)
{
printf("\nYou have to enter a number, not an character or symbol.");
return 1;
}
if (num < 1)
{
printf("\nOnly postive number is allowed.");
return 1;
}
iterationLimit = (int)sqrt(num);
for (iterationIndex = 1; iterationIndex <= iterationLimit; iterationIndex++)
{
if (iterationIndex * (iterationIndex + 1) == num)
{
printf("\nInput %d is a Pronic Number.", num);
return 0;
}
}
printf("\nInput %d is not a Pronic Number.", num);
return 0;
}
P045.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Make this pattern for input n.
Pattern :
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
*/
#include <stdio.h>
int main()
{
int i, j, n;
printf("Enter n : ");
scanf("%d", &n);
for (i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
printf("%d\t", j);
}
printf("\n");
}
return 0;
}
P046.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Make this pattern for input n.
Pattern :
1
2 1
3 2 1
4 3 2 1
5 4 3 2 1
*/
#include <stdio.h>
int main()
{
int i, j, n;
printf("Enter n : ");
scanf("%d", &n);
for (i = 1; i <= n; i++)
{
for (j = i; j >= 1; j--)
{
printf("%d\t", j);
}
printf("\n");
}
return 0;
}
P047.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Make this pattern for input n.
Pattern :
5
5 4
5 4 3
5 4 3 2
5 4 3 2 1
*/
#include <stdio.h>
int main()
{
int i, j, n;
printf("Enter n : ");
scanf("%d", &n);
for (i = n; i >= 1; i--)
{
for (j = n; j >= i; j--)
{
printf("%d\t", j);
}
printf("\n");
}
return 0;
}
P048.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Make this pattern for input n no of row.
Pattern :
1
2 3
4 5 6
7 8 9 10
11 12 13 14 15
*/
#include <stdio.h>
int main()
{
int i, j, n, temp = 1;
printf("Enter row number : ");
scanf("%d", &n);
for (i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
printf("%d\t", temp);
temp++;
}
printf("\n");
}
return 0;
}
P049.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Make this pattern for input n no of row.
Pattern :
#
@ @
# # #
@ @ @ @
# # # # #
*/
#include <stdio.h>
int main()
{
int i, j, n;
char a = '#', b = '@';
printf("Enter row number : ");
scanf("%d", &n);
for (i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
if (i % 2 == 0)
printf("%c\t", b);
else
printf("%c\t", a);
}
printf("\n");
}
return 0;
}
P050-SHORT.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to input a number and check whether it is Disarium Number or not.
Note : A number is said to Disarium if sum of its digit powered by with their
respective position is equal to the original number. */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
#include <math.h>
int main()
{
int num;
printf("Enter the number : ");
scanf("%d", &num);
int position = printf("%d", num);
int temp = num;
int res = 0;
while (temp > 0)
{
res += (int)pow(temp % 10, position);
position--;
temp /= 10;
}
if (res == num)
printf(" is a Disarium Number.");
else
printf(" is Not a Disarium Number.");
return 0;
}
P050.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to input a number and check whether it is Disarium Number or not.
Note : A number is said to Disarium if sum of its digit powered by with their
respective position is equal to the original number. */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
#include <math.h>
int main()
{
int num, res = 0, temp, position = 0;
printf("Enter the number : ");
scanf("%d", &num);
temp = num;
while (temp > 0)
{
position++;
temp /= 10;
}
temp = num;
while (temp > 0)
{
res += (int)pow(temp % 10, position);
position--;
temp /= 10;
}
if (res == num)
printf("\nInput %d is a Disarium Number.", num);
else
printf("\nInput %d is Not a Disarium Number.", num);
return 0;
}
P051.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to input two number and check whether they are Amicable Pair or not
Example : Sum of Proper Divisors of 220 (1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110) = 284
Sum of Proper Divisors of 284 (1, 2, 4, 71, 142) = 220 */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
int a, b, i, sa = 0, sb = 0;
printf("Enter two number : ");
scanf("%d %d", &a, &b);
for (i = 1; i <= a / 2; i++)
if (a % i == 0)
sa += i;
for (i = 1; i <= b / 2; i++)
if (b % i == 0)
sb += i;
if (sa == b && sb == a)
printf("\nInput %d and %d is Amicable Pair.", a, b);
else
printf("\nInput %d and %d is Not Amicable Pair.", a, b);
return 0;
}
P052.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Print the sum of this series for upto n element.
Series: 1 + (1 + 2) + (1 + 2 + 3) + (1 + 2 + 3 + 4) + ... + (1 + 2 + 3 + ... + n) */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
int n, sum = 0, temp = 0, i;
printf("Enter the n : ");
scanf("%d", &n);
for (i = 1; i <= n; i++)
{
temp += i;
sum += temp;
}
printf("%d", sum);
return 0;
}
P053.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Print all pattern */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int main()
{
int i, j, temp;
printf("\n\nPattern 1 : \n\n");
/*
9 9 9 9 9
7 7 7 7 7
5 5 5 5 5
3 3 3 3 3
1 1 1 1 1
*/
temp = 9;
for (i = 1; i <= 5; i++)
{
for (j = 1; j <= 5; j++)
{
printf("%d ", temp);
}
printf("\n");
temp -= 2;
}
// Another method print above pattern
printf("\n\nPattern 1 : \n\n");
for (i = 9; i >= 1; i -= 2)
{
for (j = 1; j <= 5; j++)
{
printf("%d ", i);
}
printf("\n");
}
printf("\n\nPattern 2 : \n\n");
/*
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
*/
for (i = 1; i <= 3; i++)
{
for (j = 1; j <= 5; j++)
{
printf("%d ", j);
}
printf("\n");
}
printf("\n\nPattern 3 : \n\n");
/*
5 4 3 2 1
5 4 3 2 1
*/
for (i = 1; i <= 2; i++)
{
for (j = 5; j >= 1; j--)
{
printf("%d ", j);
}
printf("\n");
}
printf("\n\nPattern 4 : \n\n");
/*
1 2 3 4
5 6 7 8
9 10 11 12
*/
temp = 1;
for (i = 1; i <= 3; i++)
{
for (j = 1; j <= 4; j++)
{
printf("%d ", temp);
temp++;
}
printf("\n");
}
printf("\n\nPattern 5 : \n\n");
/*
1 2 3 4
4 8 12 16
1 2 3 4
4 8 12 16
1 2 3 4
*/
for (i = 1; i <= 5; i++)
{
for (j = 1; j <= 4; j++)
{
if (i % 2 == 0)
printf("%d ", j * 4);
else
printf("%d ", j);
}
printf("\n");
}
printf("\n\nPattern 6 : \n\n");
/*
1
2 4
3 5 7
6 8 10 12
9 11 13 15 17
*/
int odd = 1, even = 2;
for (i = 1; i <= 5; i++)
{
for (j = 1; j <= i; j++)
{
if (i % 2 == 0)
{
printf("%d ", even);
even += 2;
}
else
{
printf("%d ", odd);
odd += 2;
}
}
printf("\n");
}
printf("\n\nPattern 7 : \n\n");
/*
1 2 3 4 5
6 7 8 9
10 11 12
13 14
15
*/
temp = 1;
for (i = 5; i >= 1; i--)
{
for (j = 1; j <= i; j++)
{
printf("%d ", temp);
temp++;
}
printf("\n");
}
return 0;
}
P054.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* WAP to check Krishnamurty number using user defined methods/functions. */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int fact(int);
int isKrishnamurty(int);
int fact(int n)
{
int fact = 1, i;
for (i = 1; i <= n; i++)
fact *= i;
return fact;
}
int isKrishnamurty(int n)
{
int temp = n, sum = 0;
while (temp > 0)
{
sum += fact(temp % 10);
temp /= 10;
}
return n == sum;
}
int main()
{
int n;
printf("Enter the number : ");
scanf("%d", &n);
if (isKrishnamurty(n))
printf("\nInput %d is a Krishnamurty Number.", n);
else
printf("\nInput %d is not a Krishnamurty number.", n);
return 0;
}
P055.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to print n terms of Fibbonacci Series (Starting from term 0) */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
void printFibonacci(int);
void printFibonacci(int n)
{
int val1 = 0, val2 = 1, val3, i;
printf("\nFibonacci series upto %d terms :", n);
if (n < 0)
printf(" N/A");
if (n == 0)
printf(" %d", val1);
if (n > 0)
printf(" %d %d", val1, val2);
for (i = 2; i <= n; i++)
{
val3 = val1 + val2;
printf(" %d", val3);
val1 = val2;
val2 = val3;
}
}
int main()
{
int n;
printf("Enter the n : ");
scanf("%d", &n);
printFibonacci(n);
return 0;
}
P056.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to swap the value of a and b using user defined method. */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
void swap(int *a, int *b)
{
int temp = *a;
*a = *b;
*b = temp;
}
int main()
{
int a, b;
printf("Enter A and B: ");
scanf("%d %d", &a, &b);
printf("\nBefore swap A: %d, B: %d", a, b);
swap(&a, &b);
printf("\nAfter swap A: %d, B: %d", a, b);
return 0;
}
P057.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to display the series using user defined method.
0, 7, 26, 63, ... upto n terms using void series(int n)
*/
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
void series(int n)
{
int i;
printf("\nSeries: ");
for (i = 1; i <= n; i++)
printf("%d ", (i * i * i) - 1);
}
int main()
{
int n;
printf("Enter n: ");
scanf("%d", &n);
series(n);
return 0;
}
P058.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to display ASCII code of Alphabets (A - Z) using void displayASCII() */
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
void displayASCII()
{
int i;
printf("ASCII Code\t\tCharacter");
for (i = 'A'; i <= 'Z'; i++)
printf("\n%c\t\t%d", i, i);
}
int main()
{
displayASCII();
return 0;
}
P059.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 12 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to find the sum of array elements using following fuctions
int array_sum(int a[], int n);
void get_data(int a[], int n);
void dispaly(int a[], int n);
*/
// This code has not been compiled.
// If you find any issues, please create a new issue on GitHub regarding them.
// Go to this link to create a new issue: https://github.com/notamitgamer/bsc/issues
#include <stdio.h>
int array_sum(int[], int);
void get_data(int[], int);
void display(int[], int);
int main()
{
int size, arr[20];
printf("How many element do you want to add (Max: 20): ");
scanf("%d", &size);
if (size < 1 && size > 20)
{
printf("\nMax Element count is 20.");
return 1;
}
get_data(arr, size);
display(arr, size);
printf("\nSum of the elements is: %d", array_sum(arr, size));
return 0;
}
void get_data(int a[], int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("Enter element for position %d: ", i);
scanf("%d", &a[i]);
}
}
void display(int a[], int n)
{
int i;
printf("\nArray: [");
for (i = 0; i < n; i++)
{
printf("%d", a[i]);
if (i != n - 1)
printf(", ");
}
printf("]\n");
}
int array_sum(int a[], int n)
{
int i, sum = 0;
for (i = 0; i < n; i++)
sum += a[i];
return sum;
}
P060.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 13 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* write a C program to count the occurrences of a given element in an array using a user-defined
function. Create a function int count_occurrences(int arr[], int n, int target) that countts how
many times target appears in the array. */
#include <stdio.h>
int count_occurrences(int[], int, int);
void inputarr(int[], int);
int main()
{
int n, arr[20], target, found;
printf("Enter the n (Max: 20): ");
scanf("%d", &n);
inputarr(arr, n);
printf("Enter the target: ");
scanf("%d", &target);
found = count_occurrences(arr, n, target);
if (found)
{
printf("\n%d found %d times.", target, found);
}
else
{
printf("\n%d is not found.", target);
}
return 0;
}
void inputarr(int arr[], int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
int count_occurrences(int arr[], int n, int target)
{
int count = 0;
int i;
for (i = 0; i < n; i++)
{
if (arr[i] == target)
{
count++;
}
}
return count;
}
P061.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 14 Dec 2025
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a C program to find the sum of even elements in an array using a user defined function.
Define a functions int sumEven(int arr[], int n) that returns the sum of all even elements in the array. */
#include <stdio.h>
void inputarr(int[], int);
int sumEven(int[], int);
int main()
{
int arr[20], n;
printf("Enter the n (Max: 20): ");
scanf("%d", &n);
inputarr(arr, n);
printf("\nSum of the even number in the array: %d", sumEven(arr, n));
return 0;
}
void inputarr(int arr[], int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("Enter element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
int sumEven(int arr[], int n)
{
int i, sum_even = 0;
for (i = 0; i < n; i++)
{
if (arr[i] % 2 == 0)
{
sum_even += arr[i];
}
}
return sum_even;
}
P062.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 16 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program to find the smallest and largest in an array using user-defined functions.
Define two functions int findSmallest(int arr[], int n) and int findLargest(int arr[], int n) that
return the smallest and largest elements in an array, respectively. */
#include <stdio.h>
#include <stdlib.h>
void inputarr(int[], int);
int findSmallest(int[], int);
int findLargest(int[], int);
int main()
{
int n, *arr;
printf("How many element do you want to enter: ");
scanf("%d", &n);
arr = (int *)malloc(n * sizeof(int));
inputarr(arr, n);
printf("\nSmallest element = %d", findSmallest(arr, n));
printf("\nLargest element = %d", findLargest(arr, n));
free(arr);
return 0;
}
void inputarr(int arr[], int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("Enter Element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
int findSmallest(int arr[], int n)
{
int i, smallest = arr[0];
for (i = 1; i < n; i++)
{
if (smallest > arr[i])
{
smallest = arr[i];
}
}
return smallest;
}
int findLargest(int arr[], int n)
{
int i, largest = arr[0];
for (i = 1; i < n; i++)
{
if (largest < arr[i])
{
largest = arr[i];
}
}
return largest;
}
P063.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 16 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a C program to find all Niven in an array. Define a user-defined function int isNiven(int num)
that returns 1 if the numbers is a Niven number, otherwise returns 0. A Niven number (also known as a
Harshad Number) is an integer that is divisible by the sum of its digits. */
#include <stdio.h>
#include <stdlib.h>
void inputarr(int[], int);
int isNiven(int);
int main()
{
int n, *arr, i;
printf("How many element do you want to enter: ");
scanf("%d", &n);
arr = (int *)malloc(n * sizeof(int));
inputarr(arr, n);
for (i = 0; i < n; i++)
{
if (isNiven(arr[i]))
{
printf("\n%d is a Niven number.", arr[i]);
}
else
{
printf("\n%d is a NOT Niven number.", arr[i]);
}
}
free(arr);
return 0;
}
void inputarr(int arr[], int n)
{
int i;
for (i = 0; i < n; i++)
{
printf("Enter Element %d: ", i + 1);
scanf("%d", &arr[i]);
}
}
int isNiven(int num)
{
int i, sum = 0, temp = num;
while (temp > 0)
{
sum += temp % 10;
temp /= 10;
}
return num % sum == 0;
}
P064.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 21 Dec 2025
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to merge two sorted integer arrays to form a single sorted array. */
#include <stdio.h>
#include <stdlib.h>
void merge(int[], int, int[], int);
int main()
{
int a[] = {10, 30, 50, 70, 90};
int b[] = {20, 40, 60, 80, 100};
int n1 = sizeof(a) / sizeof(a[0]);
int n2 = sizeof(b) / sizeof(b[0]);
merge(a, n1, b, n2);
return 0;
}
void merge(int a[], int n1, int b[], int n2)
{
int n = n1 + n2;
int *c = (int *)malloc(n * sizeof(int));
int i, j, k;
i = j = k = 0;
while (i < n1 && j < n2)
{
if (a[i] < b[j])
{
c[k++] = a[i++];
}
else
{
c[k++] = b[j++];
}
}
while (i < n1)
{
c[k++] = a[i++];
}
while (j < n2)
{
c[k++] = b[j++];
}
printf("Merged Array:");
for (i = 0; i < n; i++)
{
printf(" %d", c[i]);
}
free(c);
}
P065.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 12 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program to reverse a string */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void str_rev(char[]);
int main()
{
char str[101];
printf("Enter the string (Max: 100 Character): ");
gets(str);
printf("\nBefore Reverse: %s", str);
str_rev(str);
printf("\nAfter Reverse: %s", str);
return 0;
}
void str_rev(char str[])
{
int i, j;
char temp;
i = 0;
j = strlen(str) - 1; // not taking the null
while (i < j)
{
temp = str[i];
str[i] = str[j];
str[j] = temp;
i++;
j--;
}
}
P066.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 14 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* WAP to find the length of a string using
i) Library Method
ii) User defined method
*/
#include <stdio.h>
#include <string.h>
int sLength(char str[])
{
int i = 0;
while (str[i] != '\0')
{
i++;
}
return i;
}
int main()
{
char str[30];
int len;
printf("Enter the string: ");
gets(str);
len = strlen(str);
printf("Length of the string: %d", len);
printf("\nLength of the string (U-D): %d", len);
return 0;
}
P067.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 14 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a program using function which concatenates two string s1 and s2 in to a third string */
#include <stdio.h>
void string_concat(char *s3, char s1[], char s2[])
{
int l1, l2, i, j, k;
i = j = k = 0;
l1 = strlen(s1);
l2 = strlen(s2);
s3 = (char *)malloc((l1 + l2 + 1) * sizeof(char));
while (s1[i] != '\0')
{
s3[k++] = s1[i++];
}
while (s2[j] != '\0')
{
s3[k++] = s2[j++];
}
s3[k] = '\0';
puts(s3);
}
int main()
{
char s1[] = "JAVA";
char s2[] = "PYTHON";
char *s3 = NULL;
string_concat(s3, s1, s2);
return 0;
}
P068.c
/*
* Author: Amit Dutta (amitdutta4255@gmail.com) | Date: 14 Jan 2026
* Repo: https://github.com/notamitgamer/bsc
* License: MIT
*/
/* Write a c program that perform the operation of strcmp() */
#include <stdio.h>
#include <stdlib.h>
int string_compare1(char s1[], char s2[])
{
int i, c, cmp = 0, p = 0;
i = 0;
while (s1[i] != '\0' && s2[i] != '\0')
{
if (s1[i] != s2[i])
{
cmp = s1[i] - s2[i];
p = 1;
break;
}
i++;
}
c = s1[i] != '\0' ? s1[i] : (-1) * s2[i];
return p == 1 ? cmp : c;
}
int string_compare2(char *s1, char *s2)
{
while (*s1 != '\0' && (*s1 == *s2))
{
s1++;
s2++;
}
return *s1 - *s2;
}
int main()
{
char str1[] = "AMIT";
char str2[] = "Amit";
printf("Result 1 = %d", string_compare1(str1, str2));
printf("\nResult 2 = %d", string_compare2(str1, str2));
return 0;
}
P069.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 14 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program using user defined method to implement the following
JAVA PROG Mastery -> JPM
java prog mastery -> JPM
Acharya Prafulla Chandra -> JPM
*/
#include <stdio.h>
#include <ctype.h>
void _short_1(char str[])
{
int i = 0, j = 0;
char s[10];
if (str[0] != '\0' && str[0] != ' ')
{
s[j] = toupper(str[j]);
i++;
j++;
}
while (str[i] != '\0')
{
if (str[i] == ' ')
{
s[j] = toupper(str[i + 1]);
i++;
j++;
}
i++;
}
s[j] = '\0';
printf("\nResult 1: %s", s);
}
void _short_2(char str[])
{
int i, j;
char strnew[10];
strnew[0] = toupper(str[0]);
i = j = 1;
while (str[i] != '\0')
{
if (str[i] == ' ')
{
strnew[j++] = toupper(str[i + 1]);
}
i++;
}
strnew[j] = '\0';
printf("\nResult 2: %s", strnew);
}
int main()
{
char str[30];
printf("Enter the string: ");
gets(str);
_short_1(str);
_short_2(str);
return 0;
}
P070.c
/*
* Author : Amit Dutta <amitdutta4255@gmail.com>
* Date : 24 Jan 2026
* Repo : https://github.com/notamitgamer/bsc
* License : MIT License (See the LICENSE file for details)
*/
/* Write a program to perform addition of two complex number having fields 'real' and 'img'
of type integer. */
#include <stdio.h>
struct complex
{
int real;
int img;
};
void getData(struct complex *c)
{
printf("Enter real: ");
scanf("%d", &c->real);
printf("Enter imaginary: ");
scanf("%d", &c->img);
}
struct complex add(struct complex c1, struct complex c2)
{
struct complex r;
r.real = c1.real + c2.real;
r.img = c1.img + c2.img;
return r;
}
void display(struct complex c)
{
printf("%d+%di", c.real, c.img);
}
int main()
{
struct complex c1, c2, c3;
getData(&c1);
getData(&c2);
printf("\nComplex Number 1:\n");
display(c1);
printf("\nComplex Number 2:\n");
display(c2);
c3 = add(c1, c2);
printf("\nResult: \n");
display(c3);
return 0;
}